This is the 3rd time I am watching this excellent video by you. I am always amazed by the way you show with an example that how 1 can look into the dimensioning & tolerancing scheme, to check if we are allowing too much variation at assembly. Excellent & crisp explanation Kevin ji with an apt example. It is a thought process & not just simple drafting a 2D drawing.
You can try it too 😉 It's fun 😃😃 At least that one like attracted your attention and tag which the efforts of 4-6 days in making videos could not do. You know? We have to take care of all type of audiences. Tought job 🙄🙄
Yes, you are right. Max dimension of groove has to be more than 5.8 in order to fit the spacer. This will drive change in stack up chain dimension or tolerance so that it meets the requirements since current dimensioning chain is not meeting the requirement.
@@mechanicalvault Dont you think minimum dimension of groove should be higher than 5.8 in that case, all the spacer between 4.2 to 5.8 will fit in the groove?
@@mechanicalvault I believe if Min of groove is 5.8 then and then all the spacers will be fit in slot which means we need to correct the overall mean from 5 to 6 and if the parts are legacy then we need to tightned their overall toleraces from 0.6 to 0.1 then all the spacers will fit. Correct me if I am wrong.
I believe if Min of groove is 5.8 then and then all the spacers will be fit in slot which means we need to correct the overall mean from 5 to 6 and if the parts are legacy then we need to tightned their overall toleraces from 0.6 to 0.1 then all the spacers will fit. Correct me if I am wrong.
For 5.8 : 5.6 is interference fit For 4.4 : 4.2 is clearance. So spacer dimension must be based on which fit do you need to plan in both lower and upper case.. If we need correct dimension fit then spacer dimension tolerance need to modify i.e 5 +/- 0.6
In wrost case spacer may not able to fit because spacer max dimension is 5.8 and we have max clearance in bolt is 5.6 so in wrost case we can't fit the spacer or we have interference fit of 0.2 mm so for wrost case we need to modify the spacer dimension as our bolt is legacy
Can u please create a video on tolerance how to select a tolerance value for specific dimensions. Like 50 pus minus 0.03. How to select 0.03 value. Why u select this value. Please share with me.
Actually the spacer width can vary from 4.2 to 5.8, but the gap is varying from 4.4 to 5.6. So basically the gap is less than the spacer and we cannot fit the spacer in the groove. But in video you are telling we can fit it.
In my opinion, you have taken a very simple looking illustrative case which can be solved orally within half a minute. The mentioned tolerances on the three dimensions can be directly added to +/_ 0.6 Can you illustrate a little complex case where the individual tolerances are not equally disposed bi-lateral ones, but with a mixed variety of un-equally disposed bi-lateral tolerances, uni-lateral tolerances etc.
In the case of unequal bilateral or unilateral tolerances, you have to convert it into equal bilateral for the analysis and then remaining process remains exactly same as I explained in this video.
How did you get 5 as the mean of the sum of 45 and 40 mm? wouldn't the mean be 42.5 mm? isn't that just the difference between the sum of both positive and negative directions?
@@mechanicalvault It doesn't make sense (to me at least) to call it the mean when you didn't do (45 + (-40))/2, which is the mean equation for two values. What you did was 45 + (-40). Wouldn't that be the nominal size if it was a perfectly made part without tolerance and not the average size if it was a perfectly made part?
Looks like you need to sit with someone experienced and understand the concept of Stackup analysis. Here we are not talking about the dimension average, we are talking about the mean of the gap and then we apply tolerance value to get extreme limits.
@@mechanicalvault yes I do, that's why I searched videos on the topic. How do you think I ended up finding this video? I'm confused on why you're saying "mean". You say we're not finding the average dimension but the mean of the gap. But "mean" means average in math. www.mathsisfun.com/definitions/mean.html You're saying we're not finding the average but then you put "mean" in the video but you found the "mean" in the video by doing 45 + (-40) which isn't how you find the mean. Does "mean" just mean something else? And being a snarky asshole when I'm asking a question trying to understand the video isn't the way to go. Yes, I need more experience that's why I'm watching TH-cam vids on the topic. I wonder how having you as a professor is like -- students can't ask questions in class without being attacked. 👍.
@@helpmeimconfused that is correct, his explanation is wrong, mean is 42.5 and you calculate the sigma value of each dimension and then calculate the min/max overall dimension to fit the spacer
Hi sir, I have some query regarding tolerance stackup of my own parts in my firm. Can you help me regarding that. It will be very helpful for me and also we can show here for your subscriber
are you kidding? how come that spacer with worst condition of 5.8 will fit in worst condition of 4.4 mm gap? Your video was very good in explaining stackup but end screwed everything
Nice explanation of tolerance stack up analysis 👍👍🙂
Glad that you liked it!
Very good video about stack analysis 👌👏
This is the 3rd time I am watching this excellent video by you. I am always amazed by the way you show with an example that how 1 can look into the dimensioning & tolerancing scheme, to check if we are allowing too much variation at assembly. Excellent & crisp explanation Kevin ji with an apt example. It is a thought process & not just simple drafting a 2D drawing.
Glad that you liked it 🙏🙏
@@mechanicalvaulthow +-0.8 can fit in +-0.6mm
Very good information my friend
Thank you Leonel 🙏🙏
Watch video to understand what is stack up analysis and why stack up analysis is so crucial skill in mechanical design engineering.
Muchas gracias por esta magnífica información
U liked ur own comment 😏
@@yogabrindha5640 It is a great comment! And a great video!
@@hemantdaulta1 😁😁
You can try it too 😉 It's fun 😃😃
At least that one like attracted your attention and tag which the efforts of 4-6 days in making videos could not do.
You know? We have to take care of all type of audiences. Tought job 🙄🙄
Very useful and clear information thankyou
I have a doubt, if the spacer comes at USL i.e. 5.8 mm how will it fit in the groove of max dimn. 5.6 mm??
Yes, you are right.
Max dimension of groove has to be more than 5.8 in order to fit the spacer.
This will drive change in stack up chain dimension or tolerance so that it meets the requirements since current dimensioning chain is not meeting the requirement.
@@mechanicalvault Dont you think minimum dimension of groove should be higher than 5.8 in that case, all the spacer between 4.2 to 5.8 will fit in the groove?
@@mechanicalvault I believe if Min of groove is 5.8 then and then all the spacers will be fit in slot which means we need to correct the overall mean from 5 to 6 and if the parts are legacy then we need to tightned their overall toleraces from 0.6 to 0.1 then all the spacers will fit. Correct me if I am wrong.
@@Halchal_America yes we need to correct that to 5to6 without changing what he said was wrong in the video, make correction that is wrong
@@Halchal_America make the dimension to 45.2+/-0.2. it will fit for all cases!
Extraordinary teaching💎
Actually all the spacers of 4.2~5.8 will not fit in slot of dimension 4.4~5.6😀
I believe if Min of groove is 5.8 then and then all the spacers will be fit in slot which means we need to correct the overall mean from 5 to 6 and if the parts are legacy then we need to tightned their overall toleraces from 0.6 to 0.1 then all the spacers will fit. Correct me if I am wrong.
When the slot is at 5.8 won't fit in 5.6 gap
For 5.8 : 5.6 is interference fit
For 4.4 : 4.2 is clearance.
So spacer dimension must be based on which fit do you need to plan in both lower and upper case..
If we need correct dimension fit then spacer dimension tolerance need to modify i.e 5 +/- 0.6
In wrost case spacer may not able to fit because spacer max dimension is 5.8 and we have max clearance in bolt is 5.6 so in wrost case we can't fit the spacer or we have interference fit of 0.2 mm so for wrost case we need to modify the spacer dimension as our bolt is legacy
Very good video for Design Engineer. Thanks for sharing.
Thank you Pravin!
excellent video. thank you so much for making it easy to understand. I wish you would explain more about the chain. Thanks again
Sure, in the future!
Simple explanation. Thank you
Thank you!
That's really easy explanation of tolerance stack up analysis sir
Glad that you liked it.
Suppose if M or L modifier is given on feature dimension then do we need to calculate VC and RC for the same for stack up analysis?
Nice one. thanks
Great video with really nice examples! Thank you for the explanation sir!!!😃
Good explanation. You should have told why that 10+/-0.2 dimension is not considered
Can u please create a video on tolerance how to select a tolerance value for specific dimensions. Like 50 pus minus 0.03. How to select 0.03 value. Why u select this value. Please share with me.
Very good nice
Thank you Vijay 🙏🙏
Actually the spacer width can vary from 4.2 to 5.8, but the gap is varying from 4.4 to 5.6.
So basically the gap is less than the spacer and we cannot fit the spacer in the groove.
But in video you are telling we can fit it.
Excellent video
thanks for this video. Very helpful to understand tol stack up analysis.
Glad that you liked it 🙏🙏
Well done brother
Glad that you liked it.
Very nicely explained...with the right examples👍🏼 Thank you for the video.
Glad that you liked it
Very informative Sir, Please Take a example of Complex assembly
In my opinion, you have taken a very simple looking illustrative case which can be solved orally within half a minute. The mentioned tolerances on the three dimensions can be directly added to +/_ 0.6 Can you illustrate a little complex case where the individual tolerances are not equally disposed bi-lateral ones, but with a mixed variety of un-equally disposed bi-lateral tolerances, uni-lateral tolerances etc.
In the case of unequal bilateral or unilateral tolerances, you have to convert it into equal bilateral for the analysis and then remaining process remains exactly same as I explained in this video.
Thank you sir ❤
🙏🙏🙏
Please try to make series on this topics
Well explained
Thank you!
Hi Kavin, Please provide reference book for Tolerance stack up analysis
Could you please suggest best book for tolerance stack up analysis to understand in depth.
Hello sir,
Can u make a video on functional dimensioning
Please.
Dear Sir,
Nice Video,
Please provide training content if possible
Sir, Videos are amazing, please provide a sequential list of ur videos, so that it will be easy to follow.
How many types of stack up method r used industries
Make vdo on radial stackup
👌👌
Hello sir, can you teach us how to apply GD&T on drawing?
👍👍 yes, soon
Any, full time course available on GD&T and tolerance stack up analysis? ,I should know it
We have online courses. Contact me to kevinkutto@gmail.com after 15th of May for course demo.
min dimension of grove is 4.4, while USL for spacer is 5.8. How can you say you can put the spacer into the grove ?
Sir plzz make series on GD&T
I have already made some videos on GD&T, hopefully you watched them.
@@mechanicalvault yes sir, but would be better if we learn whole gd&t from you
if u got a spacer of 5.8 mm and a groove of 4.4 mm i.e the worst case of it , how can it fit there then??
The example shown at 2:07 not used in 13:38
Sir,
Can you share this presentation
How did you get 5 as the mean of the sum of 45 and 40 mm? wouldn't the mean be 42.5 mm? isn't that just the difference between the sum of both positive and negative directions?
This mean is the mean of the clearance between positive and negative values because we are interested into the clearance and it's variation.
@@mechanicalvault It doesn't make sense (to me at least) to call it the mean when you didn't do (45 + (-40))/2, which is the mean equation for two values. What you did was 45 + (-40). Wouldn't that be the nominal size if it was a perfectly made part without tolerance and not the average size if it was a perfectly made part?
Looks like you need to sit with someone experienced and understand the concept of Stackup analysis.
Here we are not talking about the dimension average, we are talking about the mean of the gap and then we apply tolerance value to get extreme limits.
@@mechanicalvault yes I do, that's why I searched videos on the topic. How do you think I ended up finding this video?
I'm confused on why you're saying "mean". You say we're not finding the average dimension but the mean of the gap. But "mean" means average in math.
www.mathsisfun.com/definitions/mean.html
You're saying we're not finding the average but then you put "mean" in the video but you found the "mean" in the video by doing 45 + (-40) which isn't how you find the mean. Does "mean" just mean something else?
And being a snarky asshole when I'm asking a question trying to understand the video isn't the way to go. Yes, I need more experience that's why I'm watching TH-cam vids on the topic. I wonder how having you as a professor is like -- students can't ask questions in class without being attacked. 👍.
@@helpmeimconfused that is correct, his explanation is wrong, mean is 42.5 and you calculate the sigma value of each dimension and then calculate the min/max overall dimension to fit the spacer
what if the limits/tolerances given are unilateral?
Hi sir, I have some query regarding tolerance stackup of my own parts in my firm. Can you help me regarding that. It will be very helpful for me and also we can show here for your subscriber
sir, please show us practically using any object, than theory.
Sir please explain about product design and design and development process involved
Yes, sure!
@@mechanicalvault I'm waiting for that 😊
are you kidding? how come that spacer with worst condition of 5.8 will fit in worst condition of 4.4 mm gap? Your video was very good in explaining stackup but end screwed everything