What is the expression for Half-Life of a Second Order Reaction? Here, I derive it from the integrated rate law. The answer is t = 1/ (k [A]0) Ask me questions: www.chemistnate...
I don't know. [A]0 is the concentration starting at whatever time you want to calculate the half-life for. i.e. if you start with 1.0 mol/L and want the half-life from that point, you plug in [A]0 = 1.0 Later if you have 0.34 mol/L left, and you want the time it'll take to get to 0.17 mol/L, you can plug in 0.34 Long story short, [A]0 IS the molarity...
I have a confusion regarding this..will you please help me? How is it physically possible that if the initial concentration is low, half life is greater...!!!???
I don't know. [A]0 is the concentration starting at whatever time you want to calculate the half-life for.
i.e. if you start with 1.0 mol/L and want the half-life from that point, you plug in [A]0 = 1.0
Later if you have 0.34 mol/L left, and you want the time it'll take to get to 0.17 mol/L, you can plug in 0.34
Long story short, [A]0 IS the molarity...
happy valentine's day i love u
THANKS FOR THIS SHORT AND TO THE POINT VIDEO....
Short and simple great video man.
I have a confusion regarding this..will you please help me?
How is it physically possible that if the initial concentration is low, half life is greater...!!!???
AHHH my homework is due in like 2 hours T-T Wish me luckkk
I want Relation between A & b in case two of 2nd order reaction to find half life time becouse A not equal b
can you solve this pls.& thxxx.
So this can be used for any order! Cool and thanks
You are a life saver. :)
Refresh? It worked for me.
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Welp, I did that wrong on the test.
at least you tried bro
Thank you 😊
Thank you
Thanks🙏
got it !! thank you man
dude... Why can't I view it??? >.<
This video has 3 likes. Half-Life 3 confirmed.
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thanks
+2kt
Why are you writing on carpet my dude? Don't have a desk? Like if you agree.
Thank you