God i just love paying nearly a grand for a college chemistry course and learning nearly nothing but i hop onto youtube and learn more than i ever can from my professors damn slide shows.
I wonder though, if you knew you needed chemistry and felt you could learn it on your own in 10-15 weeks as in a class, why did you not just watch the online videos or read a chem book and then test out of it? There is more to paying for a class than a power point and lecture. The prof should have office hours, there are tutors available at most universities and community colleges, classmates with whom to work, email/school forums/phone numbers and a guided tour of the lessons. Not that it always justifies the prices, but you are paying for a lot more than just one person. :)
***** [Click to read more] +Solonneysa It is possible to take appropriate tests and earn the degrees from those tests. I did not have a official high school education transcript, but was able to get into LFCC (community college) by taking their placement tests. (I was homeschooled for 4.5 years since the 7th grade, and never went to high school) Surely you could do the same for higher levels to avoid having to pay $$$. However, 3 big problems arise: 1st, there is no curriculum for one to follow: this makes it especially hard to stay on track, and learn everything equally. Without guidance, it is easy to concentrate on the east parts, while floating through the harder parts. you really have to be responsible, and self-disciplining. You have to force yourself to learn things that are boring, and keep away from procrastination, since noone else has the power to do so. (In formal education, the grading and GPA keeps you pushing hard to do good, but that will no-longer exist in self-education) 2nd: As +Solonneysa has mentioned, collage can give you 1 on 1 attention and tutoring. It LFCC, they even have a free tutoring service (you, of course, have to be enrolled though!) Not to mention the community of students and the professor's office hours. And 3rd and most obvious: studies show that only ~40% of the information online is accurate. I do not know how this was determined, but that might mean a failing 40% on a placement test.
Order of reaction is the name of the calculation method. Adding the powers of the experimentally calculated rate of rxn. But the reason why it is calculated is to make it easier and kind of tabular. It helps understand the change in the rate of rxn due to change in concentration
chemistry is difficult because your examples look very simple but on the exams the questions and numbers are too complicated to comprehend, is it possible for you to use a bit more complex numbers?
+FTjack AoE7AoT yeah I need to know how to find the orders with complex numbers that you need to know how to us the natural log function (I think) in the algebra to find the final order. But i don't know how to use the natural log...
+FTjack AoE7AoT What level chemistry are you doing? I'm in university and find that the numbers used were very similar to the ones used in highschool, but certain concepts require knowledge of log laws and so knowing them may help you.
can you just be my professor? Lol you actually put things into terms that i can ACTUALLY understand and you don't go too quickly. This is perfect. I wish i can just ask you questions all the time haha. and just so you know I never comment on youtube videos. that is how much this helped me out
Thank you for not zip through this video. I understand what you were doing vs my teacher who just zips through the whole thing and everyone sits there blank
Thanks Ben,but I wish you could make a tutorial of how to get the order of a reaction from the given volumes of a product and the time taken for formation,cuz I really can't figure it out.
concentration is No. Of moles upon volume. Either no. Of moles will be given in the question or u can assume it as x. If percentage of reactant used is given for example.."70 percent reactant is used" Then initial moles will be 100 and final will be 30.(i.e. 100-70) So u have no. Of moles now..and...u have volume. So bingo now u can calculate concentration So use ur formula of zero first and second order. And place the values. Fr example zero order formula is [A]=[A°]- kt [A] is final concentration. (Moles/vol) [prev ex.: 30/V] [A°] is initial conc.[100/v] K= rxn const. (Given in question) t= time P.s. if moles is not given and molecular weight and mass of reactants is given. Use formula Moles= mass/ Molecular weight Have fun!
Is there a method to predict the products of a reaction??? Example: H2 + O2 ---> ??? We were given lots of questions like this, some way harder than this, and there is no way for us to memorize all of them. So is there a way to figure out if it is a single displacement? or a double displacement? or a decomposition? and so on. And is there a way to find out what is the product of the equation after we knew what reaction it is???
How is the rate equal to the square of the concentration in the second example?? if you square the concentrations you don't get the values in the right side of the table, I don't understand?
Wow, this is like the ONE good source of explinations anywhere. everything else is retardedly overcomplicated with 200 redundant things per sentence, you actually explain things well, its followable, and everything you say is practical. another article i found told me to get mols made per second per fucking cubic meter, why tf would i wanna do it in cubic meter what am i gonna do measure my flask?!
Thank you so much for your feedback! Feel free to check out my latest content. It's much faster-paced, however I don't have anything new on kinetics. It's on the way! Thanks again! -Ben
God loves you and he wants to save everyone, but in order for him to do that, you need to repent and be baptized. Also share his gospel with everyone you come in to contact with and keep his commandments 🙏🏾😘
Hey if you're looking for HW HELP ASAP, visit the thestudylobby. com Ask any question; we guarantee a response within 30 minutes!! Give us a try and a thumbs up if we were able to help you out :)
God i just love paying nearly a grand for a college chemistry course and learning nearly nothing but i hop onto youtube and learn more than i ever can from my professors damn slide shows.
I wonder though, if you knew you needed chemistry and felt you could learn it on your own in 10-15 weeks as in a class, why did you not just watch the online videos or read a chem book and then test out of it? There is more to paying for a class than a power point and lecture. The prof should have office hours, there are tutors available at most universities and community colleges, classmates with whom to work, email/school forums/phone numbers and a guided tour of the lessons. Not that it always justifies the prices, but you are paying for a lot more than just one person. :)
***** I did say "test out of it." In other words, test out of the class.
***** [Click to read more]
+Solonneysa
It is possible to take appropriate tests and earn the degrees from those tests. I did not have a official high school education transcript, but was able to get into LFCC (community college) by taking their placement tests. (I was homeschooled for 4.5 years since the 7th grade, and never went to high school) Surely you could do the same for higher levels to avoid having to pay $$$. However, 3 big problems arise:
1st, there is no curriculum for one to follow: this makes it especially hard to stay on track, and learn everything equally. Without guidance, it is easy to concentrate on the east parts, while floating through the harder parts. you really have to be responsible, and self-disciplining. You have to force yourself to learn things that are boring, and keep away from procrastination, since noone else has the power to do so. (In formal education, the grading and GPA keeps you pushing hard to do good, but that will no-longer exist in self-education)
2nd: As +Solonneysa has mentioned, collage can give you 1 on 1 attention and tutoring. It LFCC, they even have a free tutoring service (you, of course, have to be enrolled though!) Not to mention the community of students and the professor's office hours.
And 3rd and most obvious: studies show that only ~40% of the information online is accurate. I do not know how this was determined, but that might mean a failing 40% on a placement test.
u in keiser university? lol the shittest uni i could think off
College is a scam.
Thank you for leaving these videos/gems on TH-cam even when made in 2011. This is very helpful for chemistry students like me. Thank you!!
HOW THE HECK DID THIS GO OVER MY HEAD IN MY CHEM LEC? I HAVE NO IDEA!!! THANK YOU!!!!!
But I still fail to understand what makes them a first, second, or zero order.
Order of reaction is the name of the calculation method.
Adding the powers of the experimentally calculated rate of rxn.
But the reason why it is calculated is to make it easier and kind of tabular. It helps understand the change in the rate of rxn due to change in concentration
chemistry is difficult because your examples look very simple but on the exams the questions and numbers are too complicated to comprehend, is it possible for you to use a bit more complex numbers?
+FTjack AoE7AoT yeah I need to know how to find the orders with complex numbers that you need to know how to us the natural log function (I think) in the algebra to find the final order. But i don't know how to use the natural log...
+FTjack AoE7AoT What level chemistry are you doing? I'm in university and find that the numbers used were very similar to the ones used in highschool, but certain concepts require knowledge of log laws and so knowing them may help you.
yeah on our tests, our professor puts 1/[A] and ln [A] and makes us find the order of the reaction... im like... bruh....
This absolutely answered my question on how to determine which rate law to use. Thank you for explaining it so clearly.
Got a chem test tomorrow n was confused shirtless on rate order prior to this video. Thanks a lot man! Really helped!
thanks 1xmillion
this is gonna get me accepted in university
THANK YOU SO MUCH. I'm math stupid and the tutors at my college don't understand that you have to explain EVERYTHING to me.
Thank you so much! I was struggling to understand this in AP Chem now it totally makes sense. Thank you so much!!!
I love how you take your time to explain alot of teachers dont do that..... THANKS :)
can you just be my professor? Lol you actually put things into terms that i can ACTUALLY understand and you don't go too quickly. This is perfect. I wish i can just ask you questions all the time haha. and just so you know I never comment on youtube videos. that is how much this helped me out
You should try to speed up your tutorials. Anyway good job!
Better too slow than too fast!
Speed up the video speed to 1.5x if its too slow for you. Great video Ben! Thank you
Saurav Acharya That is exactly what I did.
you teach so much better than my professor... thank you very much ^^
Why didn't my chemistry professor just tell us this in class? Thanks, soo much help.
Bcz he expects u to be "smart"-
People are wild.
This was a brilliant video. Very well explained
Thank you for not zip through this video. I understand what you were doing vs my teacher who just zips through the whole thing and everyone sits there blank
beautiful mate,missed the class on this one but with your tutorial am pretty confident thanks
my lectures and textbooks makes this look so complicated, couldn't believe it was that simple!
Thank you loads :D Helped so much, so light and so complete ^_^
Oh man, i wish i can like this 10000 times!
why the freaking hell has someone disliked this video... MUST BE SOME JEALOUS PROFFERSOR WHO CANT TEACH AS GOOD AS HE DOES -.-
btw THANKS =)
excellent explanation..u r great!
Thank you so much for giving a great lecture! You saved me.
OMG THE BEST PERSON IN THE WORLD! I LOVE YOU. THANKS!
saved yet again, thank you so much
Thanks Ben,but I wish you could make a tutorial of how to get the order of a reaction from the given volumes of a product and the time taken for formation,cuz I really can't figure it out.
concentration is
No. Of moles upon volume.
Either no. Of moles will be given in the question or u can assume it as x.
If percentage of reactant used is given for example.."70 percent reactant is used"
Then initial moles will be 100 and final will be 30.(i.e. 100-70)
So u have no. Of moles now..and...u have volume.
So bingo now u can calculate concentration
So use ur formula of zero first and second order.
And place the values.
Fr example zero order formula is
[A]=[A°]- kt
[A] is final concentration. (Moles/vol) [prev ex.: 30/V]
[A°] is initial conc.[100/v]
K= rxn const. (Given in question)
t= time
P.s. if moles is not given and molecular weight and mass of reactants is given. Use formula
Moles= mass/ Molecular weight
Have fun!
errgerd chem exams tomorrow and this video really helped thanks
Thank you very much Ben ..this was VERY helpful :)
Is there a method to predict the products of a reaction???
Example: H2 + O2 ---> ???
We were given lots of questions like this, some way harder than this, and there is no way for us to memorize all of them. So is there a way to figure out if it is a single displacement? or a double displacement? or a decomposition? and so on. And is there a way to find out what is the product of the equation after we knew what reaction it is???
i tried for like 1000 times but never could get myself clear on this topic... Thankyou i finally did
Very cool! Thank you for sharing that 😲
Shouldn't [A] decrease over time since it's breaking down into products from a single reactant?
THIS WAS REALLY HELPFUL THANK YOU!!
Great video! You really showed me how to do this,!
I love you sir. You have saved me from getting a nasty grade. ;w; ♥
So how do we find k for the second order? I have an idea but seeing it in the video would've been nice.
To find k, just solve for it algebraically.
@@BensChemVideos I hate to say it, but I am not good at algebra. So, are you saying k=(3/2)/(9/4)?
How is the rate equal to the square of the concentration in the second example?? if you square the concentrations you don't get the values in the right side of the table, I don't understand?
awesome. cleared things up for me. thanks!
Was very helpful. thank you
what if there are 4 equations and [A] when x2 and x4 increase the rate to x2 and x4?Would that mean [A]^2?
Is this a college level chemistry in other countries?
so what if you're graph only has time and pressure?
Yeah, I kinda wish this video was a lot faster and quicker. It's good though. Thank you
Ah you are a life saver!!!!
Great video, thanks
Thnx a lot now i understand how to determine the order of reaction
Hello,
you were assuming elementary reactions for this purpose of this video?
I think I am in love... THANK YOU!! :')
youuuuuuuu r awesomeeeeeeeeeee....thaaaaaank alot
Could not thank you enough :")
Wow, this is like the ONE good source of explinations anywhere. everything else is retardedly overcomplicated with 200 redundant things per sentence, you actually explain things well, its followable, and everything you say is practical. another article i found told me to get mols made per second per fucking cubic meter, why tf would i wanna do it in cubic meter what am i gonna do measure my flask?!
Thank you Ben
thx, man :) helped a lot
you are the besttttttttttttt thank youuuuuuuuuuuuuuu
thank you sir 🙏🙏❤️❤️
But what about 3d order reaction?
Thank you sir.
Thank you soooo much!
I've totally understood
How to know that it has 3rd order...
your my hero...
wow,that was great, thanks :)
Thanks a lot !
Very Helpful. Good Job and keep up the good work! A tip for the future, try speed up the talking but anyways well done!
Thank you so much for your feedback!
Feel free to check out my latest content. It's much faster-paced, however I don't have anything new on kinetics. It's on the way!
Thanks again!
-Ben
Hey thanks alot Mr.ben's you did ah great job thanks for the break down of the order as well really really thankful @ Ben's Chem Videos
thank you thank you thank you
thanks so much!
really helped thanks
thank you!
IT'S ALL STARTING TO MAKE SENSE NOW WTF DID I LEARN AT UNI??
it helped me thanks
thank you
anyone pls explain how to find exponents
It's very uncommon for reactions to go over 2, more then likely you'll never get any reactions like that in your chemistry class.
You could make me love chemistry enen as much as girls. Well explained,
thank you so much
I bet that was my chemistry professor lmao
Thanks!
You're very welcome! Many thanks for watching and commenting 😀
coool man. keep goin,
thank you very much :)
amazing
Thank you so much omg
Thanks ben
Awesome
girls love chemistry!
you take the natural log of each side of the equation
life saver ;P!
it seems that TH-cam is my best prof :/
thank you
allah bless you
thx
Thats what she said!
Can you just be my tutor?!?!
I fucking love youtube thank you !!!!
God loves you and he wants to save everyone, but in order for him to do that, you need to repent and be baptized. Also share his gospel with everyone you come in to contact with and keep his commandments 🙏🏾😘
I love you.
cant not watch this at 2x speed
thanks but why u talk so slow..
YOU CAN SPEED IT UP
Hey if you're looking for HW HELP ASAP, visit the thestudylobby. com
Ask any question; we guarantee a response within 30 minutes!!
Give us a try and a thumbs up if we were able to help you out :)
You were you breathing so heavily...
Professor Xavier does not approve.