i'm blown away by how much more sense everything makes after one afternoon on youtube. thank you so much, when i kill my exam tomorrow i'll owe it all to you!
Was falling behind in my Mech. of Materials class. What are the odds that this would be up the same month? Thanks so much, you really saved me. Great explanations.
shouldn't the compressive force also include the force from the neutral axis down to the top of the base of the beam (30-20) that is on the vertical section?
structurefree wouldnt that volume on the vertical section have a force resultant that would add to the force resultant from the bottom part of the beam?
@@structurefree sir, he's got a point. Care to explain why the little strip of 10mm x 20mm vertical strip not i cluded in your compressive resultant force?
Should'nt the depth of the Flange be 3m . when u calculated Force resultant you took the area of flange as 29 mm x 60mm but the stress is acting sideways tht means that the area should be 20 mm x 3 m or 3000 mm . No ??
WarmSensations I think the reason it doesn't show up in some of the other sections, is because for a centroid located at a distance of 0 from neutral axis, (picture an I shape where centroid of bottom left is in line with the neutral axis). However, lets say the top rectangle of the I has a centroid an actual Y-distance from the N.A. Therefore only that one has a Ady^2 on it.
Hey man, just one question. Why is your compression in the stress profile (red) isn't flipped on the left side since it is negative? Great video nonetheless! Been helping me out quite a lot! Cheers!
structurefree Hahaha I figured it out just the moment I finish type the comment == Anyway thanks for your response you are much more better than my lecturer.I will like to watch all your video :)
8 years later and still extremely good! Absolutely sick!
i'm blown away by how much more sense everything makes after one afternoon on youtube. thank you so much, when i kill my exam tomorrow i'll owe it all to you!
time to ball, son.
hope you're a graduate now
Brilliant...simply brilliant..thanks a lot for all the videos you have blessed us with...one thanks is just not enough....
thank you for the kind words. thank you.
zero dislikes!! This says it all. thanks man
Was falling behind in my Mech. of Materials class. What are the odds that this would be up the same month? Thanks so much, you really saved me. Great explanations.
I loved mechanics but after this video I feel mechanics. Thank you.
i send you my thanks from arab world . you are amazing
you really really helped me
These videos helped me pass this class. Thank you sir.
thanks sooo much. my teacher is horrible and I've actually learned more from watching your videos than attending her lectures
you're soooooo welcome.
thank you so so much, I really learn form the video
Your drawings are lit bro!
very useful!!!, thanks, I've learn a lot
dude's a wizard man
You are amazing! Thank you so much!
shouldn't the compressive force also include the force from the neutral axis down to the top of the base of the beam (30-20) that is on the vertical section?
we're calculating the normal stress at the very bottom of the cross-section, which is 30 mm from the neutral axis.
structurefree wouldnt that volume on the vertical section have a force resultant that would add to the force resultant from the bottom part of the beam?
@@structurefree sir, he's got a point. Care to explain why the little strip of 10mm x 20mm vertical strip not i cluded in your compressive resultant force?
What hardware do you use for screen drawing? BC it's not a mouse for sure
Should'nt the depth of the Flange be 3m . when u calculated Force resultant you took the area of flange as 29 mm x 60mm but the stress is acting sideways tht means that the area should be 20 mm x 3 m or 3000 mm . No ??
why doesn't the I in the -my/I formula just equal 1/12*bh^3?, I just dont understand the Ady^2 part and its use
WarmSensations I think the reason it doesn't show up in some of the other sections, is because for a centroid located at a distance of 0 from neutral axis, (picture an I shape where centroid of bottom left is in line with the neutral axis). However, lets say the top rectangle of the I has a centroid an actual Y-distance from the N.A. Therefore only that one has a Ady^2 on it.
For the resultant why did you use 0.5*(Sigma1 + Sigma2)???
please also do Bending stress
Hey man, just one question. Why is your compression in the stress profile (red) isn't flipped on the left side since it is negative?
Great video nonetheless! Been helping me out quite a lot! Cheers!
It doesn't matter
If you look closely you'd find out that the stress arrows are already flipped due to compression
For the force resultant part why just calculate the compression part (30mm from neutral axis) instead of calculate the whole thing?
and how you determine the top part is undergo tension and bot part is compression? structurefree
imgassault depends on the internal moment.
structurefree Hahaha I figured it out just the moment I finish type the comment == Anyway thanks for your response you are much more better than my lecturer.I will like to watch all your video :)
Will you please just come teach all of my classes
at 2:00 don't you mean 1m/1000mm?
shylildude the unit conversion is to convert kN-m into kN-mm.
shylildude the unit conversion is to convert kN-m into kN-mm.
Awesome!
Very good
bam. thanks