This is the best video I’ve watched on combined loading and not to mention, I haven’t understood the right hand rule for YEARS because no one has ever explained it well to me, but this video cleared up all my confusion on everything. Everything I questioned that I didn’t even understand enough to question was explained so well! I wish I found this video sooner
OMG... Thank you!!!! I was very confused with why the transverse shearing stress could be = to 0 sometimes and I spend hours trying to understand why and thanks to you I finally understand it, x1000 thanks, pls keep making videos, they're amazing!!!!
Thank you a lot for giving such a compact video, all in one concept. Our lecturer tried to teach this topic but it took his 2 hour to finish such kind a problem.
Really great video. I'm doing a lab on combined loading right now and I was wondering how you would calculate strain at point A in this problem if you have the modulus of elasticity?
In combined loading problem, are we considering a 2D square element on the surface of the member or a 3D cube stress element? I am getting confused on what the orientation of the element chosen is and how the stresses act on that element.
Thank you! I have a quick question sir. The axial force that is perpendicular to the cut will cause a normal stress, and the other two axial forces will cause torsional and shear stresses. How do we differentiate which force will cause the torsional stress and which force will cause the shear stress?
if the force is an axial force, it will cause a normal stress. if the forces are parallel to the cross section (fx and fy) then they're shear forces that will cause a shear stress and a bending stress (using Mx and My) and if the moment (Mz) is longitudinal then it creates torsion
Is there no quantitative way of calculating the moments other than imagining it? i tried using cross product which is M= r xF but i always get the negative of what you get for moments.So i got -200000,-300000, and 600000. pls help
Remember that we are calculating the internal moments at the cut: they will be exactly opposite the external moments created by r x F. These are the internal moments at the cut that counteract (sum to zero) the external moments.
correct, there is no normal force because there are no forces in the z direction in this problem. There is normal stress, though, due to one of the moments.
@@engineeringdeciphered oh okay. This topic really confuses me. Do you have other examples like this ? I really want to get a hold of it and master it.
The video before this is the explanation of 3D combined loading, and then there are two more examples after this one. You can these 5 videos in order on my mechanics of materials playlist
Why is no one saying how awesome this video is? Literally, this video is so well explained that it's insane
This is the best video I’ve watched on combined loading and not to mention, I haven’t understood the right hand rule for YEARS because no one has ever explained it well to me, but this video cleared up all my confusion on everything. Everything I questioned that I didn’t even understand enough to question was explained so well! I wish I found this video sooner
OMG... Thank you!!!! I was very confused with why the transverse shearing stress could be = to 0 sometimes and I spend hours trying to understand why and thanks to you I finally understand it, x1000 thanks, pls keep making videos, they're amazing!!!!
Wow i cant believe how simple you have made this for me, thank you very much really appraciate it.
Thank you a lot for giving such a compact video, all in one concept. Our lecturer tried to teach this topic but it took his 2 hour to finish such kind a problem.
this really made it so much easier to understand seriously thank you !!
hell yeahg
I hope you understand you have helped me and many other students before l because of this video, and I thank you for it.
very neat and well explained, thank you
u re really lifesaver
Superb..simplified..clearing lot concepts..
amazing explanation thanks a million!
Very well done and super helpful. Thanks!
Amazing video, thank you
Many thanks!!!!!!!!!!
great explination, thanks
hey, what app are you using? thanks for the video btw
It was great, thanks
Really great video. I'm doing a lab on combined loading right now and I was wondering how you would calculate strain at point A in this problem if you have the modulus of elasticity?
In combined loading problem, are we considering a 2D square element on the surface of the member or a 3D cube stress element? I am getting confused on what the orientation of the element chosen is and how the stresses act on that element.
great work 👍👍❤❤
why isn't the Fy force direction going the opposite direction considering that you got a - Fy in your calculation
when using cross product I am getting +200 ; +300 ; +600, which is the best way of calculating the internal moments?
Thank you! I have a quick question sir. The axial force that is perpendicular to the cut will cause a normal stress, and the other two axial forces will cause torsional and shear stresses. How do we differentiate which force will cause the torsional stress and which force will cause the shear stress?
if the force is an axial force, it will cause a normal stress. if the forces are parallel to the cross section (fx and fy) then they're shear forces that will cause a shear stress and a bending stress (using Mx and My) and if the moment (Mz) is longitudinal then it creates torsion
Thanks, Daniela!@@Daniela-it1fc
how do you know the force in the z direction is pointing that way?
three forces and three moments are all you need bro
Is there no quantitative way of calculating the moments other than imagining it? i tried using cross product which is M= r xF but i always get the negative of what you get for moments.So i got -200000,-300000, and 600000. pls help
Remember that we are calculating the internal moments at the cut: they will be exactly opposite the external moments created by r x F. These are the internal moments at the cut that counteract (sum to zero) the external moments.
So basically are you saying there’s no normal force in this problem?
Only shear forces?
correct, there is no normal force because there are no forces in the z direction in this problem. There is normal stress, though, due to one of the moments.
@@engineeringdeciphered oh okay.
This topic really confuses me.
Do you have other examples like this ?
I really want to get a hold of it and master it.
The video before this is the explanation of 3D combined loading, and then there are two more examples after this one. You can these 5 videos in order on my mechanics of materials playlist
Which book do you get the example?
I think Hibbeler’s Mechanics of Materials textbook
I thought the I of the circle supposed to be pi*d^4/64
You can use your equation as well. That’s the same as pi*r^4/4 because r=d/2
th-cam.com/video/vwqf54paRk4/w-d-xo.html part 2 guys
ims till struggling :(
my god i hate physics