Flexure Formula (Part 1) - Mechanics of Materials

แชร์
ฝัง
  • เผยแพร่เมื่อ 25 ม.ค. 2025

ความคิดเห็น • 76

  • @ismaelmunoz152
    @ismaelmunoz152 7 ปีที่แล้ว +5

    appreciate the fact that you sound like a homie rather than an old boring prof. makes me understand things better (:

  • @goodguyishagoodguy9798
    @goodguyishagoodguy9798 5 ปีที่แล้ว +5

    I want to truly thank you, pulling an all nigther, covering weeks of work

  • @jazzbuckeye
    @jazzbuckeye 12 ปีที่แล้ว +1

    I can't thank you enough for these videos. I usually stare at an awful lecturer or at my Hibbeler book for multiple hours and get nowhere, but this is making my life a lot easier.

  • @structurefree
    @structurefree  11 ปีที่แล้ว +38

    I wish I were my prof too.

    • @kennethlian3585
      @kennethlian3585 3 ปีที่แล้ว

      a tip: watch series on Kaldrostream. I've been using them for watching lots of of movies recently.

    • @ralphkai9078
      @ralphkai9078 3 ปีที่แล้ว

      @Kenneth Lian Yea, I've been watching on kaldroStream for since december myself =)

  • @bigboateng2011
    @bigboateng2011 9 ปีที่แล้ว +99

    that moment when a free 15mins video explains things better than a paid 1hr lecture

    • @structurefree
      @structurefree  9 ปีที่แล้ว +56

      That moment of clarity when all things come together like that first bite of a peanut butter and jelly sandwich and a tall glass of cold milk....well soy milk because....you know. #youknow

    • @Rayquesto
      @Rayquesto 8 ปีที่แล้ว +1

      structurefree Yuknows Beyancenulls.

  • @MassiniMonster
    @MassiniMonster 10 ปีที่แล้ว +3

    Thank you so much for these videos! My professor is super hard to understand and goes so fast that i feel completely lost in class, but when I watch your videos everything makes sense the first time.

  • @wayupthep0unds
    @wayupthep0unds 9 ปีที่แล้ว +1

    I was getting so stressed out because I couldn't get my head around this after my lecture, then I watch this and all my problems were ironed out! Thanks a bunch man!!

  • @rikschoonbeek
    @rikschoonbeek 8 ปีที่แล้ว +2

    This is so much easier to digest than those dry textbooks. Much gratitute for putting your stuff online!

  • @jovanilijevski466
    @jovanilijevski466 9 ปีที่แล้ว +3

    This is a great explanation of the flexure formula. Thanks man. Greetings from Macedonia. Keep up with the good work.

  • @structurefree
    @structurefree  11 ปีที่แล้ว +2

    thanks for the comments. It just takes time and Allen Iverson's favorite word.

  • @structurefree
    @structurefree  11 ปีที่แล้ว

    Thanks for the support, but let's not get carried away here it's just a video on mechanics. Although I would not mind being able to convert water to wine on a regular basis....is there an app for that?

  • @arupkuet
    @arupkuet 7 ปีที่แล้ว

    This video is really helpful. It includes figure that's why it seems very easy to understand...

  • @kenikozo
    @kenikozo 12 ปีที่แล้ว +1

    Dude, great videos. I love your attitude! Keep up the great work bro

  • @structurefree
    @structurefree  11 ปีที่แล้ว +3

    no, no, no, you're amazing.

  • @aahmedbhatti8344
    @aahmedbhatti8344 11 ปีที่แล้ว

    You are a Beautiful person...My mechanics prof doesn't speak English so this is amazing

  • @ariefsyahrizal3645
    @ariefsyahrizal3645 5 ปีที่แล้ว +1

    Thank U sir.. You explain it so Clearly.

  • @MisterBinx
    @MisterBinx 8 ปีที่แล้ว +4

    This is cool because it's mathematical proof that the top is compressing and the botton side is in tension. In statics it wasn't as obvious to me.

  • @JusticeHunter
    @JusticeHunter 9 ปีที่แล้ว +3

    thank you very much for the videos and all the effort you put into doing these amazing stuff

  • @TheTablamaniac
    @TheTablamaniac 9 ปีที่แล้ว +1

    Excellent video. Thanks. I have doubt. If I have a highly elastic beam in pure bending (no shear), until what included angle will the formula for strain (i.e. -y/R) be valid?

  • @linsey5627
    @linsey5627 8 ปีที่แล้ว +2

    Thank you for this video, it was very helpful!

  • @raveenekanayake9494
    @raveenekanayake9494 8 ปีที่แล้ว +11

    seriously you should lecture us in the uni!

  • @mxcollin95
    @mxcollin95 5 ปีที่แล้ว

    Awesome channel! So glad I stumbled onto your channel! Thanks for sharing.

  • @SWCoastBodyboarding
    @SWCoastBodyboarding 6 ปีที่แล้ว +2

    To the point and very clear. Thanks!

  • @shubhamshah6499
    @shubhamshah6499 8 ปีที่แล้ว +4

    really sir you are great

  • @zuby555
    @zuby555 12 ปีที่แล้ว +1

    Thank you, these videos are really clearing up a few misconception I have had!
    What programs and equipment do you use to produce these videos?

  • @53BigNasty
    @53BigNasty 8 ปีที่แล้ว +9

    The dude is like a wizard.

  • @liamodonnell9091
    @liamodonnell9091 10 ปีที่แล้ว +1

    you're such a DON! your videos are targeted towards viewers actually understanding! Thanks so much for these! I hope they stay on youtube for a long time to come!

  • @aprihi
    @aprihi 10 ปีที่แล้ว +2

    Thanks a lot sir! This video really helps me! Keep up the good work :)

  • @xtcKrauspe
    @xtcKrauspe 11 ปีที่แล้ว

    What program are you using to write these tutorials out for us? Looks nice

  • @tomray4702
    @tomray4702 5 ปีที่แล้ว

    for your delta s and delta s', are those values some arbitrary line above the neutral axis or do they represent the section above that line?

  • @alimorgan3737
    @alimorgan3737 4 ปีที่แล้ว

    Could you tell me any real-life applications of Deformation of a thin plate and/or Linear Elasticity, i already have a condenser microphone and thermoplastic thermoforming
    Thanks

  • @reymarkquisel5939
    @reymarkquisel5939 9 ปีที่แล้ว +2

    tnx for uploading this video I hope this
    will help me..
    for addition on my knowledge

  • @فرجبنعمران-ص9س
    @فرجبنعمران-ص9س 6 ปีที่แล้ว

    can we say that y/raw is the ratio of change in length and multiply it by the x

  • @tara-jodeagle4755
    @tara-jodeagle4755 7 ปีที่แล้ว

    My suggestion is that you step away from the book derivation and attempt to derive it by yourself using your own notation; it will involve failing, but that will show you what assumptions they made and what simplifications they stepped into (which you could mention here for completion). That also helped me better explain the buckling formula. Also, you could include an analysis from a meshed FEM software like Abaqus, to show that the assumptions about the 'NA' are incorrect and limit the beam formula in the longitudinal direction (for completion). The limitations of the beam formula should be known to the designer, especially in more complex cross sections (even if prismatic). Local buckling, longitudinally asymmetric elongation, etc. are products of the simplifying assumptions. These concepts give the user a balanced idea of what the beam formula can and cannot do.
    Also, the DelX = p*DelTheta is a geometric property of arc length, not triangles. See: "The angle around a circle can go from 0 to 2 pi radians. The arc segment length is always radius x angle. When the radius is 1, as in a unit circle, then the arc length is equal to the radius."-www.geogebra.org/m/mbzAXPmu
    That property is valid beyond small angles.

  • @diasy77714
    @diasy77714 8 ปีที่แล้ว

    Is there anyway you can post your notes from the videos?

  • @johnyjoe2k
    @johnyjoe2k 6 ปีที่แล้ว

    But how do you find the radius of curvature???

  • @antreaschatzitofi1614
    @antreaschatzitofi1614 6 ปีที่แล้ว

    if the question says compressive stress=45 MPa in my calculations do I have to use positive or negative sign?

  • @yoshitasahishnaa
    @yoshitasahishnaa 9 ปีที่แล้ว +2

    in the beginning of the video ... when you mentioned neutral axis.. you actually meant longitudinal axis of the beam. Neutral axis comes only in the cross section right?

    • @structurefree
      @structurefree  9 ปีที่แล้ว

      yoshita sahishna technically it's a plane.

  • @dustinbrennan5271
    @dustinbrennan5271 10 ปีที่แล้ว +1

    Hey! Great video! I have a question. This derivation shows that strain varies linearly along the cross section. (saying (epsilon)=-y/(rho).) Is this only valid for linear elastic bending or will the section strain graph change from linear to some other shape when it yields? like if for instance a steel beam yielded, would the strain still be linear along the section? Thank you!

    • @structurefree
      @structurefree  10 ปีที่แล้ว +1

      Dustin Brennan even if the materials yield, a beam's strain profile still remains linear assuming everything stays connected. The stress profile however would no longer be linear.

    • @structurefree
      @structurefree  10 ปีที่แล้ว

      Dustin Brennan Great question!

  • @easyengineering483
    @easyengineering483 7 ปีที่แล้ว

    I love your channel

  • @1Motoko
    @1Motoko 11 ปีที่แล้ว

    Id rather pay my tuition money to youtube than to my reputable 4 year university...
    Thank you Structurefree.

  • @rajuthapamagar1438
    @rajuthapamagar1438 8 ปีที่แล้ว +4

    The neutral axis you are showing is wrong..its called neutral plane. The neutral axis is along the z axis at each cross section, isn't it???

    • @TheSunshineRequiem
      @TheSunshineRequiem 7 ปีที่แล้ว

      that's what i thought, z lying in the plane of the cross section is the neutral axis, x-axis is the longitudinal axis, this is straight from the text book.

  • @vatsaakhil
    @vatsaakhil 7 ปีที่แล้ว +2

    If you ever do a MOOC, I'm in.

  • @reymarkquisel5939
    @reymarkquisel5939 9 ปีที่แล้ว +1

    tnx for uploading this video I hope this will me little bit

  • @willtolife9323
    @willtolife9323 7 ปีที่แล้ว

    I still don't understand what it means by linearly

  • @andreduplessis8384
    @andreduplessis8384 9 ปีที่แล้ว

    Thanks this helps a lot.

  • @geezerlb4066
    @geezerlb4066 6 ปีที่แล้ว

    amazing content:))

  • @shaikhshaan8507
    @shaikhshaan8507 8 ปีที่แล้ว

    thanks !!!! you easily described it sir :)

  • @anjleenatufail
    @anjleenatufail 5 ปีที่แล้ว

    What is (ro).∆theta ....? Can someone tell me plzzz

    • @structurefree
      @structurefree  5 ปีที่แล้ว

      It is the arc length when the angle, deltatheta, is very very small.

    • @anjleenatufail
      @anjleenatufail 5 ปีที่แล้ว +1

      @@structurefree thanku 😊

  • @wardiegal8612
    @wardiegal8612 8 ปีที่แล้ว +1

    Thank you.

  • @FelixyzTv
    @FelixyzTv 12 ปีที่แล้ว

    you're amazing

  • @PurpleNurpple
    @PurpleNurpple 8 ปีที่แล้ว +2

    If you were near me I would kiss your beautiful head in thanks because I'm so happy. Been stuck on this problem for hours because my lecturer never bothered to explain ANY OF THIS!

  • @RohKage
    @RohKage 8 ปีที่แล้ว

    I didn't get the ∆x=(rho).∆(theta)

    • @Aman78628
      @Aman78628 8 ปีที่แล้ว +1

      its a formula for finding out the arc length of a circle
      if theta is angle and r is radius then length of curvature\ arc length lets call it S, is given by
      s = r x theta
      if you want proof\ derivation of formula think of it like this
      circumference of whole circle = 2pi x R
      now here 2pi is not just a constant number but it is angle in radians
      so the formula for arc length is S = R x angle(in radians)

    • @SaiKrishna-vz1up
      @SaiKrishna-vz1up 8 ปีที่แล้ว +1

      Roh Nain bro it's simple...l=r*thetha is the formula where l is length of arc r is radius and thetha is the angle enclosed by the arc

  • @teejar12
    @teejar12 11 ปีที่แล้ว

    geez you love dat straight edge XD

  • @reymarkquisel5939
    @reymarkquisel5939 9 ปีที่แล้ว +1

    upload more videos

  • @structurefree
    @structurefree  11 ปีที่แล้ว

    fo sho.

  • @structurefree
    @structurefree  11 ปีที่แล้ว

    word.

  • @danielminch4448
    @danielminch4448 3 ปีที่แล้ว

    You drew left handed axes OOF

  • @aseelremawi481
    @aseelremawi481 11 ปีที่แล้ว

    I need lectures in Arabic if I allowed the student of Civil Engineering

  • @cykia3102
    @cykia3102 11 ปีที่แล้ว

    wish you were my prof -__-

  • @amirhossainraju676
    @amirhossainraju676 8 ปีที่แล้ว

    Hey dude you sound like Salman khan from khan academy..

  • @danahaddi1358
    @danahaddi1358 8 ปีที่แล้ว

    thx dude but please stop using the word " BAMM "

  • @zhilinzhuo7201
    @zhilinzhuo7201 6 ปีที่แล้ว

    my prof sucks...