Heat Removal from a Chemical Reactor

Organized by textbook: learncheme.com/
Determines the heat removal so that a chemical reactor is isothermal. Made by faculty at the University of Colorado Boulder, Department of Chemical and Biological Engineering.
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[@LearnChemE]

This screencast has been reviewed by faculty from other academic institutions.

[@maysamahmoud813]

Thank you very much only i love thermodynamic from this channel thanks alot for your effort

[@binn12t82]

why do not we multiply the heat of reaction for amonia at 25C by 2 since 2 moles of NH3 are formed ?

[@LearnChemE]

+t13 ta Great question. The heat of reaction is dependent on a reference state. In this case, the 46 kJ/mol is based "per mole of NH3". If you looked up the heat of reaction for N2 +3H2 -> 2NH3, it would be -92 kJ/mol, but since that is to produce 2 moles of NH3, you would divide the number by 2, therefore getting the same answer. Does that make sense?

[@Pink_kiwi707]

LearnChemE @ 6:00 cool down the "reactant" stream

[@rainelrodriguez4806]

this is a bad explanation , i m doing the replacement of the variables and i cant get the final result dont know why

[@hanswurst1724]

If we would Not remove the heat, what would be the temperature increase assuming an adiabatic process? Is it T_end= (q/(m*c_p)) + 350?
Thanks

[@ahmedselim5735]

the heat of reaction calculation , we must multiply heat of formation of ammonia by stoic. coeff. of ammonia which was not done here !!!!!!!