Very easy. Square the first equation you get a+b+2 root"a"root "b". Equation is a+b+20=100.So a+b=80. Substitute this .By squaring this you aSquare+b square+2ab=6400. So u get a×a+b×b=6400-200=6200. You bringby either substituting for a or for b. You get quadratic equation in one variable with two solutions. And then substitute to get the value of other.
Much simpler: Since ab = 100, once you know a + b = 80, substitute 80-b for a in the first equation: (80-b)b = 100 80b - b^2 = 100 b^2 - 80b + 100 = 0 Use quadratic equation as before.
Very easy. Square the first equation you get a+b+2 root"a"root "b". Equation is a+b+20=100.So a+b=80. Substitute this .By squaring this you aSquare+b square+2ab=6400. So u get a×a+b×b=6400-200=6200. You bringby either substituting for a or for b. You get quadratic equation in one variable with two solutions. And then substitute to get the value of other.
Much simpler:
Since ab = 100, once you know a + b = 80, substitute 80-b for a in the first equation:
(80-b)b = 100
80b - b^2 = 100
b^2 - 80b + 100 = 0
Use quadratic equation as before.
A+b and ab known find a-b
And salvove a,b
8 and 6
Why back ground music
Too many steps; could be simpler.