I can see how to get it, before watching the video, I would use the system of equations to subtract 2 equations then factor out one of the variables. I would do E2-E1=>E5 and E3-E1=E6 then use the factored variables to substitute then plug in the values to get one variable by itself. Then substitute the variable back in to solve another variable then repeat for the last variable
(abc)^2=100×200×300
Applying square roots to get abc. Then, a= abc/bc; b=abc/ac; c=abc/ab
@@uthamann134 This process is right
(55/3) √6
I can see how to get it, before watching the video, I would use the system of equations to subtract 2 equations then factor out one of the variables. I would do E2-E1=>E5 and E3-E1=E6 then use the factored variables to substitute then plug in the values to get one variable by itself. Then substitute the variable back in to solve another variable then repeat for the last variable
I like how you did it. It brings in a different perspective to me in math.
400
bc=⅔ac----->b=⅔a
bc=2ab------->c=2a
ac=a×2a=2a²=300----->a²=150----->a=√150
a+b+c=11/3a=11/3（√150）
Very nice and interesting to see the solution.
b=200/c
a*200/c=100 a=100/200*c 2a=c
ca=300 2a*a=300 2a(sq)=300 a(sq)=150 a=sq root 150 a=12.25
ab=100 12.25b=100 b=100/12.25 b=8.16
ca=300 c*12.25=300 c=300/12.25 c=24.49
a+b+c=12.25+8.16+24.49=44.90
a+b+c=44.90
a= √150 , b = 100/ √ 150 and c= 300/√150
a+b+c= 55√6/3
Nicely explained.
a=100/b,b=200/c
a=100/200/c=1/2*c
1/2*c*c=300,c=√600
b=200/√600,a=√600/2
A=100,B=0,C=200.
Thanks friend it useful
300b.b=100×200
b.b =2/3
b=(2/3)^1/2
a =
Good explanation ❤️
b=200/c
b=100/a
2a=c
3a=300
a=100
c=200
b=1
a+b+c=100+1+200=301
So complicated ,it can be solved in 3 minutes
A 0, B 100, C 200
There is no beauty in either exercise or solution
A 100
B 000
C 200
A+b+c=300
Simple explanation
So complicated, and eine gute exercise, but with equation i’ts simply!
a=100/b, b=200/C, C=300/a
a+b+C=100/b+200/C+300/a
=100.ca+200.ab+300.bc
=100.300+200.100+300.200
=30000+20000+60000
=110000
It shocks and disappoints me that so many people said b=0 …. When they know b multipled by a or c is a higher value than 0
B_50+c-150-200
Gjithnje i referohem zgjidhjes klasike; kemi 3 ekuacione me 3 te panjohura. Duke zevevdesu njen pas tjetres.
sum=30(6^0.5)
a+b+c=25+4 + 50=79
ab+bc+ca= 600 ie 2a,+2b+2c=600 so a+b+c=300
a+b+c = 10+20+30=60
100 + 0 + 200 = 300 (b = 0)
A 100, B 0, C 200
Answer = 55
(a^2)*bc = 300 * 100
a^2 = 150 ...
(a + b + c)^2 = (a^2) + (b^2) + (c^2) + 2*(ab + bc + ca).
a + b + c = √(2016+(2/3)).
Damn that's fucking cool
Thank you for usefull tric 🙏
100 + 1 + 200 = 301
Parece-me que a explicação é muito detalhista. Será necessário tanta miudeza?
Why we multiply √3/√3 at last??
@@TheexperienceofSurya to rationalise
ఏదో చెప్పడానికి ట్రై చేసావు గాని ఏమీ అర్థం కాలా
My. Answer 30/√6+10√6/3+10√6=55√6/3.
B = 0 C =200 A = 100
இது போன்ற கணக்குகள் வாழக்கையில் பயன் பாடு இல்லை என வை தேவை இல்லை
Nation builders are the piilss of World.
I can do it.
Your equetion is differ from question, frist modify one
Wrong answer..because you are wrongly devided. 6050with 2.devide 6050 with 3 andget the result.
600😊😊😊😊
300,a=100,b=0,c=200😅
= 44,90731....irracional
c/a =2...c = 2a
b = 100/a.
a + b + c = 3a + 100/a
2a×a = 300
a = 150^(1/2).= 12,2474...
Ahora apenas substituir
This process will not be acceptable to the students.
ab+bc+ca =300+200+100 2(a +b +c ) =600 a+b+c=600/2 a+ b+c=300
@@biswarupmondal1376 wrong
@@biswarupmondal1376 how..2(a+b+c)
Genius
Молодец А тот, кто сказал ,что неправильно вообще не соображаетТы Молодец!!!
Нет я сама ошиблась
300
a+b+c=300
60
a=✔️150 , b = ✔️200/✔️3 , c= ✔️600
a+b+c = ✔️150 + ✔️200/✔️3
✔️600
.
.
.
= ✔️150(11/3)
= 55/3 × ✔️6
= +55✔️2 or - 55✔️2
=
Other way also is there
50+50+250=350
আপনার প্রশ্নই ভুল। C মান 150 A মান 50 তাহলে CA এর মান আপনি 300 লিখলেন কেন? প্রথম লিখছেন AB সমান 100 এখনে বুঝা যায় 50+50
350
சிறப்பு
600
Ac
250
300🙏
Video yu uzatmak için soruyu çözmekten daha çok uğraşmışsın
300?
unwanted steps wasting time.
Your process is lenthy,not easy
Not easy
Sorry
Why so complicated method.a*200/c=100
2a=c
2a*a=300
a sq=150 & further steps.2 min solution
You don't know how to solve,you are I think not a teacher,ok. At first you take a lesson about algebra.
Bakvas
ab+bc+ca=100+200+300
2(a+b+c)=600
a+b+c=600/2
a+b+c=300
A+b+c=300
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A+b+c=300
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a+b+c=300
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