Thank you very very much for the nice comment. I spent a fair amount of time trying to figure out how to fit everything into a well organized 10 minute video.
spent hours watching videos on this topic for the MCAT. didnt understand a single one. Thank you so much for this explanation. You made it so easy to understand this topic!
That is very nice of you to say, I spent a fair amount of time trying to figure out how to get everything in that video. You can see a listing of all my videos at my website, www.stepbystepscience.com
I'm currently taking AP Physics 1, and I already saved some of your videos in a playlist if I need them once we hit kinematics in two dimensions. You teach great!👍🙂
You are a very good teacher. All thanks to you I understand the physics 101 I am taught in the University. Please could you solve this √(8+√3). Thank you. Will be expecting your answer.
Hi, does the symmetric change of velocity in the y direction (such as the ball's velocity changing from +29.43m/s to -29.43m/s) apply to all objects in 2d motion moving with different velocities? Thank you :)
Thanks a lot however I do I have to mention that if you apply air resistance to the equation the acceleration of x will not be constant therefore will change ever so slightly
I just got a perfect score in my projectile exam, Thank you Sir!, Also do you have some tutorial about friction force sir? where you solve for acceleration,Force,Normal Force, something like that.
+Exogen Design Excellent, you are very welcome. I am glad that you found the vidoes helpful. Yes I believe I have what you are looking for. You can link to all my videos at my website: www.stepbystepscience.com Then got to Physics and then Newton's 2nd Law....here the link to one of the videos th-cam.com/video/dvk7p5-nDJs/w-d-xo.html
Brian Swarthout I'm watching it right now sir, You're probably one of the best teacher here in youtube, And I never thought I could be good in physics and mechanics since I am an electrical engineering student and mechanics isn't really my specialty, But now That I understand physics, step by step, I start loving it, Anyhow, Thank you Again for your videos Sir, Good day!.
something confused me!!!!! it is supposed they at t = 0 the velocity identical not 25 and 29.43 and at t = 1,2,3,4, .....act. we use Vfy = Viy+gt at Y direction so, the value of velocity decreases by 9.8 m/s2 in other side in x direction the value of velocity in X direction not change
I get this question a lot. It is negative because the acceleration due to gravity points in the negative direction (down). It does not mean that it is less than zero. But it does mean that when things fall down, also the negative direction, that they will be speeding up under the force of gravity. And that when things "fall up" or are projected straight up, the positive direction, that they will be slowing down under the force of gravity. Does that help?
Which velocity vector, x or y. In this case, the velocity in the x-direction is constant and to the right, at the highest point the velocity in the y-direction is 0 m/s, so there is no vector shown. Does that help?
@@stepbystepscience Omg. THANKS for the reply. I meant, what is the direction of the velocity of the projectile at the highest point if it is 0 m/s? Doesn't it have direction since it is 0m/s? Since the velocity is a vector so it doesn't only have a magnitude but it also has a "direction". That is the "direction" I'm trying to know. I just know that the direction of the velocity follows the motion of the object. Also, I read from the internet that the velocity is directed on the horizontal and in some diagrams the velocity vector points to the right, if the object is moving from left to right. I just want to confirm if they are correct. THANK YOU!
Hmm my only question here...is how is the initial starting Velocity in the horizontal direction (X) 25m/s but the vertical initial Veolicty is 29.43? Shouldn't these two values be identical?
The same thing confused me!!!!! it is supposed they have the same value but in Y direction the value of velocity decreases by 9.8 m/s2 in other side in x direction the value of velocity in X direction not change
I'm too slow for this dude. He talks too fast for me and I don't get all the components and symbols. I'm gonna have to watch this 10 times. It's okay though, maybe I'll figure it out. Gonna try for sure.
the best teacher in the world
Very nice of you to say, thanks for watching and commenting.
Probably the best channel for physics. Helps a lot for studying and understanding.
Thanks so much, glad it was helpful.
i have seen soo many videos related to projectile motion but this is the best tutorial video....THANKYOU SOOO MUCH ......
Thank you very very much for the nice comment. I spent a fair amount of time trying to figure out how to fit everything into a well organized 10 minute video.
same here
@@stepbystepscience well done
man you exist on earth and that's why thousands of students hope to be passed in the exam is still alive
hat's off to u you doing a great job
Thank you, I love to help students!
you got a talent for this
(explainning)
+Júlio Bessa Thank you, this video took awhile to organize and put together. You can link to all my videos at my website: www.stepbystepscience.com
spent hours watching videos on this topic for the MCAT. didnt understand a single one. Thank you so much for this explanation. You made it so easy to understand this topic!
You're very welcome! Good luck on the MCAT!
I am a physics teacher. Great job, I will utilize this to supplement my teaching.
Wonderful, best wishes for your teaching!
Please continue to do what you're doing. You are seriously talented in explaining concepts!
That is very nice of you to say, I spent a fair amount of time trying to figure out how to get everything in that video. You can see a listing of all my videos at my website, www.stepbystepscience.com
Wow, you’re an absolute legend. Best science channel on TH-cam!
Appreciate that, thanks so much!
I'm currently taking AP Physics 1, and I already saved some of your videos in a playlist if I need them once we hit kinematics in two dimensions. You teach great!👍🙂
Thank you very much, hope it goes well in AP Physics 1.
Thank you, this is the best video I have seen that covers 2 dimensional projectile motion.
Very nice of you to say.
I thought I opened a Khan academy video but this one was even more helpful
Great.
Your explanation actually led me to grasp the concept as a whole!
Fantastic, glad to hear it!
Good day! I really do like how you simplify your explanation. This is a video I badly need thank you for making it. Your so good! 💕
You are so welcome and thanks a bunch for your nice comment!
Thank youuuu!!!! I’m watching this an hour before my test please wish me luck
Good luck!!
You are going to be the reason I pass this class. Thank You!!
Glad to be of help and thanks for letting me know.
Man what an excellent explanation. No thumbs down. totally deserved. :)
Thank you very much.
I was panicking because I seriously didn't understand this concept at all, but I think I actually get it thanks to this video. Thank you!!
That's wonderful, you're very welcome.
Your videos are indeed helpful for some of us who study by correspondence. Keep it up..
So great. Our teacher is using these in our community college class to help explain concepts.
Tell you your teacher, thank you from me.
thank you very much T^T this really helped me, I couldn't find a better explanation anywhere else.
Wish every professor has your voice and your way of explaining such stuff!
Nice of you to say, thanks.
Excellent and clear explanation of everything and example given. Thank you!
You're very welcome!
Man U r the one that I was looking for u really believe and focus on the details that I like to focus on which is awesome
Glad to hear that, thanks for watching!
thats my first time i understand phy.... thank u sooo much
You are welcome, Thanks for watching and for commenting
Thank you for sharing your experience with us in this period of time.
It's my pleasure, thanks for watching.
You are a very good teacher. All thanks to you I understand the physics 101 I am taught in the University. Please could you solve this √(8+√3). Thank you. Will be expecting your answer.
Thanks for the positive comment but no.
very helpful😍😍😍 thank you so much for this video....i can understand all of your explaination👍👍👍👍!!!thumbs up for you!!😁
Great, thank you so much for the comment!
Omygosh you explained it sooo easy 😍unlike from other videos, they get too complicated
Thanks for the positive feedback!
Excellent approach for explaining 2Dmotion :). Thank you
Glad it was helpful!
The best EVER!!! Thank you for your videooo!
You're welcome!
Thank you so much. You are a great professor.
Not a professor, just a high school physics teacher. Thanks you the comment.
Great explanation i really enjoyed
Glad you enjoyed it! Thanks for the nice comment.
Wow very helpful. Thank you. Very clear.
Glad it was helpful!
I finally know what is projectile motion thank you for this
That's great, glad I could help!
Amazing explaination sir.. good job😊😊🇵🇭🇵🇭🇵🇭
So nice of you, thanks a lot!
Thank you very much for this video I now have a better understanding
That's great. Thanks for watching and best wishes.
Hi, does the symmetric change of velocity in the y direction (such as the ball's velocity changing from +29.43m/s to -29.43m/s) apply to all objects in 2d motion moving with different velocities? Thank you :)
yes.
Love this!!. step-by-Step Sci. you are blessed!
Best explanation ever i see🥰
Glad you think so!
Thank you so much. This video was very helpful👍🏻
Glad it was helpful!
You r really tallent experience in those subjects
Thanks for watching and for commenting
may you find the ultimate success
Thanks so much, you too!
Excellent v well explained
Thanks a lot, glad it was helpful.
Thanks a lot however I do I have to mention that if you apply air resistance to the equation the acceleration of x will not be constant therefore will change ever so slightly
WOW! Thank you sooooo much! It helps me!
Great, glad it helped!
Thankyou sir,
Very helpful
You are very welcome!
Sir you are excellent!!!
Thanks you for the excellent comment!
I really understood. Thank you
Great, you're very welcome
I am very understand from your video
Glad to hear that!
Excellent explanation
Thanks glad you liked it.
thank you so much this video is amazing!
You're so welcome!
This tutorial is amazing, thank you!
You're very welcome!
Well explanation
Thanks and you're welcome!
really good thank you
You're very welcome!
Such a great professor !👍🏾
UwU thanks so much! I had a math project to do on geometry and you helped me so much! alos sorry for bad English.
Glad I could help!
Thank you 🙏
You’re welcome 😊
Nice explanation
Thanks very much!
Thank you!
You're welcome!
Thank you very much
u r very helpful
Happy to help and thanks for the great comment.
U are the best
Very nice of you to say so.
Thankyou very much
Most welcome
I just got a perfect score in my projectile exam, Thank you Sir!, Also do you have some tutorial about friction force sir? where you solve for acceleration,Force,Normal Force, something like that.
+Exogen Design Excellent, you are very welcome. I am glad that you found the vidoes helpful. Yes I believe I have what you are looking for. You can link to all my videos at my website: www.stepbystepscience.com
Then got to Physics and then Newton's 2nd Law....here the link to one of the videos
th-cam.com/video/dvk7p5-nDJs/w-d-xo.html
Brian Swarthout I'm watching it right now sir, You're probably one of the best teacher here in youtube, And I never thought I could be good in physics and mechanics since I am an electrical engineering student and mechanics isn't really my specialty, But now That I understand physics, step by step, I start loving it, Anyhow, Thank you Again for your videos Sir, Good day!.
Great video! just wondering why 29.4 m/s is the initial velocity for vy
It is the given value for the initial velocity in the y-direction.
Thanks!
Welcome!
Will velocity always be +29.43 in the y direction at t=0 ?
No, it could be anything.
@@stepbystepscience if it could be anything at time=0, then at t=1, velocity will be anything - 9.81
Am I correct?
GOD BLESS YOU!!!!
Best wishes to you too
something confused me!!!!! it is supposed they at t = 0 the velocity identical not 25 and 29.43 and at t = 1,2,3,4, .....act. we use Vfy = Viy+gt at Y direction so, the value of velocity decreases by 9.8 m/s2 in other side in x direction the value of velocity in X direction not change
You are my hero
Aww, thanks!
Thank you❤
You are welcome.
amazing !!!
Thank you!!
Perfect
superb
Thanks !
Thank you sir
Most welcome
Why the acceleratio of vertical is -9.81 m/s²
I thought its 9.8 only but i dont know why?
Explain me plsss
I get this question a lot. It is negative because the acceleration due to gravity points in the negative direction (down). It does not mean that it is less than zero.
But it does mean that when things fall down, also the negative direction, that they will be speeding up under the force of gravity. And that when things "fall up" or are projected straight up, the positive direction, that they will be slowing down under the force of gravity. Does that help?
I mean why -9.81 i thought its -9.8
But how?
thank youuuu sooo muchhhhh🤍🤍🤍🤍🤍
You are very welcome.
I wish you were my physics professor
Aww, thanks!
thank you bro
Any time, you're welcome!
YOU ARE AWESOME
nice video
How did we calculate the 29.43 ? Thank you
The two values for the initial velocity in the x-direction (25 m/s) and the y-direciton (29.43 m/s) are give at the beginning of the problem.
@@stepbystepscience Thank you so much , your explanation was the best TH-cam could offer
@@stepbystepscience thank you so much
wow thank u
At the highest point, the velocity vector is directed where? I'm confused if it's downwards or rightwards. Haha. Sorry.
Which velocity vector, x or y. In this case, the velocity in the x-direction is constant and to the right, at the highest point the velocity in the y-direction is 0 m/s, so there is no vector shown. Does that help?
@@stepbystepscience Omg. THANKS for the reply. I meant, what is the direction of the velocity of the projectile at the highest point if it is 0 m/s? Doesn't it have direction since it is 0m/s?
Since the velocity is a vector so it doesn't only have a magnitude but it also has a "direction". That is the "direction" I'm trying to know. I just know that the direction of the velocity follows the motion of the object.
Also, I read from the internet that the velocity is directed on the horizontal and in some diagrams the velocity vector points to the right, if the object is moving from left to right. I just want to confirm if they are correct. THANK YOU!
That's better. Hehe. Thanks a lot! ❤
My favourite
Very nice of you to say so, thanks.
keep it up
Thanks, will do!
thank you very much 😭 !!
You're welcome 😊
Nice comment for you!
Thanks for the nice comment.
Hmm my only question here...is how is the initial starting Velocity in the horizontal direction (X) 25m/s but the vertical initial Veolicty is 29.43? Shouldn't these two values be identical?
The same thing confused me!!!!! it is supposed they have the same value but in Y direction the value of velocity decreases by 9.8 m/s2 in other side in x direction the value of velocity in X direction not change
Min 3:25 oh no that noice :U
The noise is the fire truck or ambulance going by our apartment. But thanks for watching and commenting.
Cant understand dis
sorry
I'm too slow for this dude. He talks too fast for me and I don't get all the components and symbols. I'm gonna have to watch this 10 times. It's okay though, maybe I'll figure it out. Gonna try for sure.
Stop and rewind. Hope you get it!
I really understood. Thank you
excellent.
excellent explanation
Thank you!
You're welcome!