Calculations on Alligation and mixtures

[@nirpashahi8164]

I understand all . thanks for improvement on my skills
.

[@MyShubb]

Easy way to understand the allegation method 👍🏻

[@egpat]

Glad you liked it. Thanks for watching

[@ishathakur5004]

Best video 👍👍

[@arkathiramar4442]

🙏🙏🙏🙏

[@mansiupadhyay6532]

simplest explanation ,thanks for this video

[@egpat]

You are welcome

[@ahmadfares5243]

Thank you so much 🙏🙏🙏👍👍

[@Dhanu1401]

Method of alligacy
Good explanation
Thankq

[@srikarthikjosyula668]

sir.... please help me with this problem......find out the quantity of 3% ointment which must be added to 100 gm of a 15% ointment to get 10% ointment

[@GN-Academy]

Thanks sir

[@medicalscience4822]

Very simple way

[@egpat]

Thank you 😊

[@trivenipatil1362]

Nice

[@LS-gh8sz]

hi
i dont understand this question: How many millilitres of drug suspensions containing 80 mg/5 mL and 30 mg/5ml should be mixed with to prepare 500 mL of a suspension of 10mg /ml
i converted all the concentratiin to the percentage volume whichbis g/100ml and why does the answer differ eventhough all units are the same. 1.6%, 0.6% and wanted percentage is 1%. please adviceeeeeee

[@nourannegm1449]

because your conversion is not correct.. if you convert all concentration to percentage it`ll be (h=0.16% , l=0.06% , m=0.1%) but it`s a difficult method you like may 2 conversion first from mg/5mg to mg/ml then into (g/ml)% .. whatever if you try the new percentage concentration you will find that it`s the same .. I hope you understand it

[@egpat]

All your conversions are correct.
Higher concentration (h) = 80 mg/5ml = 1600mg/100ml = 1.6 g/100ml
Lower concentration (l) = 30 mg/ 5ml = 600 mg/100 ml = 0.6 g/100ml
Final concentration (m) = 10mg/ml = 1000mg/100ml = 1g/100ml
Therefore, if we apply alligation,
1.6 1-0.6 = 0.4
1
0.6 1.6-1 = 0.6
H = m-l = 1-0.6 = 0.4
L = h-m = 1.6 -1 = 0.6
Hence, alligation ratio will be,
h:l = 0.4 : 0.6 = 2:3
Same ratio as you have seen in the video.
Please remember that, H can be obtained by using formula "m-l" not by "h-m".
Hope this clarified your question.

[@maharshithalla9291]

I think in last method we can directly go with C1V1=C2V2.
5%v/v×X=6% v/v×100mL this gives 120 mL.

[@egpat]

Exactly, You are right. When diluting with water, simply we can use the formula C1V1=C2V2. But if we are mixing solutions of two different concentrations or to know dilution ratio, we should use alligations. Thank you for watching video.

[@Baby_version]

Thank u ♥️

[@egpat]

You're welcome. Keep watching.

[@LS-gh8sz]

Search Results
(80 mg) / (5 ml) =
1.6 g / (100 ml). i got this from the internet conversion website . im sure the conversions i have stated are correct.

[@egpat]

Exactly, you are right ! 80 mg/5ml = 1600 mg/100ml = 1.6 g/100 ml

[@mx5083]

C1V1=C2V2+C3V3 YO SE QUE AL MEZCLAR SOLUCION 2 CON SOLUCION 3 VOY A OBTENER LA SOLUCION 1 LA CUAL YO SE SU VOLUMEN Y SU CONCENTRACIÓN, DE LAS OTRAS SOLUCIONES 2 y 3 YO SE SU CONCENTRACIÓN PERO NO SE QUE VOLUMEN VOY A AGARRAR DE CADA UNA, sustituimos los datos en la fórmula, 10(500)=16(X)+6(500-X). 5000=16X+3000-6X. 5000-3000=16X-6X, 2000=10X X=2000/10 X=200 ml 500-200=300 ml, 200 ml de la solución de 80 mg/5 ml y 300 ml de la solución de 30 mg/5 ml. NOTA= X no se que volumen es, pero al encontrarlo por ejemplo 150 y el otro volumen será completar los 500 ml o sea 500-150=350 ml