Your entire lecture is helpful for me but I am stuck how to draw sfd and bmd in this type problem..can you make a video on that in a easiest way?? So that all will be helpful
Tanvesh D no thats wrong because at first end fem should be 🔄 and second end fem 🔃 Element AB First end A : 🔄 so - Second end B : 🔃 so + Element BC First end B : 🔄 so - Second end C : 🔃 so + Element CD First end C : 🔄 so - Second end D : 🔃 so + And so on.... U can see that concept on moment distribution method lectures of this channel
No akash, im the one who makes these lectures,you are not thinking conceptually here, its not always that the first end has to be negative just because in all other case it is negative, the direction of a fixed end moment is determined on how the member is deflected. If it is causing a clockwise deflection due to the load at that end then the fixed end moment will be anticlockwise and hence negative, whereas in this case if you see at end A the load is causing an anticlockwise rotation and hence the FEM will be clockwise and therefore positive. I hope you understood the concept.
Hi Sir, why is the sign convention here ( Minute 8:09- ClockWise positve) different than what you already explained in the Video where you explained the stiffness Matrix ( Video : Civil engineering - Stiffness method structural analysis - Concepts & Basics) thank you in advance
Hossam ALDAFFAIE yes you are correct about that video in which i had shown double arrows and their corresponding moment direction and in that anticlockwise was taken as positive, i have also solved a problem using the concepts i had explained in that particulat video and that video is a bit of higher difficulty level than this current video lecture. This is a much simplified approach for stiffness matrix that is taught to students so they do not get confused, so for simplicity without going into details i have taken clockwise positive in this video lecture however you are free to choose your sign convention before you start solving the problem and stick to that sign convention throughout the problem.
What happens when you have a symetric structure, and only moments due to distributed loads, i seem not to find a by hand solution and yet the softwares say that there is
@@DCBAonline If i use a symetric frame and grid structure where all the beams are the same length, then, the forces of action in the in between nods will sum cero, cause all the double fixing condition when writing the stiffness matrix. And so, since i work with these conditions i haven't been able to match the results from ftool, and i'm thinking maybe is because i'm missing something that has to do with the action forces and how to write down the force vector. I solve it in Excel (of course) but the final moments equations are never correct. I'm working in the simpliest case, with two beams and three columns loaded with distributed charge only and 1 lateral pushing force since there's only one slab.
Hello sir....sir ap kab cable's and suspension bridge pe video ban rhe ho....or ek or bat sir ji mjh two hinge arch mai bhi problem aa rhi hai usse bhi ek video ban do please sir
You can solve it by using simultaneous equations function in the calculator by going to Mode --> 5 (EQN) --> 2 and then input all the variable parameters.
sir please upload the sway frame sum !! Even i am a student of datta and took elective of ASA this sem...if any notes of yours we can get then it'll be great sir !!
You are talking about externally applied moment which has nothing to do with fixed end moments, fixed end moments are calculated based on loads or moments applied on span and not on joints.
Sriteja Komarivolu actual i dont have more problems solved with that method currently, you will have to refer to my previous lectures of stiffness matrix which has been solved that way.
Your entire lecture is helpful for me but I am stuck how to draw sfd and bmd in this type problem..can you make a video on that in a easiest way?? So that all will be helpful
Many thanks, it was very useful for me !
awesome video brother
GREAT................
Sir plz make a video on truss by stiffness matrix method
THANKYOU SO MUCH FOR THIS
Pls make videp on sway frame solved using stiffness method
Sir, could you make a video of truss analysis using stiffness matrix method. please?
I think u did a mistake in fem
Mfab should be nagetive
Mfba positive
Then all r correct
M i right?
Akash Gohel no, it is correct, you need to check the frame while standing inside.
Tanvesh D no thats wrong because at first end fem should be 🔄 and second end fem 🔃
Element AB
First end A : 🔄 so -
Second end B : 🔃 so +
Element BC
First end B : 🔄 so -
Second end C : 🔃 so +
Element CD
First end C : 🔄 so -
Second end D : 🔃 so +
And so on....
U can see that concept on moment distribution method lectures of this channel
No akash, im the one who makes these lectures,you are not thinking conceptually here, its not always that the first end has to be negative just because in all other case it is negative, the direction of a fixed end moment is determined on how the member is deflected. If it is causing a clockwise deflection due to the load at that end then the fixed end moment will be anticlockwise and hence negative, whereas in this case if you see at end A the load is causing an anticlockwise rotation and hence the FEM will be clockwise and therefore positive. I hope you understood the concept.
th-cam.com/video/fB2CyLGdzIk/w-d-xo.html check this video that i just uploaded for fixed end moments, it might clear your concepts
Tanvesh D oh thats the concept i didnt know about the concept thanks for that
Hi Sir, why is the sign convention here ( Minute 8:09- ClockWise positve) different than what you already explained in the Video where you explained the stiffness Matrix ( Video : Civil engineering - Stiffness method structural analysis - Concepts & Basics)
thank you in advance
Hossam ALDAFFAIE yes you are correct about that video in which i had shown double arrows and their corresponding moment direction and in that anticlockwise was taken as positive, i have also solved a problem using the concepts i had explained in that particulat video and that video is a bit of higher difficulty level than this current video lecture. This is a much simplified approach for stiffness matrix that is taught to students so they do not get confused, so for simplicity without going into details i have taken clockwise positive in this video lecture however you are free to choose your sign convention before you start solving the problem and stick to that sign convention throughout the problem.
thank you so much sir. i understood that
i am really grateful for your answer sir
What happens when you have a symetric structure, and only moments due to distributed loads, i seem not to find a by hand solution and yet the softwares say that there is
Why cant you find a hand solution? Where are you getting stuck?
@@DCBAonline If i use a symetric frame and grid structure where all the beams are the same length, then, the forces of action in the in between nods will sum cero, cause all the double fixing condition when writing the stiffness matrix. And so, since i work with these conditions i haven't been able to match the results from ftool, and i'm thinking maybe is because i'm missing something that has to do with the action forces and how to write down the force vector. I solve it in Excel (of course) but the final moments equations are never correct. I'm working in the simpliest case, with two beams and three columns loaded with distributed charge only and 1 lateral pushing force since there's only one slab.
Sir plz make video on stiffness matrix for truss element
Hello sir....sir ap kab cable's and suspension bridge pe video ban rhe ho....or ek or bat sir ji mjh two hinge arch mai bhi problem aa rhi hai usse bhi ek video ban do please sir
Thank you
sir can you plzz make a video on Slope and deflection of beams
how to identify whether it want rotations or deflections to solve the problem?
K12,k32,k23,k21 is anty clock wise so wetake negative sigh . But not take in stiffness matrix value formation why sir?
They are clockwise, not anti clockwise.
Shouldn't Mba be equal to Mbc at last to maintain equilibrium
do for truses and fabrication error and temperature changes please
If joint E settlement is there... Then what will be the value of P3
Good day, what function on the calculator is used to determine the displacments theta B, C, and E? I used a Casio fx-991ES PLUS. Thank you very much.
You can solve it by using simultaneous equations function in the calculator by going to
Mode --> 5 (EQN) --> 2
and then input all the variable parameters.
Thank you very much Sir.
which software you used for making such types of videos
CIVIL TECH its MS Powerpoint 2016
Can't we use slope deflection simply at last ,sir?
You can use to cross check.
sir please upload the sway frame sum !! Even i am a student of datta and took elective of ASA this sem...if any notes of yours we can get then it'll be great sir !!
Shouldn't MFAB be -10 kNM
why this frame is non sway frame give geniune resons:
Once checkout Mfcd & Mfce
Its correct.
@@DCBAonline moment at c is in clock wise na...so..why it is negative w.r.t D
You are talking about externally applied moment which has nothing to do with fixed end moments, fixed end moments are calculated based on loads or moments applied on span and not on joints.
Sir global stiffness matrix, local stiffness matrix, transformation matrix use chesi cheyandi sir . Those formulas are different from this concept
Sriteja Komarivolu yes in the start of this lecture i had mentioned that this is a easier way of analysing a problem using stiffness method.
Sir I'm doing m. Tech. Plz up load with that method exam is there sir. If I follow this simple method I can't get sufficient marks
Sriteja Komarivolu actual i dont have more problems solved with that method currently, you will have to refer to my previous lectures of stiffness matrix which has been solved that way.
Your fixed moment wrong in AB,CD
No its not.
The point load is acting at centre of vertical member
Of it is acting at centre WL/4 Fixed end monent
So? Calculate and check the answer comes out same, i dont use a different formula for centre loading.
But you have mentioned Wb2a/L2
Sir can I contact personally on email