I saw many video lectures but lots of doubts and confusion. I find your lecture crisp and clear. no confusion at all. You r really good at teaching. Thank you!!
Sir,I have watched all the videos but i didn't find any question in which supports are settling.I am facing a problem in that type of questions.please upload the video for that..Thanks sir for the amazing lectures!!
For calculation of Ar1 matrix value of Ra comes out to be 53.34 and Rb as 26.66 your values is different from my values which one is correct pls tell ☺
Thanks , very helpful and quite easy to understand , I have one doubt...what if all support are fixed instead of roller or pin at B & C, In that case how do we proceed
when you were finding for the member reaction matrix for member 2 @ 18:30 why did you assume that the member is fixed from both sides, you can apply the FEM as FEMbc= WL^2/8 since its a roller ended beam. Because you will be getting a different answer if you're assuming its fixed ended from both sides
Ahmed Ismail while writing those equations you need to consider all supports to be fixed, the fact that it is a roller would be used in Step 7 when you cancel out all what is not required.
So you mean that if i applied the advanced FEM equation for the roller ended part as WL^2/8 it would be wrong when am writing down the Reaction matrix, And its a must to to assume that its always a fixed end even though its not always fixed ended? Thank you sir for your quick response and you have earned your self a new subscriber :)
Ahmed Ismail by writing advanced FEM equation u mean finite element method quation or fixed end moment equations?, that step was reaction step and you need to write the fixed end moments ans reactions generated at each span and for that matte you need to assume every span to be a fixed end span.
DCBA online I mean the fixed end moment equations for a roller/pin ended span like in this example which I was suggesting to use wl^2/8 and assume that it's only fixed from one end which is b when analysing Member 2
Well to just simply say, it is the method which has to be followed but if you want an explanation than, there we are dealing with two kinds of matrix one is a load matrix and another one is a reaction matrix, take note that both are opposite in nature to each other and hence if we have to combine them we have to change the sign of reaction matrix i.e. done by subtracting it and hence Ar is subtracted from Aj.
Hi, thank you for the clear explanation, how can I contact you? I have a question in fining weak form from governing equations of the Timoshenko beam, may be you can help me. thank you
sir please make a video on the analysis of space truss and space frames using direct stiffness method... i requested u some days bk also... please reply soon
When calculating the member reaction matrix Ar. The moment in the middle M=10 kNm was not included in neither members. was that a mistake? What if there is a force in the middle.
Youssef Cherqaoui no it's not a mistake, Ar is the reaction matrix and no force is to be included in that, the moment of 10kNm has been included in Aj matrix which is a joint load matrix in which all loads on the joints have to be considered. Force in the middle means where exactly please specify joint location or beam location
seelam manohar there is no modifications you can apply it to a continuous beam, by fixed beam do you mean a single span with both ends fixed? I guess such a problem would not be solve as all the rows and columns would be deleted later, for both ends fixed you need to solve it using energy methods like castiglianos theorem or flexibility method or unit load method or moment area method etc
it has to be zero since the joint is getting rotated, as it gets rotated it means it cannot give resistance to the loads hence the combined moment has to be zero at such joint, from stiffness method you get Mba + Mbc = 0 In other methods we do get values of Mba & Mbc but in those methods as well there summation leads to a zero moment. The sum is not wrong. You can check it by solving through any software you want.
DCBA online if you check it by any software it will give you the actual value of the moment at B. The correct way to get BM is by calculating the forces for each member separately
abduallah adi yes it does but what i mentioned in my previous comment is that if you sum up moments at that joint it should give you zero and that is what you get in stiffness method, if you want the value of moment carried by member BA or BC you will have to separate them and find the moment values separately. From stiffness method if a joint is rotated you will get the value of moment as 0 since it cannot resist the rotation.
sir I can understand that you have applied the equilibrium condition at the joint... if the two moments were added together at the joints then it will become zero to statisy the equilibrium condition. but the question is how it doesn't resist the rotation? if we consider the individual moments then it will resist corresponding to the individual span??
+Venkatesh janakiraman if the roller support is provided at the end of the beam means then it will not resist the rotation but if the same is provided as intermediate support then it will behave like partial fixity na. I know that roller support never resist rotation and horizontal translation. kindly clarify the doubt is I am right??
I saw many video lectures but lots of doubts and confusion. I find your lecture crisp and clear. no confusion at all. You r really good at teaching. Thank you!!
I'm a student of bits-pilani...........and honestly u teach much..much better than our bits-pilani faculty...hands down !!!!!
Thank you so much, appreciated.
Your way to teaching is awesome, thanks buddy
Thanks so much, very simple and clear, it help encourage young engineers do not be afraid about beam fem and math"
Sir You are a legend! A whole legend!!
Thank you
thanks man this was so helpful
Nice explanation. But I have doubt whether AC=AJ-AR or AC=AJ+AR as already considered the sign for each force and moment. Pleas clarify.
You are Awesome Man!
Really Helpfull!! Hats off to DCBA.
vikas Dudi thanks a lot bro
Sirr please make more videos on stiffness matrix problems. Thanks a Lot!
Nice elaboration.. Truely super... Please do some videos on other method like conjugate beam method.. Moment area method etc... 😊😊😊
Very good teacher!!! Super helpful
Thank you! Fantastic video! Please keep up the good work
better my class teacher awsm sir
If K x delta = Ac
Then K x delta - Ac should be 0 ?no?why is it R?
Sir,I have watched all the videos but i didn't find any question in which supports are settling.I am facing a problem in that type of questions.please upload the video for that..Thanks sir for the amazing lectures!!
In the final stiffness matrix, put the value of displacement in the displacement Matrix.
Sir , please made videos on ' strain energy method ' this is very helpful for engineering students.
You are the king
Thanks alot
For calculation of Ar1 matrix value of Ra comes out to be 53.34 and Rb as 26.66 your values is different from my values which one is correct pls tell ☺
59.26 , 20.74 are
correct
Ra = 53.34 + 5.926 = 59.26
Rb = 26.66 - 5.926 = 20.74
+- 5.926 = due to the moment
@@thanomm can i know how to get the value of +- 5.926?
@@thanomm 5.926 ?? please tell me
Thanks for sharing your knowledge! Very useful...
Thank you so much for your valuable inputs 😌😌😌😌😌🙏🙏🙏🙏
Sir...I m studying mtevhbin distance...so I don't have any note,book,sir...u r everything for me
Superb explanation 😊😊👏👏
Excellent video on this topic
SALUDOS DESDE MEXICO, ME ASEGURASTE EL 10!
Encantado de poder ayudar, gracias!
Thanks , very helpful and quite easy to understand , I have one doubt...what if all support are fixed instead of roller or pin at B & C, In that case how do we proceed
Your videos are awesome sir..
Excellent explanation...but can u just give the formula for finding members forces separately and thereby the BMD and SFD ?
Good work sir
Thanks alot for ur effort , please do you have a video of frame analysis in the same way ?
Thanks a lot! It was very helpful!
Sir plz solve an overhanging beam using this method..
Sir I want to ask that whether this method is elementary stiffness or system stiffness method?
Elemental stiffness method
Sir if there is some displacement or settlement already given on any joint let say 1.5mm settel on joint B then how we will proceed
TQ for such a good explanation
when you were finding for the member reaction matrix for member 2 @ 18:30 why did you assume that the member is fixed from both sides, you can apply the FEM as FEMbc= WL^2/8 since its a roller ended beam. Because you will be getting a different answer if you're assuming its fixed ended from both sides
Ahmed Ismail while writing those equations you need to consider all supports to be fixed, the fact that it is a roller would be used in Step 7 when you cancel out all what is not required.
So you mean that if i applied the advanced FEM equation for the roller ended part as WL^2/8 it would be wrong when am writing down the Reaction matrix, And its a must to to assume that its always a fixed end even though its not always fixed ended? Thank you sir for your quick response and you have earned your self a new subscriber :)
Ahmed Ismail by writing advanced FEM equation u mean finite element method quation or fixed end moment equations?, that step was reaction step and you need to write the fixed end moments ans reactions generated at each span and for that matte you need to assume every span to be a fixed end span.
DCBA online I mean the fixed end moment equations for a roller/pin ended span like in this example which I was suggesting to use wl^2/8 and assume that it's only fixed from one end which is b when analysing Member 2
Plizz make a video on how to solve truss problem by the help of stiffness matrix method concept..
Why [Ar] is subtracted from [Aj] in calculating combined load matrix.please reply soon.
Well to just simply say, it is the method which has to be followed but if you want an explanation than, there we are dealing with two kinds of matrix one is a load matrix and another one is a reaction matrix, take note that both are opposite in nature to each other and hence if we have to combine them we have to change the sign of reaction matrix i.e. done by subtracting it and hence Ar is subtracted from Aj.
DCBA online Thank you Sir.
GOOD JOB SIR.CAN YOU MAKE A VIDEO FOR STIFFESS METHOD FOR TRUSSES?
Sir, one more problem upload base on stiffness matrix plz as soon as possible ..
So can you provide a means of calculating the wertical (sic) range?
hello please where we not supposed to have 3elements? as where there is a point charge we put a joint there
a big thank you sir
very good!
what if there is a downward settlement in joint B? what will we take the sign of the settlement as? (del b)
Sir plz add vdo on plane truss using member approach
Hi, thank you for the clear explanation, how can I contact you? I have a question in fining weak form from governing equations of the Timoshenko beam, may be you can help me. thank you
DCBA sir flexibility matrix method....mein Jo apne method btaya hai...usse answer match nhi kar rha..
isn't the Ac is the summed up from the Aj and Ar instead?
Thank you very much
is stiffness method and matrix displacement method are the same?
sir please make a video on the analysis of space truss and space frames using direct stiffness method... i requested u some days bk also... please reply soon
Hello, im really sorry but i am not at all getting time to prepare more lectures due to work commitments.
that was heart wrenching
When calculating the member reaction matrix Ar. The moment in the middle M=10 kNm was not included in neither members. was that a mistake? What if there is a force in the middle.
Youssef Cherqaoui no it's not a mistake, Ar is the reaction matrix and no force is to be included in that, the moment of 10kNm has been included in Aj matrix which is a joint load matrix in which all loads on the joints have to be considered. Force in the middle means where exactly please specify joint location or beam location
Thanks alot dude
U FAKIN ROCK MANNN !!
YOU SAVED MY ASS.... THANK YOU !!!!!!!!!!!
sir ye konsi method heee-
1.structural approach
or
2.member approach
???
I have same question please ans?
what happen if there is a hinge?
Thank you sir
Rb is an input or output, 40 kn ?
Sir plz upload stiffness method to solve pin jointed truss
do you have the 2x2 matrix approach and 6x6?
can you explain how to create a one example of matrix mathod in excel sheet.....plz
thanks a lot.......
Sir I applied this procedure for a fixed beam. But I didn't get answer sir. Is there any modifications, for fixed beam problems
seelam manohar there is no modifications you can apply it to a continuous beam, by fixed beam do you mean a single span with both ends fixed? I guess such a problem would not be solve as all the rows and columns would be deleted later, for both ends fixed you need to solve it using energy methods like castiglianos theorem or flexibility method or unit load method or moment area method etc
DCBA online
Sir fixed beam having two spans.and eccentric loading is present on the two spans
Sir how can we analyse beam with crack (v notch)
Why haven't you considered 10 kNm moment at joint B while calculating Ar2
It was included in Aj as a joint load. As you end up assembling Ac from Aj and Ar it would be doubled if you included it in Aj and Ar.
thxxx！！！
sir is there any problem of varying distributed load beam
No, not solved, but the concept will remain same
why you didn't consider upward load 40kn in step:5?
Soumya Kodimyala 40 kN is a joint load and not member load and since step 5 is pertaining to member reaction matrix it shouldn't be considered
thank you
Sir plz make video on column analogy method
Ajay Bhuriya i would surely try to do it in future, currently i wont be getting enough time to invest into it
There's a mistake in the solution. How come MB is zero ?!?!
it has to be zero since the joint is getting rotated, as it gets rotated it means it cannot give resistance to the loads hence the combined moment has to be zero at such joint, from stiffness method you get Mba + Mbc = 0
In other methods we do get values of Mba & Mbc but in those methods as well there summation leads to a zero moment.
The sum is not wrong.
You can check it by solving through any software you want.
DCBA online if you check it by any software it will give you the actual value of the moment at B. The correct way to get BM is by calculating the forces for each member separately
abduallah adi yes it does but what i mentioned in my previous comment is that if you sum up moments at that joint it should give you zero and that is what you get in stiffness method, if you want the value of moment carried by member BA or BC you will have to separate them and find the moment values separately. From stiffness method if a joint is rotated you will get the value of moment as 0 since it cannot resist the rotation.
sir I can understand that you have applied the equilibrium condition at the joint... if the two moments were added together at the joints then it will become zero to statisy the equilibrium condition. but the question is how it doesn't resist the rotation? if we consider the individual moments then it will resist corresponding to the individual span??
+Venkatesh janakiraman if the roller support is provided at the end of the beam means then it will not resist the rotation but if the same is provided as intermediate support then it will behave like partial fixity na. I know that roller support never resist rotation and horizontal translation. kindly clarify the doubt is I am right??
there should be the moment at point B it cannot be zero
pls, can be use this method for all type of beams
saif En yes probably all indeterminate beams
Thank you so much
where is type to link send
This is direct stifdness method not stiffness matrix methid
is there is any difference ?
They are the same
sir plz upload truss sum for this method plz
sir pls make vidios on flexibility method in SA 2
AMRUTA POKHARKAR sure i will.
Sir please send me the notes of matrix method of structure analysis for Mtec structure engg
Prashant.lit@laxmi.edu.in
everything is in matrix form.....😲😲😲
send me link here
th-cam.com/video/Y8sZlECJ6nA/w-d-xo.html
Thanks sir