Algebra 1 Practice - Solving a Proportion (Example 2)

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  • เผยแพร่เมื่อ 30 พ.ค. 2024
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    Solving a proportion involves finding the value of the variable that makes two ratios equal. A proportion is an equation of the form \(\frac{a}{b} = \frac{c}{d}\), where \(a\), \(b\), \(c\), and \(d\) are numbers and \(b\) and \(d\) are not zero. Here’s a detailed guide on solving proportions:
    General Steps:
    1. **Set Up the Proportion**: Write the equation in the form \(\frac{a}{b} = \frac{c}{d}\).
    2. **Cross Multiply**: Multiply the numerator of one ratio by the denominator of the other ratio.
    3. **Solve the Resulting Equation**: Solve the resulting linear equation for the variable.
    4. **Check Your Solution**: Substitute your solution back into the original proportion to ensure both sides are equal.
    Example 1: Simple Proportion
    **Proportion**: \(\frac{x}{4} = \frac{3}{8}\)
    1. **Set Up the Proportion**:
    \[
    \frac{x}{4} = \frac{3}{8}
    \]
    2. **Cross Multiply**:
    \[
    x \cdot 8 = 4 \cdot 3
    \]
    Simplifies to:
    \[
    8x = 12
    \]
    3. **Solve the Resulting Equation**:
    \[
    x = \frac{12}{8}
    \]
    Simplifies to:
    \[
    x = \frac{3}{2} \quad \text{or } 1.5
    \]
    4. **Check Your Solution**:
    Substitute \(x = 1.5\) back into the original proportion:
    \[
    \frac{1.5}{4} = \frac{3}{8}
    \]
    Simplifies to:
    \[
    0.375 = 0.375 \quad \text{(True, so the solution is correct)}
    \]
    Example 2: Proportion with a Variable in the Denominator
    **Proportion**: \(\frac{5}{x} = \frac{10}{6}\)
    1. **Set Up the Proportion**:
    \[
    \frac{5}{x} = \frac{10}{6}
    \]
    2. **Cross Multiply**:
    \[
    5 \cdot 6 = 10 \cdot x
    \]
    Simplifies to:
    \[
    30 = 10x
    \]
    3. **Solve the Resulting Equation**:
    \[
    x = \frac{30}{10}
    \]
    Simplifies to:
    \[
    x = 3
    \]
    4. **Check Your Solution**:
    Substitute \(x = 3\) back into the original proportion:
    \[
    \frac{5}{3} = \frac{10}{6}
    \]
    Simplifies to:
    \[
    \frac{5}{3} = \frac{5}{3} \quad \text{(True, so the solution is correct)}
    \]
    Example 3: Proportion Involving Variables on Both Sides
    **Proportion**: \(\frac{2x + 1}{5} = \frac{3x - 2}{4}\)
    1. **Set Up the Proportion**:
    \[
    \frac{2x + 1}{5} = \frac{3x - 2}{4}
    \]
    2. **Cross Multiply**:
    \[
    (2x + 1) \cdot 4 = (3x - 2) \cdot 5
    \]
    Simplifies to:
    \[
    8x + 4 = 15x - 10
    \]
    3. **Solve the Resulting Equation**:
    - Subtract \(8x\) from both sides:
    \[
    4 = 7x - 10
    \]
    - Add 10 to both sides:
    \[
    14 = 7x
    \]
    - Divide both sides by 7:
    \[
    x = 2
    \]
    4. **Check Your Solution**:
    Substitute \(x = 2\) back into the original proportion:
    \[
    \frac{2(2) + 1}{5} = \frac{3(2) - 2}{4}
    \]
    Simplifies to:
    \[
    \frac{4 + 1}{5} = \frac{6 - 2}{4}
    \]
    \[
    \frac{5}{5} = \frac{4}{4}
    \]
    \[
    1 = 1 \quad \text{(True, so the solution is correct)}
    \]
    Key Points:
    - **Cross Multiplication**: Multiply diagonally across the equal sign to create a linear equation.
    - **Simplify and Solve**: After cross-multiplying, solve the resulting equation as you would any linear equation.
    - **Verification**: Always check your solution by substituting it back into the original proportion to ensure both sides are equal.
    By following these steps, you can solve proportions accurately and systematically.
    I have many informative videos for Pre-Algebra, Algebra 1, Algebra 2, Geometry, Pre-Calculus, and Calculus. Please check it out:
    / nickperich
    Nick Perich
    Norristown Area High School
    Norristown Area School District
    Norristown, Pa
    #math #algebra #algebra2 #maths

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