Bending Moment Diagrams

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  • เผยแพร่เมื่อ 2 ธ.ค. 2024

ความคิดเห็น • 30

  • @Raghavcric
    @Raghavcric 12 ปีที่แล้ว

    Thank you very much, really helpful at the exam time. You read through so many books and you dont get it, someone explains it to you and it just strikes so thanks once again =)

  • @crx1299
    @crx1299 12 ปีที่แล้ว

    Assuming that you are a teacher, I must say your students are very lucky. These subjects seemed so difficult to me back when I was learning them.

  • @Mostafa20268
    @Mostafa20268 12 ปีที่แล้ว

    thank you sir..I am here to refresh what i study in 80s..Civil Engineer.

  • @WiperTF2
    @WiperTF2 8 ปีที่แล้ว +7

    4:30 Why are the 1050N included when this FBD only deals with x from 2 to 4.8? And why are the 750N on the right NOT included?

  • @martingillie6321
    @martingillie6321 10 ปีที่แล้ว

    Very nice. One small slip in the first example. The gradient of the BMD has units N (not N/m). It is actually useful note this as the relationship dM/dx=V allows for quickly drawing SFDs if you have a BMD.

  • @damaster720
    @damaster720 12 ปีที่แล้ว +1

    2m is the distance between the first and second force, 4.8m is the length of the beam.

  • @MUSTASCH1O
    @MUSTASCH1O 11 ปีที่แล้ว

    As far as I understand he is saying it is the moment caused by the 1050 N force. If you visualise it you can see the 1050 N force would produce an anticlockwise moment.

  • @hardabrahmadave5865
    @hardabrahmadave5865 11 ปีที่แล้ว +1

    while considering the free body diagram....dont we consider normal reaction due to gravity?

  • @dustz33
    @dustz33 10 ปีที่แล้ว

    Sir, please transfer to Imperial College London. Your teaching skills and excellent but concise explanations make these videos amazingly enjoyable and efficient.

  • @MrKamran425
    @MrKamran425 12 ปีที่แล้ว

    Darrryyyyyy you need to release some more examples pleaseeeee :D:D:d And can you also show you sign conventions as well please. and do a lot more examplessss. I am definitely referring you to my friends :D

  • @LucaCappelletti94
    @LucaCappelletti94 7 ปีที่แล้ว

    How do we proceed with crossed or angled bars?
    Thanks for the amazing explanation!

  • @ArcanePhalanx
    @ArcanePhalanx 9 ปีที่แล้ว

    Hey, I was just wondering if you could use this to work out the flex in a beam i.e. the radius of a bend. Also, why not take moments about the 2952N force?

  • @hellowill
    @hellowill 9 ปีที่แล้ว

    what do I do when there is a moment on the beam? (my problem has a 15KNm anti clockwise moment placed 13m from the start of the beam.)

  • @sntfrancisco31
    @sntfrancisco31 12 ปีที่แล้ว +1

    are the distances 2m and 4.8 m the distances between the forces?

  • @purplecow265
    @purplecow265 11 ปีที่แล้ว

    How would I integrate the bending moment of a load that is not uniformly straight, like a line or other function?

  • @11baroda
    @11baroda 11 ปีที่แล้ว +4

    Holy shit dude this was fken amazing
    my teacher doesnt teach shit and we have exams in 2 days
    this was brilliant and i actually understand shit now
    thnx man

  • @Madvilllain
    @Madvilllain 11 ปีที่แล้ว

    why did you not include the shear in your FBD for the distributed load?

  • @asharXXIII
    @asharXXIII 11 ปีที่แล้ว

    this was excellent thankyou so much :D !

  • @vivekkumar151
    @vivekkumar151 9 ปีที่แล้ว

    VERY NICE VIDEO.sir,please upload a video about bending moment diagram of cantilever beam.I am struggling with it.Your help will be appreciated a lot.

  • @Paharimaanu
    @Paharimaanu 9 ปีที่แล้ว

    please explain how u draw Bending moment diagram frm equations.

  • @mohamed1313mad
    @mohamed1313mad 12 ปีที่แล้ว

    thnx .......production engineer

  • @53dexter
    @53dexter 12 ปีที่แล้ว

    wait--why did you neglect the 750N?

  • @warrensze321
    @warrensze321 10 ปีที่แล้ว

    thank you very much!

  • @nutterhm
    @nutterhm 10 ปีที่แล้ว

    where did you get 5904 Nm ?

  • @stn4256
    @stn4256 12 ปีที่แล้ว

    why u r taking the forces on only side. 750N was also there. And why did you multiply 1800 with (X-2), instead of X.

  • @CJMilsey
    @CJMilsey 11 ปีที่แล้ว

    If you assume it's weightless then no.