Scroll up and hit that 👍 button if you found this video helpful! The full circuit analysis playlist is here: th-cam.com/play/PLOAuB8dR35ocf9Typ1iX9NRmX0V04UYfQ.html
Incredible summary of the topic. This isn't a super common strategy in Electrical Engineering and Circuits classes, so I'm glad I came across your video making it simple and easy to digest.
Thank you so much! There’s a little typo tho: in the last calculations, you put 1 instead of 5, since you multiplied (Vb +1) by 5. Besides that it’s all good, this really helped me to understand 1 hour of class in only 6 mins, thanks!
you are just a life savior I'm studying my final exam and i couldn't figure out what to do and this just helped me a lot !! thanks man i really appreciate people like you !! Wish me luck in my finals !! ♥
Thank you, well explained! I followed your Circuits playlist and it helped me understanding concepts a lot. I need to practice questions though, now its on me:)
3:10 anyone who is confused how did he get the supernode equation when he said "Va is just 1V higher than Vb" and wants some clear explanation here it is based on my understanding: Va is facing the + sign of the battery which is 1V and Vb is facing the - sign of the battery which is 0V. I don't know if this is true but this is how I undestand it.
Hello, great video but i have a question, which direction do u think the current flows at the 1V power source? Based on my calculation. the current flows from node Vb to node Va. However, node Va has higher potential than node Vb , so which one is correct ?
Hey, all of the hardware and software that I use to make the videos is here: engineer4free.com/tools The drawing program in this video is called Sketchbook
@@Engineer4Free I get two different answers one when I consider all 4 outgoing currents ,and another when I consider two incoming and two outgoing currents which one should I consider
Hi, what if the polarity at voltage source between Va and Vb change? is the equation still same like Va=Vb+1 or it change to Vb=Va+1..What if the polarity at 2v source change? is the current flow at i5 change too?
For the first question: Yes, the equation would change to "Vb=Va+1". For the second question: It doesn't matter which direction you determine the current at first as a reference. If you determine the direction otherwise, you would simply get the same value but with opposite sign. So the answer to your question is that the voltage sources polarity doesn't affect your selection of current direction.
I have a similar problem but in my case the 2nd voltage source (2v) is upside down......In this case the ground is connected to negative terminal but in mine the voltage sources are inverted . 1st one has negative side facing down (like in this case ) but the 2v source has the positive side facing downwards (unlike this case where both negative sides are facing downwards) . In that case what do I do?
To @The Android Minimalist: no difficulty here. In all the equations in this vid where you have (2 V) you should write (-2 V) and continue solving the problem. Just do the maths. Most likely, you will get some of the currents (here, probably i5 and i4) with negative values. This will mean that this/these current flow in opposite direction. No hassle at all. In this kind of problems, you may always arbitrarily assume certain (or the opposite) direction of current flow. Then, be consistent with drawing voltage arrows and writing the equations. Once the equations are solved, you will see if your gut feeling of how the current flows are oriented was correct. Regardless of how good you are at guessing the current directions at the beginning, the end result will always be the same.
@Pau Gasolina: no it does NOT matter. If the current flows in opposite direction to what you assumed, the current value will be negative. What is extremely important, be consistent with the current directions and voltage drops when writing the equations. Once the equations are well written, the solution will be correct (sometimes with negative current, but correct). Courage!
Ah, there is a 1V voltage source between (points) A and B. The way it's oriented is such that the left side is 1V higher than the right side, and because Va is the left side and Vb is the right side, it means that Va is 1 volt higher than Vb, or mathematically its just, Va = Vb +1, with each term being in units of volts.
Scroll up and hit that 👍 button if you found this video helpful!
The full circuit analysis playlist is here: th-cam.com/play/PLOAuB8dR35ocf9Typ1iX9NRmX0V04UYfQ.html
Incredible summary of the topic. This isn't a super common strategy in Electrical Engineering and Circuits classes, so I'm glad I came across your video making it simple and easy to digest.
I wish I could like twice, this video helped alot...thank you
Thanks Delroy! Glad I could help 😁
Thank you so much! There’s a little typo tho: in the last calculations, you put 1 instead of 5, since you multiplied (Vb +1) by 5. Besides that it’s all good, this really helped me to understand 1 hour of class in only 6 mins, thanks!
P
@@mridul7480 P
@@mrsandman4769 P
you are just a life savior I'm studying my final exam and i couldn't figure out what to do and this just helped me a lot !! thanks man i really appreciate people like you !!
Wish me luck in my finals !! ♥
How'd you go??
@@konstantinosrope-maker1228 Amazing got 35 out of 40 thanks to this guy's channel !
@@-b6h-586 congratulations man! I hope to score highly too!
@@konstantinosrope-maker1228 you will score high bro just focus and practice problems more than anything else !!
Best video on supernode analysis!
Thank you, well explained! I followed your Circuits playlist and it helped me understanding concepts a lot. I need to practice questions though, now its on me:)
Thanks a lot, a big thumbs up from Sri Lanka👍😁
Brilliant video! Make me much clear about the concepts. Thanks a lot.
Im back, I have not yet escaped the need for your high quality videos lol
3:10 anyone who is confused how did he get the supernode equation when he said "Va is just 1V higher than Vb" and wants some clear explanation here it is based on my understanding: Va is facing the + sign of the battery which is 1V and Vb is facing the - sign of the battery which is 0V. I don't know if this is true but this is how I undestand it.
basically the potential difference between the nodes V2 and V1 is 1V
@@hamkaboo543how we can find the value 1 volt in supernode
this is so clear and concise! thanks
i understand very well thank you so much from Korea~
The video was concise and helpful. Keep up the good work.
Great have a like from Egypt
Thank you so much for the explanation. Very easy to understand and helpful
this video is very helpful for the students who study one night before exam 😅.
you explained very well 🥰
Haha, thanks! 😁
5:38 how did you go from 21 to 16????, nevermind; it comes from subtractng 5(+1) from 21.
Good video and nice soothing voice too
Haha thank you 😁
You're a genius. Thanks so much for making it easy to understand. 🙂
I couldn^'t get how did you find out the second supernode equation? is it a constant
Man, that was crazy 🔥
sorry can i ask you at 5:38, why 5(Vb+1) is not 5Vb +5 ?
it is adjusted in the next line, hence the 16 and not 21. I believe he jus messed up the arithmetic.
Hello, great video but i have a question, which direction do u think the current flows at the 1V power source? Based on my calculation. the current flows from node Vb to node Va. However, node Va has higher potential than node Vb , so which one is correct ?
very helpful & nicely explained .. thnx man
Glad you liked it =)
what's the name of program you are using in this videos to explain all this?
x2
@@vicentechavez3662 ?
Hey, all of the hardware and software that I use to make the videos is here: engineer4free.com/tools The drawing program in this video is called Sketchbook
In case one or all power sources has internal resistance, how can we solve the problem?
you are so amazing, thank you so much!
Glad it helped!!! =)
@@Engineer4Free I get two different answers one when I consider all 4 outgoing currents ,and another when I consider two incoming and two outgoing currents which one should I consider
how did you know that Va is at a higher potential then Vb? im confused on this part as I dont see the polarity
His voltage source flows from left-to-right since the positive end is on the left and vice-versa, so Va must be greater than Vb by 1V.
Longer line in the battery symbol indicates the higher potential side of the battery or voltage source.
Hi, what if the polarity at voltage source between Va and Vb change? is the equation still same like Va=Vb+1 or it change to Vb=Va+1..What if the polarity at 2v source change? is the current flow at i5 change too?
For the first question: Yes, the equation would change to "Vb=Va+1".
For the second question: It doesn't matter which direction you determine the current at first as a reference. If you determine the direction otherwise, you would simply get the same value but with opposite sign. So the answer to your question is that the voltage sources polarity doesn't affect your selection of current direction.
How do you know that the voltage at A is larger than at B?
thanks this is really helpful
I have a similar problem but in my case the 2nd voltage source (2v) is upside down......In this case the ground is connected to negative terminal but in mine the voltage sources are inverted . 1st one has negative side facing down (like in this case ) but the 2v source has the positive side facing downwards (unlike this case where both negative sides are facing downwards) . In that case what do I do?
To @The Android Minimalist: no difficulty here. In all the equations in this vid where you have (2 V) you should write (-2 V) and continue solving the problem. Just do the maths. Most likely, you will get some of the currents (here, probably i5 and i4) with negative values. This will mean that this/these current flow in opposite direction. No hassle at all. In this kind of problems, you may always arbitrarily assume certain (or the opposite) direction of current flow. Then, be consistent with drawing voltage arrows and writing the equations. Once the equations are solved, you will see if your gut feeling of how the current flows are oriented was correct. Regardless of how good you are at guessing the current directions at the beginning, the end result will always be the same.
Very good 🔥
does it matter in which direction i put the current flowing out of the voltage sources?
@Pau Gasolina: no it does NOT matter. If the current flows in opposite direction to what you assumed, the current value will be negative. What is extremely important, be consistent with the current directions and voltage drops when writing the equations. Once the equations are well written, the solution will be correct (sometimes with negative current, but correct). Courage!
good information
Glad to hear it! =)
Thanks broski
i am confused with how you got VA=VB+1
Ah, there is a 1V voltage source between (points) A and B. The way it's oriented is such that the left side is 1V higher than the right side, and because Va is the left side and Vb is the right side, it means that Va is 1 volt higher than Vb, or mathematically its just, Va = Vb +1, with each term being in units of volts.
Where does the voltage equation come from?
Ur the best. New sub ;)
I believe you made a mistake when you expanded 5(VB+1) into 5VB + 1... It should've been 5VB + 5
how did you get 16 = 14 Vb? im still new to this and im so confused
I am also confused about that part, have you figured it out?
He distributed 5. Hence 21-5= 16
And 9Vb +5Vb
What if there is a voltage source between Va and Vo(0 volts)
transfer it to current source
amazinnggggggg!!!!!!!!!!!!!!!!
thanks a lot
Good morning
☕️
what if there is also a resistance between Va and Vb
then it is not a supernode
Great explanation but the asmr-ey sound made me turn the audio off
thx
np
👍
👌
OMG tf that easy???/ srsly???
why my lecturer teach nothing
☺️