Solubility Curves Explained

[@jesepiorlando2836]

Im not exaggerating when I say my chemistry teacher won't teach me, so thanks for the video.

[@hunterelsarelli2686]

That’s most teachers these days

[@dogestep64]

American education system be like

[@Djsjnsnsnsns]

This helped me pass my chemistry test. Thanks for the help.

[@ChemAcademy]

Glad it helped!

[@daniellecarbajal3732]

Your videos just get better and better! I am your biggest fan! Thank you Chem Academy!!! :)

[@stb96573]

Thanks so much, so much better than my teacher

[@ChemAcademy]

New video on Solubility Curves. SUBSCRIBE to my TH-cam channel if you like it.

[@andrewteh8594]

U are the greatest man to live

[@rmsarchive]

THANK THANK YOU SO MUCH FOR CREATING THIS VIDEO!!!!!!!

[@brendaelizondo4782]

Thank you!! I wish you were my teacher. My teacher goes super fast, you made this so easy!

[@romeledeinbarboza4-3]

Very Helpful. Thanks for the Video

[@zackt1480]

thank you too much i have a test today

[@sethsteiner1]

Same

[@katherinedemetroulis9781]

FREAKING LEGEND YESSS NOW I CAN WRITE THE HONORS PART FOR MY TEST THANK YOU SO MUCH :)

[@Moonokami_KR]

CORONAVIRUS BRING ME HERE!!!
ANYONE 2020😂😂😂???

[@kyleroby9749]

same

[@nunyaaa1bidness233]

Moon Wolf same🤣

[@danismom7182]

same moon wolf same

[@keypo790]

It's been 2 years already d4mn :(

[@naghamlvly6306]

wow, well understood thank you very much for the super chem teacher well done.

[@meatsandwitch3141]

Learnt a lot thx

[@baileywallman1547]

You should watch some grammar videos next 🤡

[@kachicelestine9659]

Cool, Thank you sir for such a comprehensive explanation.

[@silindokuhlenogaga1494]

This video is very helpful.Thank you guys

[@alyssaelmore5246]

This helped a lot! Thanks!! Happy Thanksgiving 🦃🍁

[@ayoshawty2599]

Thank you for this video I have a test Tomorrow and this really help sense i was confused on this topic!

[@ComandaKronikk]

Thanks man u are a legend!

[@azourisuarez4040]

Thank u sooooooooo much cause I was not understanding how the saturated, unsaturated n supersaturated work

[@dechendorji7755]

This really really helped me do my assignment. Thankyou for the video sir

[@markwalusimbi2278]

This video was amazing! Thanks for the help!

[@raylynbarnes7013]

Thank you SO MUCH!!!!!!!!!!

[@skullesports805]

Thanks alot sir helped alot 😍😇

[@himanshupatel5458]

wonderful

[@9885040370]

why cerium sulphate solubility decreases with increase in temperature

[@baileywallman1547]

It is a gas-liquid not a liquid-liquid or solid-liquid so it has to have a decrease in temp to increase solubility 😊

[@niayamcintosh5416]

Life saver

[@DMRVR]

So let's say the solution is over saturated by 22 grams. Could you also add 22 mL of water to make it saturated?

[@jharyncraig4856]

THANK YOU SO MUCH!!

[@SaraAli-dx8kd]

Thank you!!

[@archaicStargazer]

I am still having trouble on solubility in 50g. Could you please elaborate on that?

[@archaicStargazer]

*mL

[@ChemAcademy]

jake jensen If you only have 50mL of water which is half of the 100mL of water that is on the Y axis then you will need to cut the solubility at 100mL in half. For example if 30 grams of a salt are soluble per 100 mL of water at a given temp. then 15 grams of that salt will be soluble in 50mL of water. If you had 200mL of water then 60 grams of the salt would be soluble. Does that make sense?

[@archaicStargazer]

Yes. Thank you.

[@davidgamble4893]

The symbol for cesium is Cs not Ce. The compound containig cerium is cerium (III) sulfate.

[@IceCream-uw5ts]

Thank you 💖

[@JJ-cc8cf]

Thank u so much : )

[@markomarosevic5240]

Thank you sir :D

[@khaloodi685]

thank you

[@sk8terwang831]

corona :(

[@zacharyjones-lehfaculty8806]

It is not true that gram amounts above the curve are supersaturated. They are simply saturated. The more solid that is dissolved beyond the saturation point DOES NOT change the concentration of the solution and therefore, despite more solids on the bottom, the concentration of the solution is still simply - saturated. A supersaturated solution is a rare circumstance where a heated solution is saturated and allowed to cool so that more solids are dissolved than would normally remain in solution at that cooler temp. So in fact, a supersaturated solution will appear to be completely dissolved with no cloudiness or solids visible. But any agitation will quickly precipitate those solids out. Please stop teaching people that gram amounts above the line are supersaturated. They are not.

[@lttrunks7866]

I have a test right now

[@heatherross9126]

Is it just me or does this guy sound a bit like technoblade??

[@dogestep64]

Woah he kinda does

[@alishan-cb1vk]

video se pehlay add bhoot boring......

[@hunterelsarelli2686]

Play fortnite

[@PhatL3210]

No

[@heatherross9126]

N-no

[@NursingwithDee472]

Thank you

[@8-theotokoscholomigueldelr287]

Thank you