You see, some teachers know what they’re doing. My teacher sent our class to this video instead of actually teaching us... Still learned more than usual
sciencepost what my teacher took 2 weeks to explain, you just did in 14:14 minutes and i completely understand it. Thanks for the help because I got my chemistry final tomorrow.
Thank you so much, my teacher showed me how to do and gave me homework and i had no idea but after this video I know how to do it thanks for this video.
I missed this day in class! Thanks for the help!! However, I was wondering what happens if your temp and your amount of water don't line up? We are using the same graph you were toward the end of this vid. My chem teacher gave the problem: ...determine how many grams of KClO3 needs to dissilve in 50 grams of water in order to have a saturated solution at 80 degrees C.
KCIO3 needs 10 more grams to have a saturated solution at 80 degrees C. I got this by lining up the compound on the x-axis and y-axis. At 80 degrees C. and 40 grams of solute they meet. However, the question is asking at 50 degrees C. so to get from 40 -> 50 you would set up the equation: 40 + x = 50 Your end result would be x = 10, thus you need 10 more grams of solute.
I know this video was posted very long ago but I still want to express how grateful I am for this video’s existence. I have a test tomorrow on this concept and I went from not understanding any of this to understanding almost completely! this is a lot more straightforward than how my teacher explained it, so thank you so much for taking time out of your day to explain this! it helped a lot!!!
Okay can someone tell me how you would figure those same problems but only if you didn’t have 100 grams of whatever is being dissolved. I’m my case it’s 79 grams of KNO3 and I have to know of it would be saturated, super saturated, or unsaturated.
Btw, im not sure how legit the graphs are, but is it saying when water is 0 degrees Celsius (frozen into ice), it can still dissolve 175 grams of sugar???
this was a great video. He taught me more in 14 minutes than my teacher does in an hour
NO FRRR
I was so confused at first, but this video made it crystal clear. Like if you agree. Thanks for putting this video up for struggling students
Chrystal clear, is that because crystals are left over🤣
100000000 subscribers without making a video STOP
You are my hero. My Chemistry teacher said I should just 'google it' because apparently I'm too 'daft' to understand. So thanks for helping.
Your teacher actually said that 😮
Shocking
You see, some teachers know what they’re doing. My teacher sent our class to this video instead of actually teaching us... Still learned more than usual
I was so stressed because I didn't know how to determine solubility curve but when I watched this video I finally understand the solubility curves.
YOU PEOPLE SAVE MY LIFE (well academic life)
thannnnkkkk youuuuu i have had sooo much trouble understanding these. this help me 1000000%
you saved my life
Can you please replace my braindead chemistry teacher, PLEASE?!?!?!?!?!?!?!?!?!?
Lol. Von, this is not easy to teach. It may be easier on video, less distractions :) Be awesome!
sciencepost what my teacher took 2 weeks to explain, you just did in 14:14 minutes and i completely understand it. Thanks for the help because I got my chemistry final tomorrow.
Hey bro, go BIG. That means STUDY. I can't stress that enough. Put the time into this Final and you will not regret it. Be awesome! Go Big!
sciencepost Thanks, that just me want you as my chem teacher even more. Wish my teacher said stuff like that.
Lol. Keep rocking the vids bro, and perhaps you'll be the chem teacher one day too. Be awesome bro! I look forward to hearing from you again.
Thank soooo you. You have made me understand things my teacher never could 👏🏾👍🏾
Thanks a lot! I was finding a bit difficult understanding this, but I get it now because of you! Thanks a lot again, you really helped me! =D
Wow you are an amazing teacher! Thanks!!
Thank you so much! i hope you have a great day and a great life
This video is nice and clear. My chemistry teacher does not teach us anything so I appreciate the video.
Thank you so much, my teacher showed me how to do and gave me homework and i had no idea but after this video I know how to do it thanks for this video.
"So, if you're a fish, and you're swimming around that lake.." Oh wow😂😂
Kym, thanks for tuning in. So happy it helped you. Keep up the the studies.
My chemistry teacher gave HW on solubility which she hasn't even taught so thanks for saving my chem grade
this was very helpfull you are able to "dumb down" something that i was unable to get thank you
Vas, thanks for the feedback. Sooooo stoked they are helping you.
Thanks, a lot. This video gives a clear understanding of the solubility curve.
Wow! You just saved me I take my Final today in chemistry and physics! I love your teaching, you are amazing!
THANKS SO MUCH MY CHEMISTRY TEACHERS A THICK HEAD AND IM ALWAYS ASKING QUESTIONS THXS :)
Thank you. Feel much better for my solutions test tomorrow.
Go big on the test!
Very helpful. Thank you for posting this video. I now understand my homework better
Very helpful!! You made everything so simple.
That's great to hear. Now it's time to ace your test. Be awesome!
Very USEFULL THANK YOU SO MUCH!
I was really struggling with this, but this video really made it click. Thank you!
I am not going to fail my Chem test today!!!! :D
eternally grateful for this video.
Thanks for watching Oneday04. I'm stoked you learned it. Tune back in again if you need help in other areas of chem. Peace..
Thanks! I have my exams tomorrow and you explained this very clearly.
Thank you so much! This helped a lot!
Very Helpful
Thank you so much .
You save my GCCEs
this is SOOOOOOOOOOOOOO easy THANK YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!
it all makes sense now. THANK YOU.
If only all teachers were like this..
You are welcome!
You're awesome. Thank you!
thanks a lot this video has really benefited me :)
your videos are really helpful, and I love how your voice is so chill!
you sound like a total bro
Thanks for the sweet feedback amigo. Not sure if I'm that chill, because I get pretty amped up to teach. Best wishes learning. Keep being awesome!
thanks for diss video it help mi a lot
I missed this day in class! Thanks for the help!! However, I was wondering what happens if your temp and your amount of water don't line up? We are using the same graph you were toward the end of this vid. My chem teacher gave the problem:
...determine how many grams of KClO3 needs to dissilve in 50 grams of water in order to have a saturated solution at 80 degrees C.
KCIO3 needs 10 more grams to have a saturated solution at 80 degrees C. I got this by lining up the compound on the x-axis and y-axis. At 80 degrees C. and 40 grams of solute they meet. However, the question is asking at 50 degrees C. so to get from 40 -> 50 you would set up the equation:
40 + x = 50
Your end result would be x = 10, thus you need 10 more grams of solute.
Thank you!!!!
Thank you so much for this video. It is so helpful.
Dude i have a quiz on this tmrw and you literally just cleared my brain if you wanna be my chemistry teacher let me know
Great video for chemistry students.
Thanks very much it's was very helpful
Thanks you're a lifesaver!!!
this was actually so good
THANKS MAN!!!!!!!!! You, sir, are AWSOME
Wow, I thought you were Awesomeness! Keep up the sweet effort. Do your best! Be Awesome!
Thank yu sir! Now I can do my homework :D
thank you so much! i can pass my test now :D
@Celeste Pineda 4years later.. did u pass it
I have a test on monday
Sarah aljamal samee
Exam
I have a test in 2 minutes 😂😂
Excellent video. Super helpful bro. Subscribed
Thank you! That helped!
This video helped me so much. Thank you!!!
U r a life saver
I know this video was posted very long ago but I still want to express how grateful I am for this video’s existence. I have a test tomorrow on this concept and I went from not understanding any of this to understanding almost completely! this is a lot more straightforward than how my teacher explained it, so thank you so much for taking time out of your day to explain this! it helped a lot!!!
So stoked it worked for you! Tune back again.
Subtitles would be awesome if you could start putting them on your videos.
You are welcome dude. Please share it if it helped. Peace out.
does a solubility curve of anhydrous solid always necessarily be continuous ?
thank you so much. I finally understand 😊
clear an simple, thanks!
Yeah! So cool to hear that the video worked for you. Be Awesome!
why he sound like Patton Sanders-
(not in a bad way of course your voice is great)
Thank you now I will share with my students!
Eduardo Miranda Thanks bro. I hope that it helps them. Best wishes.
i love your vids
thank you so much
i like how at 4:44 the amounts of solution are different. one is 33ml and one is 35ml.
Thanks for you're help.
thanks a lot you have helped me a lot
thanks for help
Thank you
thank you very much!
Okay can someone tell me how you would figure those same problems but only if you didn’t have 100 grams of whatever is being dissolved. I’m my case it’s 79 grams of KNO3 and I have to know of it would be saturated, super saturated, or unsaturated.
Thanks! so helpful
What if you were asked to a solution which is the least saturated at 20 degrees celsius with 20g of solute dissolved in 100g of water
so helpful!! thank you!
Thank you so much!!!
Thanks helped on Hw
Thank's this really helped
lets go ms.Nathan
great vid!!
Thanks this helped a lot! :)))
So cool to hear. Thanks!
Well did
Great Video!! =]
Thanks for tuning in and leaving feedback! Keep up the good work!
@11:01 Cerium Sulfate, not Cesium Sulfate.
amazing video thanks alot
Btw, im not sure how legit the graphs are, but is it saying when water is 0 degrees Celsius (frozen into ice), it can still dissolve 175 grams of sugar???
you're awesome
ty
bro saving my life i get it now😭
You didn't do any of the question my grade 11 teacher needs, but i understand a little better now
thank you help me
can u put in the file u are using thx
Who just saw this in ms. Ganesh
Goat
Bruh
Is tequila saturated solution or unsaturated?