at 8:36 while writing the shear equation the units are not matching ....you took 4kn downwards correct....V to be downward correct but the load by the triangle is not taken you took it as like a moment ....can you correct me if i m wrong or else clear my doubt .......(1/2)4kn/m*x2 its moment ....my solving it we get unit as KN-m which is moment not force
Well you have mixed one thing the (4/3*X having unit KN/m) and when you convert triangular load in to Point load (1/2 * (4/3*X unit KN/m)* (x unit m) will have Unit KN which is the unit of force. I hope it will be clear to you now.....
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@@engradnanrasheedmechanical ok sir Insha Allah
@@engradnanrasheedmechanical ok sir Insha Allah
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at 8:36 while writing the shear equation the units are not matching ....you took 4kn downwards correct....V to be downward correct but the load by the triangle is not taken you took it as like a moment ....can you correct me if i m wrong or else clear my doubt .......(1/2)4kn/m*x2 its moment ....my solving it we get unit as KN-m which is moment not force
Well you have mixed one thing the (4/3*X having unit KN/m) and when you convert triangular load in to Point load (1/2 * (4/3*X unit KN/m)* (x unit m) will have Unit KN which is the unit of force. I hope it will be clear to you now.....