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Engr. Adnan Rasheed Mechanical
Pakistan
เข้าร่วมเมื่อ 26 ก.พ. 2021
Free education is the right of all students
IN MY CHANNEL , YOU WILL FIND MECHANICAL ENGINEERING'S SUBJECT REALTED VIDEOS WHERE YOU CAN CLEAR YOUR CONCEPTS.
IN MY CHANNEL , YOU WILL FIND MECHANICAL ENGINEERING'S SUBJECT REALTED VIDEOS WHERE YOU CAN CLEAR YOUR CONCEPTS.
Determine to nearest 1/4 in required diameters of steel pin | Example 1.12 | Mechanics of material
The control arm is subjected to the loading shown in Fig. 1-25 a . Determine to the nearest 1/4 in. the required diameters of the steel pins at A and C if the allowable shear stress for the steel is tallow = 8 ksi.
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Determine the average compressive stress along AB and BC | Example 1.11 | Mechanics of materials
มุมมอง 11114 ชั่วโมงที่ผ่านมา
The inclined member in Fig. 1-23 a is subjected to a compressive force of 600 lb. Determine the average compressive stress along the smooth areas of contact defined by AB and BC , and the average shear stress along the horizontal plane defined by DB .
Determine average shear stress along shear planes a - a | Example 1.10 | Mechanics of materials RC
มุมมอง 135วันที่ผ่านมา
If the wood joint in Fig. 1-22 a has a width of 150 mm, determine the average shear stress developed along shear planes a - a and b - b . For each plane, represent the state of stress on an element of the material. Dear Viewer You can find more videos in the link given below to learn more Theory Video Lecture of Mechanics of Materials by Beer & Johnston th-cam.com/play/PLuj5YwfYIVm9GBcC6S4-ZgHS...
Determine the average shear stress in pin A & B | Example 1.9 | Mechanics of Materials RC Hibbeler
มุมมอง 18514 วันที่ผ่านมา
Example 1.9 Determine the average shear stress in the 20-mm-diameter pin at A and the 30-mm-diameter pin at B that support the beam in Fig.1-21 a . Dear Viewer You can find more videos in the link given below to learn more Theory Video Lecture of Mechanics of Materials by Beer & Johnston th-cam.com/play/PLuj5YwfYIVm9GBcC6S4-ZgHS1szlF7s1Y.html 289 Problem solutions of all chapter of Mechanics of...
Determine normal stress at points B and C | Example 6.17 | Bending | Mechanics of materials RC Hib
มุมมอง 25621 วันที่ผ่านมา
A composite beam is made of wood an reinforced with a steel strap located on its bottom side. It has the cross-sectional area shown in F i g. - 3 8 a . If the beam is subjected to a bending moment of M=2 KN.m , determine the normal stress at points B a n d C. Ta k e Ew = 12 GPa and Est = 200 GPa. Dear Viewer You can find more videos in the link given below to learn more Theory Video Lecture of ...
Determine shear flow at B & B' that must be resisted by glue | Example 7.4 | Mechanics of Materials
มุมมอง 18821 วันที่ผ่านมา
The beam is constructed from three boards glued together as shown in Fig. 7-15 a . If it is subjected to a shear of V = 850 kN, determine the shear flow at B and B that must be resisted by the glue. Dear Viewer You can find more videos in the link given below to learn more Theory Video Lecture of Mechanics of Materials by Beer & Johnston th-cam.com/play/PLuj5YwfYIVm9GBcC6S4-ZgHS1szlF7s1Y.html 2...
Determine maximum shear stress in glue to hold the boards | Example 7.1 | Mechanics of materials
มุมมอง 50521 วันที่ผ่านมา
The beam shown in Fig. 7-9a is made from two boards. Determine the maximum shear stress in the glue necessary to hold the boards together along the seam where they are joined. Dear Viewer You can find more videos in the link given below to learn more Theory Video Lecture of Mechanics of Materials by Beer & Johnston th-cam.com/play/PLuj5YwfYIVm9GBcC6S4-ZgHS1szlF7s1Y.html 299 Problem solutions of...
Example 6.14 | Determine maximum normal stress in member for both cases | Mechanics of Materials
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Example 6.14 The member having a rectangular cross section, Fig. 6- 2 8 a , is designed to resist a moment of 40 N # m. In order to increase its strength and rigidity, it is proposed that two small ribs be added at its bottom, Fig. 6-28 b . Determine the maximum normal stress in the member for both cases. Dear Viewer You can find more videos in the link given below to learn more Theory Video Le...
Two Example Problem of Chapter 2 | Strain | Mechanics | Mechanics of materials RC Hib
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Example 2.1 The slender rod shown in Fig. 2-4 is subjected to an increase of temperature along its axis, which creates a normal strain in the rod of Pz = 40(10-3)z1^2 , w h e r e z is measured in meters. Determine ( a ) the displacement of the end B o f t h e r o d d u e t o t h e t e m p e r a t u r e i n c r e a s e, and ( b ) the average normal strain in the rod. Example 2.2 When force P is ...
The secret behind 3 solved example revealed | Mechanics of materials RC Hibbeler | Mechanics
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Example 3.4 A bar made of A-36 steel has the dimensions shown in Fig. 3-22 . If an axial force of P = 80 kN is applied to the bar, determine the change in its length and the change in the dimensions of its cross section after applying the load. The material behaves elastically. Example 3.5 A specimen of titanium allow is tested into torsion and the shear stress and strain strain diagram is show...
Expert Guide to Chapter 8 Combined Loading | Example Problems | Mechanics | Mechanics of materials
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Example 8.2 A force of 150 lb is applied to the edge of the member shown in Figure 8-3a. Neglect the weight of the member and determine the state of stress at points B a n d C. Example 8.4 The member shown in Fig. 8-5 a has a rectangular cross section. Determine the state of stress that the loading produces at point C. Example 8.5 The solid rod shown in Fig. 8-6 a has a radius of 0.75 in. If it...
Determine the modulus of elasticity | Example 3.6 | Mechanics | Mechanics of materials RC Hibbeler
มุมมอง 168หลายเดือนก่อน
An aluminum specimen shown in Fig. 3-26 has a diameter of d0 = 25 mm and a gauge length of L0 = 250 mm. If a force of 165 kN elongates the gauge length 1.20 mm, determine the modulus of elasticity. Also, determine by how much the force causes the diameter of the specimen to contract. Take Gal = 26 GPa and sY = 440 MPa. Dear Viewer You can find more videos in the link given below to learn more T...
Determine shear modulus G and ultimate shear stress | Example 3.5 | Mechanics of materials Rc Hibb
มุมมอง 118หลายเดือนก่อน
A specimen of titanium allow is tested into torsion and the shear stress and strain strain diagram is shown in Fig. 3-25 a . Determine the shear modulus G, the proportional limit, and the ultimate shear stress. Also, determine the maximum distance d that the top of a block of this material, shown in Fig. 3-25 b , could be displaced horizontally if the material behaves elastically when acted upo...
Determine the change in its length | Example 3.4 | Mechanics | Mechanics of materials RC Hibbeler
มุมมอง 213หลายเดือนก่อน
A bar made of A-36 steel has the dimensions shown in Fig. 3-22 . If an axial force of P = 80 kN is applied to the bar, determine the change in its length and the change in the dimensions of its cross section after applying the load. The material behaves elastically. Dear Viewer You can find more videos in the link given below to learn more Theory Video Lecture of Mechanics of Materials by Beer ...
Determine the normal strain developed in wire BD |Example 2.2 | Mechanics | Mechanics of materials
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When force P is applied to the rigid lever arm ABC in Fig. 2-5 a , the arm rotates counterclockwise about pin A through an angle of 0.05°. Determine the normal strain developed in wire BD. Dear Viewer You can find more videos in the link given below to learn more Theory Video Lecture of Mechanics of Materials by Beer & Johnston th-cam.com/play/PLuj5YwfYIVm9GBcC6S4-ZgHS1szlF7s1Y.html 299 Problem...
Determine range of values for eccentricity ey of load along y axis | Ex 8.7 | Mechanics of materials
มุมมอง 304หลายเดือนก่อน
Determine range of values for eccentricity ey of load along y axis | Ex 8.7 | Mechanics of materials
Example 8.6 | Determine the state of stress at point A | Combined Loading | Mechanics of Materials
มุมมอง 648หลายเดือนก่อน
Example 8.6 | Determine the state of stress at point A | Combined Loading | Mechanics of Materials
Determine the state of stress at point A | Example 8-5 | Combined Loading | Mechanics of Materials
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Determine the state of stress at point A | Example 8-5 | Combined Loading | Mechanics of Materials
Example 8.2 | Determine state of stress at point B and C | Combined Loading | Mechanics of Materials
มุมมอง 529หลายเดือนก่อน
Example 8.2 | Determine state of stress at point B and C | Combined Loading | Mechanics of Materials
Determine state of stress that loading at point C | Example 8.4 | Mechanics of Materials RC Hibbeler
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Determine state of stress that loading at point C | Example 8.4 | Mechanics of Materials RC Hibbeler
Mechanics of Materials Beer & Johnston, Mechanics of Materials RC Hibbeler Problems and Lectures
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Mechanics of Materials Beer & Johnston, Mechanics of Materials RC Hibbeler Problems and Lectures
The BEST Mechanics of Materials Lectures and Problems for 2024!
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The BEST Mechanics of Materials Lectures and Problems for 2024!
6-142 | Determine maximum allowable force P | Curved Beams | Mechanics of materials
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6-142 | Determine maximum allowable force P | Curved Beams | Mechanics of materials
Determine displacement of point B and strain | Example 2.1| Mechanics of materials RC hibbeler
มุมมอง 4242 หลายเดือนก่อน
Determine displacement of point B and strain | Example 2.1| Mechanics of materials RC hibbeler
6-143 | Maximum stress developed at section a-a | Curved Beams | Mechanics of materials RC Hibbeler
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6-143 | Maximum stress developed at section a-a | Curved Beams | Mechanics of materials RC Hibbeler
6-140 | Determine the maximum moment M | Curved Beams | Mechanics of materials RC Hibbeler
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6-140 | Determine the maximum moment M | Curved Beams | Mechanics of materials RC Hibbeler
6-141 | Bending Stresses in Curved Beam | Mechanics of Materials RC Hibbeler
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6-141 | Bending Stresses in Curved Beam | Mechanics of Materials RC Hibbeler
6-139 | Determine maximum bending stress in curved beam | Mechanics of materials RC Hibbeler
มุมมอง 2992 หลายเดือนก่อน
6-139 | Determine maximum bending stress in curved beam | Mechanics of materials RC Hibbeler
6-138 | Bending Moment for Curved Beam | Mechanics of Materials RC Hibbeler
มุมมอง 3152 หลายเดือนก่อน
6-138 | Bending Moment for Curved Beam | Mechanics of Materials RC Hibbeler
Determine the position x of this force | Example 1.8 | Mechanics of materials
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Determine the position x of this force | Example 1.8 | Mechanics of materials
Why did we take the height as 200mm when calculating I? I was thinking of taking 30mm. thank you
When calculating the moment of inertia, I calculated all areas separately, but I find a different result than yours. 1/12*((0,2)(0,015)^3)*2 + 1/12(0,03)(0,3)^3 for figure a
The reason is that both upper and lower flanges are away from neutral axis so you have to add Ad^2 with each of the moment of inertia of flange and then you will get the same answer
@@engradnanrasheedmechanical But isn't this a symmetrical shape? Why do we feel the need to do this?
@Ders-x2n yes symmetrical about both horizontal and vertical axis. But if you take horizontal axis then you can see that centroid of Web portion lies on neutral axis and while centroid of the flanges are away from horizontal axis that's why we apply parallel axis theorm for calculating moment of inertia about horizontal axis. While of of you want to calculate moment of inertia about y axis then both centroid of flange and Web lies on it so no need to take the term Ad^2. I hope you have clear understanding now
@@engradnanrasheedmechanical thank you
Please, can I have the source of the questions?
What do you mean by that? Please explain
@engradnanrasheedmechanical I mean the reference from which you solve the questions, the questions file.
Fantastic 😍
Thank you
Why 1/12x0.125x0.15 don’t need to x 2?
Kindly mention the time where you have problem
Thats awesome! Thank you.
You are welcome 🌹
Great job
Thank you
Great video sir n happy new years to you n your family 🎉🎉🎉
Thank you 👍 and happy new year to you and your family members ❤
On the 0:53 part B then you substitute X with L/2 instead of 3L/2 on 16:07
Dear kindly check the section diagram x starts from from point B and I have mention for portion BC x is greater or equal to 0 and less or equal to L. At point B x=0 and at point C x=L . At the mid point of BC , X is L/2. I hope it will be clear now. Do check my new videos about this with clear handwriting
Chapter 12 Deflection of beams and shafts BY MECHANICS OF MATERIALS R.C HIBBELER (9TH EDITION), Complete Solution by Engr: th-cam.com/play/PLuj5YwfYIVm-zYKIRhkcp8T14ca9gKZVM.html Check out this playlist as well
At the midspan why did you put L/2? Because have that L+L/2= 3L/2 AND WHEN WE DIVIDED IT BY 2 IT WILL BE 3L/4…. Or you mean by the midspan the mid point between A and B?
kindly mention the time 🕰️ in video so that i can check
Can you explain why you got + for the torsional stress applied to point b?
The torsion distribution diagram the maximum shearing stress due to torsion will be at point B is upward so that'd why
When calculating the bending stress according to point a in 8.36, we took my/I as negative, since it is compression, shouldn't it be + when calculating the bending stress according to point b this question ?thank you sir We already found zero but I still wanted to ask
The general formula for Bending stress is sigma = - M*y/ I where y is distance from neutral axis either upward or downward. AS POINT B LIES ON NEUTRAL AXIS SO Y IS ZERO MAKES WHOLD EQUATION SIGMA = 0
When calculating mz, is the reason we take vy and nx into account because they pass through moment points? If they did not pass through, we would include them too, right? thank you
No you can see these forces along with the horizontal and vertical component of applied force F are producing couple about Z axis therefore. If we talk about a point at which sum of all moment is zero then forces passing through that point will not produce moment ❤
No you can see these forces along with the horizontal and vertical component of applied force F are producing couple about Z axis therefore. If we talk about a point at which sum of all moment is zero then forces passing through that point will not produce moment ❤
Why didn't we take h as 4 in the first question? How do we understand that 10 is the height? thank you
You can see the moment is about the horizontal line or axis towards you. So moment of inertia about that axis will be taken so based on that axis the height is 10 and the width is 4. ❤
Why u didn’t multiply the q=F/s by two because we have nails on both sides of the body?
In question it is given that each nail support shear force of 100 and distance between the center of nail is also given so that's why we have taken it only F/S....❤
Thank you ❤️
You are welcome 🌹 and kindly share it to maximum people
thank you so much
You are welcome and keep watching and sharing 😀
❤❤
Thank you and share my videos with your friends ❤
Mashallah sir ❤️❤️
How to get the shear stress from this?? Need asap
From this, get the maximum shear force from shear force diagram and then watch this video Transverse Shear (CHAPTER 07) BY MECHANICS OF MATERIALS R.C HIBBELER (9TH EDITION), Complete Solution by Engr Adnan Rasheed Mechanical: th-cam.com/play/PLuj5YwfYIVm8XgaWLuFz55Me-A2wqY9KV.html You will get it. Its quick solution. If you need any assistance, do let me know
Sir why have we take the thickness to be 0.025,are we not supposed to take the two thickness one for 0.025 and other is 0.030
Kindly read the question , it is stated to find the shear stress in Web so we are taking Web's thickness
Loved this one 🎉
Thank you 👍
Can you solve 7-55?
@@Ders-x2n I shall check it today
@@engradnanrasheedmechanical thank you sir
@Ders-x2n you are welcome 🌹
if we look at joint D, Fdc*4/5=Fbd, then Fcd= 25 not 0, right
Fcd= 25 kip
@@engradnanrasheedmechanical thank you, Sir.
@mynguyenthihoang2230 you are welcome
When calculating q, we multiplied by the number of rows in other questions. Why didn't we do it here? In which type of questions do we multiply by the number of rows? Thanks.
You can check the figure which will clearly tell you the number of rows of nails...
sir the corresponding maximum nail spacing nearest multiply 5mm What did he mean in the question? I guess we didn't use this information.
In question it is not mentioned. Please read the question again ❤
Why did we take the thickness of the Qd part as 0.05? Shouldn't we have taken it as 0.1? I thought so because it was stuck on both sides.
That is done only for one side. If you put thickness 0.1 then it's for both side and at the last you will divide it by 2 to get the result in single side. Things are the same, rest it depends on you what you choose....
@@engradnanrasheedmechanical thank you sir
god
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@@engradnanrasheedmechanical you save my life
@gbgfgfc good to know that
nice and wondeful
Thank you, keep watching and sharing 😊
sir how do come p with Pcos(theta) that part confuses me
Ok you can see that we draw a line parallel to inclined plane at the point of application of load P it will also make angle theta with that line. Now this P will have two rectangular components one along the inclined line and other perpendicular to it. If you take cos theta then it will be equal to component along incline line/ P so the component along inclined line will be P cost theta.....❤
I couldn't understand why we calculated the static moment separately as points c and d. Where does it say in the question, how should we understand that we should do this or that we should not separate it as points c and d? But while calculating Qd, we also added Qc, which we found above. Why didn't we answer this question as we calculated Qmax? thank you💛
The reason is that in question we have to find the intensity of shear stress distribution. For that we need to find the shear stress at C and Shear stress at D. You have seen that shear stress at c is less than Shear Stress at D. The reason is that Qc < Qd. and Q max will be equal to Qd. Rest you can find the shear stress at any point if given....
Hi Adnan! I can't understand where the L^2 multiplied by x in the fourth equation come from. Did you divided by 1/L? minute 17:06
Kindly simply it you will get it and its not necessary that you should get exactly what I have written. You can leave the length equation as well. ❤ that will be correct as well
Thank you soo much🌷🤍
You are welcome and share my videos with your friends as well! 🙏
Sir your playlıst really helped me to understanding the concept with the problems thank you soo muchh
You are welcome and share my videos videos with your friends ❤
such a great explaining
Happy to help you learn! 😄
brother you are a king!
Thank you and keep watching my videos and share them with your friends also so that they may learn ...
Did we take the thickness v shear force as 0.1 because it is applied to that area?
yes you are right
Hi just wondering why have you taken the moment for 400(4) to be positive should it not be negative? Can you please explain
Sum of all moment about point B is taken as zero so keeping point B the 400 lb force is producing counter clockwise moment and we have taken counter clockwise moment is positive that's why it is positive ❤
Thank you!
@shadibentamy9668 you are welcome
Professor how can I get the mechanic~1 pdf
You mean solution of this book?
@@engradnanrasheedmechanical yes professor
@@engradnanrasheedmechanicalyes professor
@@engradnanrasheedmechanicalyes professor
@ yes professor
🎉🎉 great explanation sir as always
Thank you brother 🙏 💙 ❤
The height is 88 not 84
HOW?
24+20+20+24 =88@@engradnanrasheedmechanical
Yes you are right it's 88 not 84. Thank you for correction. Rest I hope you have learnt it. 🙏
How you used r^4, r’^4 for J ,instead of (r^4-r’^4)?
Kindly mention the time frame please
@@engradnanrasheedmechanical in 2.05 You wrote the Tmax as Tr/((π/2)(r^4)) but it is a tube, so In this case, shouldn't we write (π/2)(r^4-r'^4) for J in the formula?
@@ufukmolla7402 please read the first line of the question solid shaft has radius r ...
@@engradnanrasheedmechanical Okay, I got it, thanks. Looking at the image, I thought it was a hollow tube.
No problem 😊
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Thank you
You help me a lot teacher
I am happy for that....
bro is saving my final exam😭
When is your final? And in which university you study?
❣❣❣
Thank you and share my videos with your friends as well