(BBS-8) Cutting length of stirrups, Proof of IS Code & Traditional Method.

[@marketknowledge360]

Great knowledge by great teacher
🙏

[@sudityabhattacharya5423]

Very helpful sir thank you

[@civilbasics21]

Happy to help

[@rahulmaurya2166]

Thank you so much sir, yaha site pe aapki btae ge vidhi aur L&T ke engineer me hamesa hi thoda defferent ho ja rha tha but ab sbhi doubt clear ho gya
Aapke jaisa mujhe gurdev mile hai mujhe bahut garv hai.
Aapki vjh se hi mai aaj apne dam pe hi Puri Pani ki tanki bnva deta hu jo ki bde bde experience log kra nahi pa rhe hai 👍👍👍👍👍

[@khalilahmed-wn9ky]

Thankyou so much sir🙏🏻🙏🏻..sir it’s a request to you please make a video on 4&6 legged stirrups 🙏🏻🙏🏻🙏🏻

[@biting.scorpio]

Thankyou for such a nice explanation,till now I have been using center line while using traditional method and appling standard bend deductions, this video is super helpful. waiting for more videos in future.

[@civilbasics21]

Thanks for nice comment . I will be happy if you gives me your brief introduction.

[@pankajubale3113]

In proof of this formulae we add the curvature portion for 90 & 135 degree but pratically there is elongation on curve portion then dont we deduct in proof instead of adding it

[@SahebDas-fx4np]

Respected Sir, as per IS 456:2000, Cl 26.2.2.4b in case of Stirrups it is recommended an extension of 8d beyond 90° bend, 6d beyond 135° bend and 4d beyond 180° bend.
But as per IS 2502:1963, Cl 3.8, the straight portion beyond end of the curve 90°, 135°, 180° shall not be less than 8d i.e. 8d for all 3 cases.
My question is, in this type of contradiction which code should we follow in
a) exam point of view
b) in field.
and again Thank you sir for this wonderful video

[@civilbasics21]

You should follow latest code at both places.

[@SahebDas-fx4np]

@@civilbasics21 ok Sir. Thank you

[@debasishghara9487]

Pl create a video an modal analysis

[@deboprasadbiswas1987]

Sir, lekin k=2 to only mild steel bar k lia hai....humlog site me to HYSD bar use karte hai......

[@deboprasadbiswas1987]

Sir, lekin traditionally site pe to k value humlog 2 hi use karte hai....but HYSD bar hota hai.....

[@pankajubale3113]

Sir can you pls give the proof for U shape stirrup of 180 degree bend.

[@nikhilmaurya1595]

Sir one question to ask, in IS code formula internal dimension of stirrup is taken A-4d and E-4d but in numerical Value is taken A-2d and E-2d while calculating cutting length? Please clear my doubt sir.

[@civilbasics21]

A-4d and E-4d are not internal dimentions . In example also A-2d etc is not taken.
Watch video again carefully and understand what I am saying.

[@soorajkumar1423]

Sir what would be the formula for HYSD bar, since its K value changes.?

[@civilbasics21]

Radius of inner curvature =kd, put real value of k and then derive formula.

[@pankajubale3113]

Sir why dont we use bend and hook allowance directly instead of circumference formulae for finding cutting lenght. We already found it in bbs-1

[@civilbasics21]

Hook allowance is derived with straight length is 4d . But as per is 2502-1963 straight length is taken 8d. This is the reason why here hook allowance is not used.
Though adding extra 4d distance you can use hook or bend allowance. Since here straight length is 8d instead of 4d.

[@pankajubale3113]

can you pls explain this also

[@musharrafibrahim4632]

Sir ye sab to mild steel per applied hogi HYSD bar k liye kya karei as per IS code?

[@civilbasics21]

Here derivation is done for mild steel (k=2). For other steel use k=3,4 etc

[@pankajubale3113]

Sir for finding 135 degree bend length why cant we use circumference of circle instead of R X thita

[@civilbasics21]

For 90 degree bend also R× theta can be used. These are alternate Methods.

[@pankajubale3113]

​@@civilbasics21yes i got the answer for 90 degree, but i am not getting the answer for 135 degree by using circumference formulae. Pls guide

[@apurbapal890]

Sir , please give a lecture for steel water tank design , under ground or rest on ground