The load is 1.5kN PER 1 meter. So the shear curve goes down at that rate starting at 2m. You see that over the next meter it goes down 1.5 from +0.75 to -0.75. So 0.5m after 2 meters, it has only gone down half of 1.5kN, which is 0.75, which brings it back down to zero.
@@Testmailing-lr3idThe video isn't really missing any information. No additional formulas needed. I tried to give more detail to explain what he was doing in the video, but if it's unclear from this video and my explanation, try googling or watching more vids.
@@Testmailing-lr3idat point B we are 2 meters away from point A. Thus, if you need an equation: 0.75-1.5*x=0 (where x distance from B). +0.75kN is the starting load, -1.5kN/m is the distributed load that started being applied from point B rightwards to point C.
The best of internet on the topic ,goes straight into head.thank u sir.
Thanks Sir
How did you determine that shear is zero kN at 2.5 meters?
The load is 1.5kN PER 1 meter. So the shear curve goes down at that rate starting at 2m. You see that over the next meter it goes down 1.5 from +0.75 to -0.75. So 0.5m after 2 meters, it has only gone down half of 1.5kN, which is 0.75, which brings it back down to zero.
@@mattyT618You are telling history. What is the formula of finding this value..
@@Testmailing-lr3idThe video isn't really missing any information. No additional formulas needed. I tried to give more detail to explain what he was doing in the video, but if it's unclear from this video and my explanation, try googling or watching more vids.
@@Testmailing-lr3idat point B we are 2 meters away from point A. Thus, if you need an equation: 0.75-1.5*x=0 (where x distance from B). +0.75kN is the starting load, -1.5kN/m is the distributed load that started being applied from point B rightwards to point C.
@@Testmailing-lr3id perform ratio and proportion of similar triangle done.
Too fast
Too fast, please slow down