Uniformly Distributed Load (UDL): Shear Force and Bending Moment Diagram [SFD BMD Problem 4]

[@raushankumar4244]

I would just say amazing!❤❤ Although the subscriber count is low, the work you're doing deserves at least millions of subscribers

[@shreyaumre995]

I would say....awesome explanation...✨️

[@md.hasanuzzamanjihad4623]

Great and easiest explanation... Thanks bro. Pls upload more videos on SFD and BMD problem solving

[@FilmonAron-qx4gg]

Thank you so much for the clear explanation!

[@ifinfotech]

Glad it was helpful!

[@AnanyaAugustine]

Thank you for the detailed explanation

[@ifinfotech]

You are welcome!

[@VijayVijji-yr3lz]

Sir how to get x value 3.57

[@VijayVijji-yr3lz]

Sister u clarify how to get x value 3.67

[@VijayVijji-yr3lz]

Sry 3.57

[@gabrielatem1121]

Much appreciated your explanation❤

[@YvonneMbinya-r7x]

Great video, have being trying to understand udl and your video helped me a lot, much love from Kenya 🇰🇪

[@mahantheshag1226]

Beautiful explanation

[@ifinfotech]

Thanks!

[@為志揚]

你超猛的,聽不懂你的語言我卻看得懂整個分布圖,

[@satazer5824]

Perfect method. Thank you.

[@ifinfotech]

You're welcome!

[@charukadilshan4599]

Great Teaching

[@forouzanhabibi]

Thank you so much

[@baiklahtu]

Sorry sir, SFdr for SF diagram should be - 4.14 or - 5.86?

[@gabrielatem1121]

Could you clarify how length x=3.57 become force at maximum point E?

[@aqsanazir4819]

Same question

[@zyler548]

Look back 10 Standard Maths Similarity of Triangles

[@olivergrennan309]

your the goat

[@prashanthakumar4573]

how did you get Rb value 5.86kn

[@mahendratripura800]

41/7

[@arcreation2732]

​@@mahendratripura800I think moment=(8*4*(4/2))+(5*5)-(Rb*7) = Rb = 12.71 kn

[@gluton07]

while taking moment at E its length is 3.57, doesnt the point load 8 kN will be counted as Moment at E = 7.14*3.57-2*3.57²/2-8*1.57 ??

[@Rahulterabhaisabsebhar.i]

Bro 8 KN is UDL and 3.57 is also udl but 3.57 is part of 8 hence we will neglect it because we Have created Individual Udl of that

[@Ham_engineer]

We got point of contraflexure

[@palakramawat4983]

Non uniformly Kaha milega sir

[@kenken578]

Can you also do for moving loads, and triangular loads example? Thank you.

[@strdpra0z]

Sir when you find out moment of udl that time 8×4×(4÷2) +5×5=Rb×6 hona chahiye

[@mrunal9390]

Right

[@VijayVijji-yr3lz]

Hlo any one tell me how to get 3.57 answer

[@kerinekylie]

There's something wrong here

[@Parmar2114]

Is that you talking about hinge support?

[@patilgouda]

How Rb =5.86kn

[@swasthik.B]

41/7

[@Lazycrusher886]

💩