really nice video in that it covered it from basics - i had only memorised it, but thanks for going in details without all the jargons and hype that other coaching institutes create
Fricking hell.. this is JEE Advanced level content right there, cleared all my doubts which i had on this topic! TYSM! Tho i may have a doubt, is it possible to calculate the electric field's *value* inside the cavity? I think not, but i am not sure
E=0 inside the cavity. Sir said in the video By taking gaussian surface as any spherical surface inside the solid sphere, electrostatic force inside gaussian surface is zero. Thus electric field =0. Refer 3:20 for more info
the field inside the cavity originates due to the positive charge, which means at any point the field is Kq/r^2 inside the cavity until you enter the conductor
the field inside a cavity is due to the positive point charge only, which is equal to Kq/r^2 at a distance r from the charge as long as you are outside the metal shell
In this video there’s a minute error, the electric field in the bulk of the sphere is not canceled by the opposing field from the +Q charge on the outer surface. According to the shell theorem, the electric field at every point inside the sphere due to the charge on the outer surface is zero. The electric field inside the bulk of the conductor is neutralized because the induced negative charges on the inner surface cause the field lines originating from the +Q charge inside the cavity to terminate on the inner surface.
Hi. I like your videos. I’m following a electromagnetism and I think that this problem (which is the Faraday ice pail) explain together different properties. As a person that is learning I don’t feel that your explanation when you say that the “outside word” is disconnected from the inside because you can imagine a Gaussian surface and so there is no flux through is the best explanation.. don’t get me wrong you can explain with Gauss law but I would try to give a different explanation without Gaus law of why outside there is not other option than uniformely distribution charge..
How the positive charges are supposed to gather around the conductor if there's no electric field in-between them or they're disconnected from the inner postive charge? Can someone clarify this?
A spherical conducting shell, centered at the origin, has inner radius a and outer radius b. Its net charge is zero. Inside the shell, on the x-axis at at x = a/2 there is a point charge q. Which will be the direction and magnitude of the electric force acting on the point charge?
The electric field inside the conductor should be zero but doesnt the field lines between the charge q and induced negative charge indicate an electric field??
Sir i have a doubt, let's say the cavity is of an irregular shape then the charge distribution on the surface of cavity will depend upon the position of point charge inside the cavity or on the local radius of curvature of the cavity ?
Depends on the position of charge inside the cavity otherwise electric field won't be zero Centre of charge of non uniformly induced charges (-q ) on surface of cavity will lie on the charge (+q) inside the cavity (off centre here) so that E=O inside the material of the conductor
He has covered all the advanced topics with such an impeccable quality of teaching
The charge distribution on the outer surface doesn't depend on the charge distribution on inner surface so outer charge distribution must be uniform
Thank u so much I was tired searching about it since long and finally got this exact thing
Me also bhai
really nice video in that it covered it from basics - i had only memorised it, but thanks for going in details without all the jargons and hype that other coaching institutes create
Physics always leaves me speechless 💯
sir please organize your videos, it's a humble request
head over to the site mentioned in the descriptions - there, the videos are verry well organised
Fricking hell.. this is JEE Advanced level content right there, cleared all my doubts which i had on this topic! TYSM!
Tho i may have a doubt, is it possible to calculate the electric field's *value* inside the cavity? I think not, but i am not sure
E=0 inside the cavity. Sir said in the video
By taking gaussian surface as any spherical surface inside the solid sphere, electrostatic force inside gaussian surface is zero. Thus electric field =0.
Refer 3:20 for more info
@@badpineapple9120 i am not saying inside the conductor, but the empty part between the charge and conductor
the field inside the cavity originates due to the positive charge, which means at any point the field is Kq/r^2 inside the cavity until you enter the conductor
@@badpineapple9120 you got it mixed up
the field inside a cavity is due to the positive point charge only, which is equal to Kq/r^2 at a distance r from the charge as long as you are outside the metal shell
Thank you….I was searching this for a long…I always used to get confused and even no one has explained this concept….finally the concepts are clear!!
Why I didn't know this channel before??
The video is so clear and easy to understand!!! Thank you very much
How'd he get the cursor to have two fingers pointed out :0
outstanding work, talking as a physics teacher
In this video there’s a minute error, the electric field in the bulk of the sphere is not canceled by the opposing field from the +Q charge on the outer surface. According to the shell theorem, the electric field at every point inside the sphere due to the charge on the outer surface is zero. The electric field inside the bulk of the conductor is neutralized because the induced negative charges on the inner surface cause the field lines originating from the +Q charge inside the cavity to terminate on the inner surface.
Had tears (of happiness) finally I got it sir. I love how you raise questions and tell us to think about it. ❤ Amazing teaching 👏🏻 stay blessed
Much precise, detailed and well explained than most of the videos out there on the same topic.
your videos clear doubts instantly! keep em coming.
You are one of the greatest teacher
Also positive charges are immobile in a solid conductor
Such a nice explanation, I couldn't even understand a single thing by reading my text book for the 5th time....Now everything is clear.
LOVE FROM UGANDA KI KALIGHATI 😌🔥
Wow extremely clear explanation. The only video i found that covers this topic in depth.
great video! We need more educators like you
This result is remarkable. I remember seeing this in Physics class but as usual throwing out all the amazement.
Thank you sir
What if the sphere is grounded, would it have the same results? Please answer as soon as possible, Ty
I fell in love with your video every time
you're a lifesaver thank you
Best explanation
Literally terrific explanation
Your explanation is very helpful...thankyou so much🤗
Explanation can be to the point and not take longer time
Really got a charge out of the lecture, you have great energy.
I am grateful to you sir❤
Outstanding amazing mind blowing sir
Thanks
Mazza aaya!
Amazing video! Thanks from Portugal
Really 😶😶😶
but what if the charge is placed at the centre then the negative charges would be uniform right??
Sir excellent sir, organize your videos sir
Hi. I like your videos. I’m following a electromagnetism and I think that this problem (which is the Faraday ice pail) explain together different properties. As a person that is learning I don’t feel that your explanation when you say that the “outside word” is disconnected from the inside because you can imagine a Gaussian surface and so there is no flux through is the best explanation.. don’t get me wrong you can explain with Gauss law but I would try to give a different explanation without Gaus law of why outside there is not other option than uniformely distribution charge..
Superb
I am so much confused about this topic but thank u so much for solving my doubt🤩
Thanks it helped a lot
THANK YOU!
Thnku sooo much sir nd hatts of to your commendable teachingg
thnks sir
will there be any charge induced on the outer surface of the cavity?
Thanks a lot
Mahn ur just too gud pls continue this good work
hush finally my doubt is solved
Nice explanation
Thankyou
Thankyouu
Simply awesome. Please create more such videos on difficult concepts.
Sir will you cover capacitor and capacitance also.?
Thank u providing us quality education bro
In case of neutral dielectric sphere wht happen??
So what is the field inside the cavity?
Zero
Hi, does that means I have a field equal to the resonance field outside of the room (faraday cage) but more scattered ?
How the positive charges are supposed to gather around the conductor if there's no electric field in-between them or they're disconnected from the inner postive charge? Can someone clarify this?
A spherical conducting shell, centered at the origin, has inner radius a and outer radius
b. Its net charge is zero. Inside the shell, on the x-axis at at x = a/2 there is a point
charge q.
Which will be the direction and magnitude of the electric force acting on the point
charge?
The electric field inside the conductor should be zero but doesnt the field lines between the charge q and induced negative charge indicate an electric field??
Sir i have a doubt, let's say the cavity is of an irregular shape then the charge distribution on the surface of cavity will depend upon the position of point charge inside the cavity or on the local radius of curvature of the cavity ?
Depends on the position of charge inside the cavity otherwise electric field won't be zero
Centre of charge of non uniformly induced charges (-q ) on surface of cavity will lie on the charge (+q) inside the cavity (off centre here) so that E=O inside the material of the conductor
Is the charge on outer surface same as in centre or Different?
It has to be same
How to find potential at centre?
Such a Nice voice😂😊
❤❤❤❤❤❤❤❤🎉🎉🎉🎉🎉
Explanation is everything good....but while listening into another English accent feeling difficult to hear....
It's probably the laziest video you ever made
Avoid that cheap accent 🙏
thanks a lot
Thanks a lot