This is the thing I love about physics, and learning in general. When you have the right teacher, things click and your mind explodes with happiness when it realises what the law is actually trying to say. Currently at 1:44 and in awe of this. Thank you!!!
I have been teaching physics for 35 years and I have no qualms in admitting you are one of the best I have heard anywhere.You have three unparalled qualities a. Enthusiasm b. Great communication skills c. Great analogies to simplify abstract ideas.
I literally had 4,5 doubts n questions related to this topic and I didn't found the answers anywhere, but this guy cleared all those. Kudos👍 great work man
Gosh I've always been excited about people who are just as passionate about knowledge as me. I am so glad I discovered this channel. I really hope we will cross paths one day, Manhash.❤️✨️
4:10 theta is 0, E is constant 7:20 Thankyou🌟 8:40 sphere offcentre 9:50 I am blown away😮🧐🤔u always pull my brain chords and activate them to think_ there's a rush of neurons😄 10:30 imagine that charge is shooting out bullets 11:55 😮ohkkkk 13:00 more charges 13:45
Thank you sir.... Your love for physics make me feel love too..... Thank you so much... Even thank you is not enough .... But now I am happy.... Your visual-teaching is awesome....
u r very sweet and loving following u since many years probably 5 or 6 years thank you so much all the best to all people here learn grow love fire 🔥 it makes me feel something i cant express i am enjoying it a lottttt i always love going in depth and learn anything i am always grateful we love u forever😇
Summary Of The Video.... *Gauss's Theorem* * Electric Flux is independent of radius. * If we increase or decrease the radius of sphere , the electric Flux Remain the same. * If we move the charge from the centre anywhere in the sphere then in that case also the flux doens't change . * If charge is positive then we get a positive flux * But if the charge is negative then we get a negative flux. * If we take an irregular surface in that case also flux remain the same. * If there is a hole in the sphere then the flux decreases because in that case some flux (Electric field lines) may leak through the sphere. That's why we always consider a *Closed Surface* * If we increase the charge inside a surface then the flux increases because of increase in Number of electric field lines. * Charge located outside the sphere doesn't contribute on flux. * Only those charges will contribute in flux which are located inside the sphere.
Please can you explain why in some textbooks, electric flux is Φ = ∫ E dA and in other textbooks electric flux is Ψ= Q, and in this video too? Which one is correct and which is wrong?
Good video, but the electric flux is equal to the charge enclosed by the Gaussian surface. It is the integral of the electric flux density D, not the integral of the electric field intensity E. D = eps*E. In fact, the flux depends only on the charge enclosed. The electric field intensity depends on the charge enclosed AND the permittivity of the space (eps).
10:3112:25 even though i understood gauss's law earlier, still i couldnt apply it in questions earlier. But this bullet's analogy really helped me to apply it to non-trivial situations with ease. So, thanks a lot for giving this analogy/memorisation tool.
Awesome!! I have a question... What if radius is approaching zero(r~0) i.e radius is comparable to the charge size What happens when radius of Gaussian surface (sphere) r < charge *radius I mean Electric flux inside the charge 😯
The surface you must understand is imaginary. If the radius were approaching zero, the surface would still be existing around the charge, but now the imagination would be that it is shrinked yet there, and since it is there the bullet analogy would also work and the flux will remain same. When the radius reaches zero our imagined surface has vanished, so there is no flux to calculate. But again you could always consider (/imagine) a second surface, and about which you can again go on calculating flux in the exact same way. So, the conclusion would be, flux is always considered/calculated with respect to certain given space(usually area), be it imaginary or physical.
@@randomstuff6799 got it! But what about flux inside a charge? Incase of a 🧲 magnet Flux lines(magnetic field lines) Go from S pole to N pole inside the magnet... So gauss's law int(B.ds)=0 what about flux inside a charge?
Consider a hollow spherical conductor situated at a distance almost equivalent to infinity, so naturally from the point of reference (infinity), the sphere would seem to be a point charge. Now if that is the charge you are talking about, you must understand there is no flux to be considered inside the charge as there are no electric field lines existing inside it(electric field lines do not exist inside a uniformly charged spherical shell). If the sphere was not hollow but solid, the field lines would be directed outwards(as the direction of an electric field is given by the direction of its experiencing force). So, there is no existence of flux inside a charge. Mathematically zero.
hey can u explain why there are 12 bulllets per minute in the case where the charge is not at the centre i feel some bullrts cross surface faster and some will take more time that is mored than one minute as it has to travel more distance to flow through the sphere
@@shrutisinha-c4w u're right when saying some bullets crossing faster. However, we consider the total of bullets after a necessary time. Therefore, either the charge is at the center or isn't at the center (But it must be inside the closed surface), the result will be the same for both circumstances.
we know that electric field lines per unit area is directly proportional to the electric field strength ( as that's how we define EFL)..so EFL α ES... We define this quantity (where the E and S are along each other) = E•S as electric flux... so electric flux is basically EFL but in a physical quantity form.... So we can imagine it like those isotropical EFLS. So it's just some lines coming out and the best thing is, no matter what or how many closed surfaces are there covering it and from whichever orientation, all the bullets which are emitted from the charge centre, if they follow the inverse square law, we know all the overlapping distorted looking closed surfaces have the same no. of lines coming out. Also even if it was something like inverse cube law, we could get the formula using integration!!!! Happy learning :D
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This guy is the best we got we must protect him at any cost.
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Great idea💡
It's always refreshing to learn with someone as enthusiastic as you. Amazing video.
th-cam.com/play/PLs66WjG_e7uJxt5Un5Yovs8qs6Fk1_c4_.html
The energy that we didn't search for... But the energy we needed
School: i won't teach you the concepts properly but will blame you for bad grades.
Indian guy on TH-cam (Khan academy in this case) : I got you Bro
😂✌🏼
@Sattwik Hazra agreed
@Sattwik Hazra when learning something new, even PhD holders won't keep up if the teacher is not slowing down!
This is the thing I love about physics, and learning in general. When you have the right teacher, things click and your mind explodes with happiness when it realises what the law is actually trying to say. Currently at 1:44 and in awe of this. Thank you!!!
True✨
Yeah.. t
That clicking sensation.. is the best
I really love the way he was excited 😂❤️
This one has converted in one of my top ten educational videos, you explained the topic better than my college teachers could have ever done
I have been teaching physics for 35 years and I have no qualms in admitting you are one of the best I have heard anywhere.You have three unparalled qualities a. Enthusiasm b. Great communication skills
c. Great analogies to simplify abstract ideas.
I love his enthusiasm ✨ that makes me wanna learn more and reminds me of why in the first place I am .
Yeah🤩
i can tell that you were excited
I know right I sensed that too
😂
Hes a cutie
If you wanna learn general physics you can check his channel float head physics. He is the best
True this is the best yt class I have ever seen he is so underrated... He is way better than most of the overrated teachers
I couldn't see your expression but could feel it. The smile on my face watching this lecture is so amazing. thank you.🙏
Man we need more enthusiastic teachers like you.
Never knew someone could be so enthusiastic about e&m. This is great
never stop sir,you are on the another level
This guy is a gem! Love his enthusiasm 💖✨
I literally had 4,5 doubts n questions related to this topic and I didn't found the answers anywhere, but this guy cleared all those. Kudos👍 great work man
You’re a gem. It’s a Saturday and I have exam Monday. You have given me motivation to stay optimistic. Love your passion.
th-cam.com/play/PLs66WjG_e7uJxt5Un5Yovs8qs6Fk1_c4_.html
The best educational video I have seen on TH-cam explaining the Gauss law of electricity.
Oh god why didn't I find this channel before . Thank you so much
Thank you, your passion for physics saved me
I know you don't reply for us but the the voice of this lecture was amazing
Gosh I've always been excited about people who are just as passionate about knowledge as me. I am so glad I discovered this channel. I really hope we will cross paths one day, Manhash.❤️✨️
Thank you jesus for suggesting this best lecture ❤❤ and thank u sir
4:10 theta is 0, E is constant
7:20 Thankyou🌟
8:40 sphere offcentre
9:50 I am blown away😮🧐🤔u always pull my brain chords and activate them to think_ there's a rush of neurons😄
10:30 imagine that charge is shooting out bullets
11:55 😮ohkkkk
13:00 more charges
13:45
I love how enthusiastic this man is. Thank you so much for making a complicated topic look like a piece of cake.
I love how he gets excited while explaining the concepts. That's the true spirit 🫀
I can sense and feel the enthusiasm and passion in this lesson I really appreciate this video it gives me a more defined version of Gauss's Law
Fantastic video. Cant believe such great content is free.
th-cam.com/play/PLs66WjG_e7uJxt5Un5Yovs8qs6Fk1_c4_.html
man i fell in love with physics, this video is awesome no one explained gauss law quite like this
I don't know why but I'm not able to contain my joy while watching this video!
Now I know why electric flux through asymmetrical surfaces is also the same as symmetrical. Huge thanks to Khan academy.
Excellent....For myself,the bullet analogy did the trick.
Literally it was very helpful lecture for me my are filled with tears after understanding this concept thanks sir
Thank you so much ❤❤❤❤
You are a GOD!!!! YOU TAUGHT US NICELY!!! WONDERFUL EXPLAINATION!!👌👌👍👍👏👏
This man has single-handedly saved my grades in physics. Thank youu 🙌
Brilliant! Mahesh sir.
You are the one who uses youtube in the best way. Thank you for all your videos.
Thankyou brother mind-blowing lecture
I wonder that India owns this type of teacher!
Love from Bangladesh!
Scored 93 out 100 in my 12th boards. Thanks to khan academy’s videos.
I really like how much excitement you put Into the lecture. I can tell you love teaching. Keep them coming.
He gets excited by his own lectures. Love this this man
Thank you sir.... Your love for physics make me feel love too..... Thank you so much... Even thank you is not enough .... But now I am happy.... Your visual-teaching is awesome....
I am amazed at how well he explains it, it is amazing how much this makes sense now, his enthusiasm is contagious too !
dude i love your energy, even if i'm too thick for this today i'm still getting the good vibes
U ARE A GOD
This is excellent
the excitement in his voice is just so pureee
This is the way of Sal Khan, thank you my friend this was one of the most fun lectures i have ever seen
What a clear explanation with a soothing voice 😀👍
Understanding at the peak level....
u r very sweet and loving
following u since many years
probably 5 or 6 years
thank you so much
all the best to all people here
learn grow love fire 🔥
it makes me feel something i cant express
i am enjoying it a lottttt
i always love going in depth and learn anything
i am always grateful
we love u forever😇
Thank you man. You are amazing.
HATS OFF TO YOUR EXCELLENT TEACHING SIR!!!!!!!!!
3:26 dA is perpendicular to the sphere.
Amazing explanation!!! I have no words that I appreciate this lecture...surpeeeééb,,amazing, outstanding
Excellent lecture, thank you, Bro.
Summary Of The Video....
*Gauss's Theorem*
* Electric Flux is independent of radius.
* If we increase or decrease the radius of sphere , the electric Flux Remain the same.
* If we move the charge from the centre anywhere in the sphere then in that case also the flux doens't change .
* If charge is positive then we get a positive flux
* But if the charge is negative then we get a negative flux.
* If we take an irregular surface in that case also flux remain the same.
* If there is a hole in the sphere then the flux decreases because in that case some flux (Electric field lines) may leak through the sphere.
That's why we always consider a *Closed Surface*
* If we increase the charge inside a surface then the flux increases because of increase in Number of electric field lines.
* Charge located outside the sphere doesn't contribute on flux.
* Only those charges will contribute in flux which are located inside the sphere.
th-cam.com/play/PLs66WjG_e7uJxt5Un5Yovs8qs6Fk1_c4_.html
Please can you explain why in some textbooks, electric flux is Φ = ∫ E dA and in other textbooks electric flux is Ψ= Q, and in this video too? Which one is correct and which is wrong?
You can learn anything from TH-cam, but with khan academy India you learn more 🎉
Wow.. you were soo excited. What a passion! 😌
I found that this is the best explanation of Guass law en earth, many many thanks. This dude rocks
th-cam.com/play/PLs66WjG_e7uJxt5Un5Yovs8qs6Fk1_c4_.html
It's really amazing either your explanation or gauss law
👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼
Thank you muzammil ❤❤
Really insightful
Kitna acha explain krte ho yr aap 👍🏻🙌🏻🙌🏻
I LOVE this law now, THANK YOU so much Sir. It was so helpful
bro deserves Nobel Peace Prize , you're making world a better place
6:01 what if the area is not sphere? Will the equation change?🫣🫣
Thank you so much!!! I was about to give up, but you saved me... once again
th-cam.com/play/PLs66WjG_e7uJxt5Un5Yovs8qs6Fk1_c4_.html
Excellent explanation sir!! Thank you
Great enthusiasm sir. Loved your teaching❤❤
Beautiful explaination...
bro you are a life saver.....
Damn this video really deserves million views 🤯🤯🤯
Greatly explained👏🏻....
Beautiful explanation sir...
Hats off...
you can tell that this guy is enjoying what he's doing
Good video, but the electric flux is equal to the charge enclosed by the Gaussian surface. It is the integral of the electric flux density D, not the integral of the electric field intensity E. D = eps*E. In fact, the flux depends only on the charge enclosed. The electric field intensity depends on the charge enclosed AND the permittivity of the space (eps).
Good presentation, Monesh. 👍
i love how u never mentioned 'hard' 'vast' 'complicated' but rather 'interesting' 'exciting'
10:31 12:25 even though i understood gauss's law earlier, still i couldnt apply it in questions earlier. But this bullet's analogy really helped me to apply it to non-trivial situations with ease. So, thanks a lot for giving this analogy/memorisation tool.
Excellent explanation 👍 Bless u 🙌🙌🙌 make more videos on tough concepts like this .
th-cam.com/play/PLs66WjG_e7uJxt5Un5Yovs8qs6Fk1_c4_.html
Organic chemistry tutor>>>>
This was very much excited🤩 Thank you so much sir
Thank you! YOU ARE GOATED!
This is wow. This man is an excellent teacher.
Plz do it for neet exam also its very helpful
Awesome!!
I have a question...
What if radius is approaching zero(r~0)
i.e radius is comparable to the charge size
What happens when radius of Gaussian surface (sphere) r < charge *radius
I mean Electric flux inside the charge 😯
The surface you must understand is imaginary. If the radius were approaching zero, the surface would still be existing around the charge, but now the imagination would be that it is shrinked yet there, and since it is there the bullet analogy would also work and the flux will remain same.
When the radius reaches zero our imagined surface has vanished, so there is no flux to calculate. But again you could always consider (/imagine) a second surface, and about which you can again go on calculating flux in the exact same way.
So, the conclusion would be, flux is always considered/calculated with respect to certain given space(usually area), be it imaginary or physical.
@@randomstuff6799 got it!
But what about flux inside a charge?
Incase of a 🧲 magnet
Flux lines(magnetic field lines)
Go from S pole to N pole inside the magnet...
So gauss's law int(B.ds)=0
what about flux inside a charge?
Consider a hollow spherical conductor situated at a distance almost equivalent to infinity, so naturally from the point of reference (infinity), the sphere would seem to be a point charge. Now if that is the charge you are talking about, you must understand there is no flux to be considered inside the charge as there are no electric field lines existing inside it(electric field lines do not exist inside a uniformly charged spherical shell).
If the sphere was not hollow but solid, the field lines would be directed outwards(as the direction of an electric field is given by the direction of its experiencing force).
So, there is no existence of flux inside a charge. Mathematically zero.
You sir are a king 🙇♂️
Just Amazing 💚💚
I really like the way you put these concepts into perspective. Great work.
What a great teacher
I am in love with the perfection
Nice✨
thank you so much because my lecturer at uni can’t even help me understand this problem
hey can u explain why there are 12 bulllets per minute in the case where the charge is not at the centre
i feel some bullrts cross surface faster and some will take more time that is mored than one minute as it has to travel more distance to flow through the sphere
@@shrutisinha-c4w u're right when saying some bullets crossing faster. However, we consider the total of bullets after a necessary time. Therefore, either the charge is at the center or isn't at the center (But it must be inside the closed surface), the result will be the same for both circumstances.
its always amazing to learn from you i love it every damn time
we know that electric field lines per unit area is directly proportional to the electric field strength ( as that's how we define EFL)..so EFL α ES... We define this quantity (where the E and S are along each other) = E•S as electric flux... so electric flux is basically EFL but in a physical quantity form.... So we can imagine it like those isotropical EFLS. So it's just some lines coming out and the best thing is, no matter what or how many closed surfaces are there covering it and from whichever orientation, all the bullets which are emitted from the charge centre, if they follow the inverse square law, we know all the overlapping distorted looking closed surfaces have the same no. of lines coming out.
Also even if it was something like inverse cube law, we could get the formula using integration!!!!
Happy learning :D
i love this guy so much
You're the best🎉
Bro u are the best..keep it up..❤❤❤