Key Expansion in AES | Round Constant and g function in Key Expansion in AES
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- เผยแพร่เมื่อ 13 ก.ค. 2020
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In this video, I have covered key expansion process of AES algorithm. How addroundkey steps will work in AES algorithm. If you are watching Key Expansion in AES then you can easily understand the AddRoundKey step of AES.
How round constant can calculate in key expansion process of AES.
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You made my life easy. Thank You so much with such a good explanation.
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Best video for that topic I have seen thank you
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This is the best explanation i have found! Thank you very much!
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Thank you! Very clearly explained and the visual presentation helps it all click!
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thanks for your effort, great video.
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V helpful thank u😊😊
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really it's too clear to understand💚
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share with others...
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Very well explained ✔
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Hello there very good explanation, helped me with my project, thank you very much. But i think in 6:02 the prime should be x^8 + x^4 + x^3 + x + 1 (0x011b). Try to get the module of x^8 with that prime and you will get the {1B}
Yes, you are right... it is irreducibel polynomial.... Plase share with others....
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Thank you sir
Welcome
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Sir, can you please clear if we use an S-box for key generation? If we do, how do we do so?
S-box is substitution box.... It is the first step of encryption process...
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Thank u so much
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hi sir can you explain how key expansion work for aes 192 and aes 256? Love this video!
Dear it is same as 128 bits.... Encryption rounds are increase only.... But everything same.....There is no changes...
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Nice
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Kow do you get the round ky on decryption? In a normal situation you have ciphertext and the key. No round key.
Round key in decryption is derived from the given key....
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@@ChiragBhalodia Thank you! Now my code is begining to work for ESP8266! :)
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Hey! where or how did you get the prime X^4+X+1? great video btw
that prime equation is used from Galois Field theorem...
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@@ChiragBhalodia I think the prime in GF(2^8) should be X^8+X^4+X^3+X+1, therefore we can have the remainder as X^4+X^3+X+1 after mod it when we're at RC9(X^8).
But anyways, it's still a fantastic video~thanks
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How we can get the key in initial stage ?
Key will be selected by user in initial stage..
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Hey man . the first round in decryption should not have the inverse MixColumns .
However it is a good explanation for key scheduling
Ohhh dear... Mix column and inverse mix column both are omitted from last round only.... It may be encryption or decryption....
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Sorry for late reply...!!!!
@@ChiragBhalodia i did not try it. but if the last step in encryption does not have a mix column and decryption is the reverse for encryption. so the last round in encryption should be the first round in decryption. so the first round in decryption should not have the mix column not the last round.
isn't it right?
The last round for encryption does not involve the “Mix columns” step. The last round for decryption does not involve the “Inverse mix columns” step.
As per my knowledge and reading from other sources...
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Great .. can u give me pppt slides
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