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To express **87 (decimal)** in **irreducible polynomial form** over \( GF(2) \), we need to: 1. **Convert 87 to Binary:** 87 (decimal) = **1010111** (binary). 2. **Interpret the Binary as a Polynomial:** In **GF(2)**, each bit represents a coefficient of a polynomial. For example: - \(1x^6 + 0x^5 + 1x^4 + 0x^3 + 1x^2 + 1x^1 + 1\). - This simplifies to: \(x^6 + x^4 + x^2 + x + 1\). 3. **Polynomial Representation of 87:** The binary **1010111** corresponds to the polynomial: \[ x^6 + x^4 + x^2 + x + 1 \] --- ### **Summary** So, the irreducible polynomial form of **87 (decimal)** is: \[ x^6 + x^4 + x^2 + x + 1 \] This polynomial can be used in AES or other algorithms requiring operations over finite fields \(GF(2^8)\).
Your word really motivete me do something extra ordinary...!!! Please share with others..... Please subscribe my channel....!!! Please follow my blog: chiragbhalodia.com
Thanks..... Please share with others.... Please subscribe my channel.... Please follow my blog: chiragbhalodia.com Also check AES Decryption example: th-cam.com/video/CTqvPze8uv8/w-d-xo.html
Thanks..... Please share with others.... Please subscribe my channel.... Please follow my blog: chiragbhalodia.com Also check AES Decryption example: th-cam.com/video/CTqvPze8uv8/w-d-xo.html
Hello Lora, Here I have used the irreducible polynomial theorem concept. So, x^8 is convert into x^4 + x^3 + x + 1. Why do I have to convert X^8? Because the maximum power should be x^7. Please follow my blog: chiragbhalodia.com Please subscribe my channel..
Mostly in examination they are given plain text in sentence form than you have to prepare matrix from that plain text.. Appreciate that, glad you found it helpful! Please share with others... Please subscribe my channel.... Please follow my blog: chiragbhalodia.com
Is the round key already defined or we are manually setting it for our project? And X^8 = x^4+x^3+x right? 1 is not there yeah? Like 1 was already there before using irreducible polynomial
Yes it is already defined....else you can defined manually also.... X^8 = x^4+x^3+x+1 is the irreducible polynomial. Sorry for late reply....!!!! Please subscribe my channel....Please share with others.... Please follow my blog: chiragbhalodia.com
Ohhh dear thank you so much for your query.... It was my typing mistake.... I am apolozige for that.....Thank you so much for watching my video in detailed....
For example, 47 is hexadecimal value.. So, 4 = 0100 & 7 = 0111. 47 = 0100 0111..... 46 (in hexadecimal) = 0100 0110 (Binary) and 46 (Decimal) = 0010 1110 (BInary)..... You also can check in online converter.... still if you have any query, you can join my telegram group Please share this video with others... Please subscribe my channel.... Please follow my blog: chiragbhalodia.com Sorry for the delayed reply....
Sorry for late reply...!!! I think this one is helpful: www.chiragbhalodia.com/2021/10/key-expansion-in-AES.html Please share with others.... Please subscribe my channel... Please follow my blog: chiragbhalodia.com
Sorry for late reply... This table is already defined when AES was implemented. Please subscribe my channel... Please follow my blog: chiragbhalodia.com
Round key is already given with the question... This is the encryption process using AES algorithm. AES Decryption Process: th-cam.com/video/CTqvPze8uv8/w-d-xo.html In exam, it may be asked find any one value of the 4x4 matrix. Please share with others.... Please subscribe to my channel... Please follow my blog: chiragbhalodia.com Sorry for late reply.
Sorry for late reply.... Predefined matrix is already defined.... Please share with others.... Please subscribe my channel... Please follow my blog: chiragbhalodia.com
Happy to hear that!...Thanks for watching..... Please share with others.... Please subscribe my channel... Please follow my blog: chiragbhalodia.com Sorry for late reply...._/\_
Please watch the video carefully. All four steps i have preformed during encryption process. Please Share this video with others... Please susbcribe my channel... Please follow my blog: chiragbhalodia.com
@@ChiragBhalodia I mean to say that this encryption is performed on plain text, in this specific example you began by working on a matrix instead of plain text how did you convert the plain text to this matrix
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watched this one night before examination. Explaned simply with good slideshow. Thank you sir.
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was just gonna skip the video because of being so long but this was the best explaination i've got so far...thank you so much sir!
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@@ChiragBhalodiasir please can you send me the prestation , i want it
Thanks sir
The best AES video i watched so far
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Outstanding Explaination 100/100👌🏻
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What a great explanation. 37:26
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very good explanation .👍 It is the best video for understanding AES 👍
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This is amazing, thank god i found your video ❤
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thank you so so much for this effort I really appreciate your effort
What a great explanation with slide show. Thanks a lot 👍👍
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What a great explanation.
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To express **87 (decimal)** in **irreducible polynomial form** over \( GF(2) \), we need to:
1. **Convert 87 to Binary:**
87 (decimal) = **1010111** (binary).
2. **Interpret the Binary as a Polynomial:**
In **GF(2)**, each bit represents a coefficient of a polynomial. For example:
- \(1x^6 + 0x^5 + 1x^4 + 0x^3 + 1x^2 + 1x^1 + 1\).
- This simplifies to:
\(x^6 + x^4 + x^2 + x + 1\).
3. **Polynomial Representation of 87:**
The binary **1010111** corresponds to the polynomial:
\[
x^6 + x^4 + x^2 + x + 1
\]
---
### **Summary**
So, the irreducible polynomial form of **87 (decimal)** is:
\[
x^6 + x^4 + x^2 + x + 1
\]
This polynomial can be used in AES or other algorithms requiring operations over finite fields \(GF(2^8)\).
87 is hex value... It is not in decimal...
Thanks for this amazing explanation sir 🤒🤲💙
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Damn, really rigorous! Great explanation.
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could u explain how did we get 47 for 01000111
Literally amazingg ❤❤❤❤
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Also check AES Decryption example: th-cam.com/video/CTqvPze8uv8/w-d-xo.html
amazing dear, great explanation
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Awesome vid man - good work
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Best video.. ❤should have done key expansion also
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Tysm Bhai, u made my day
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thank you very much sir
you're welcome..!!!
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Best video
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Also check AES Decryption example: th-cam.com/video/CTqvPze8uv8/w-d-xo.html
Thanku Soo much..I searched all the lectures on you tube..but it was the best❤❤
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Sir, how is x^8 equal to x^4 + x^3 + x + 1 (13:13 in the video) I didn't quite get that?
Hello Lora,
Here I have used the irreducible polynomial theorem concept. So, x^8 is convert into x^4 + x^3 + x + 1.
Why do I have to convert X^8?
Because the maximum power should be x^7.
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@@ChiragBhalodia take 2^8 = 2^4+2^3+2+1 is 128=27?
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sir will the question be asked in the 4x4 matrix FORMAT like u mentioned in the beggining? (EA , 04) or a plaintext will be given in different format?
Mostly in examination they are given plain text in sentence form than you have to prepare matrix from that plain text..
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Is the round key already defined or we are manually setting it for our project? And X^8 = x^4+x^3+x right? 1 is not there yeah? Like 1 was already there before using irreducible polynomial
Yes it is already defined....else you can defined manually also....
X^8 = x^4+x^3+x+1 is the irreducible polynomial.
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thankyou so much
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Why does 03 hex binary value keep changing from 0000 0011 to 0000 0110?
Ohhh dear thank you so much for your query.... It was my typing mistake.... I am apolozige for that.....Thank you so much for watching my video in detailed....
Hii Sir , Vishwa here
Sir what u took the value of 46 in binary is wrong if we convert it into decimal its 70 the binary for 46 is 0010 1110
For example, 47 is hexadecimal value.. So, 4 = 0100 & 7 = 0111. 47 = 0100 0111..... 46 (in hexadecimal) = 0100 0110 (Binary) and 46 (Decimal) = 0010 1110 (BInary)..... You also can check in online converter.... still if you have any query, you can join my telegram group
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Sorry for the delayed reply....
87 to binary is supposed to be "01010111"
I need clarification
87 (in decimal) = 0101 0111
87 (in hex) => 8 = 1000, 7 = 0111 so, 87 = 1000 0111
Last step ma Round key matrix kasa aii Ya bata da😊
Round key matrix already available form the first step only.
Sir please make a video on how to generate a 128 bit key
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Sir, how do you got round key matrix
Sir how did you write S Box permutation table?
will they give the table or prepare our own like the table in video 16*16?
It's a given table by the algorithms, dear
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This table is already defined when AES was implemented.
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sir, can u tell me how we got the round key in step 4, and can u please tell me the question for this example
Round key is already given with the question...
This is the encryption process using AES algorithm.
AES Decryption Process: th-cam.com/video/CTqvPze8uv8/w-d-xo.html
In exam, it may be asked find any one value of the 4x4 matrix.
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Sorry for late reply.
From where predefined matrix came? Whether it is given in question or we assume randomly in question?
Can anyone tell?
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Predefined matrix is already defined....
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thanks g
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Thanks
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Can you in last step how ac 77 comes mean 47 xor AC how ac comes?
I’ve never seen a perfect explanation like yours, thank you so much 🤍🤍🤍
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Sorry for late reply...._/\_
WHERE IS YOUR ADD ROUND KEY
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sir what was the plain text
Plain Text means our oiginal message.
@@ChiragBhalodia well I know that, but in this specific example what is the plain text which you're converting into cipher text
@@ChiragBhalodia I mean to say that this encryption is performed on plain text, in this specific example you began by working on a matrix instead of plain text
how did you convert the plain text to this matrix
sir
could u explain how did we get 47 for 01000111
47 is hexacecimal value.. So, 4 = 0100 & 7 = 0111. 47 = 0100 0111
@@ChiragBhalodiasir how did we know that 4 =0100 and 7=0111.how to know these values sir?
its just convert into binary number..... Do you know number system???? Binary, Octal, Decimal, Hexa Decimal?????
Sir can you give me the slides of this video plesse ?
Sorry dear slides are not avialble due to damage of laptop..
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❤❤❤❤❤
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Es main 10 rounds pory ho gae hain hain sir
No, this one is 1st round only. Still nine rounds are pending.
DES b bta do
I haven't solved example but I have just animated video....
Video Link: th-cam.com/video/3YBwhWuXZ0o/w-d-xo.html
What a great explanation.
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Thanks 😊
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Thanks
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What a great explanation.
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thank you so much
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What a great explanation.
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