AES: How to Design Secure Encryption

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  • เผยแพร่เมื่อ 20 พ.ย. 2024

ความคิดเห็น • 221

  • @joirnpettersen
    @joirnpettersen ปีที่แล้ว +565

    It would be really interesting to explain some of the candidates that didn't make it. For example show why some of the rejected algorithms weren't secure.

    • @dascandy
      @dascandy ปีที่แล้ว +85

      The remaining 5 were all considered "secure enough". Rijndael was the winner for simplicity, speed and hardware/software friendlyness. Serpent was chosen as backup since it resembles DES in its design (but uses 32 rounds, making it pretty slow), as it mitigated the risk of choosing Rijndael (with GF(2^8) arithmetic, relatively unstudied in the early 2000s). RC6, Twofish and the last one I can't remember were all also fine, but not preferred.

    • @dascandy
      @dascandy ปีที่แล้ว +23

      @yuvalne Chacha is much newer. From NIST: "The AES finalist candidate algorithms were MARS, RC6, Rijndael, Serpent, and Twofish". The AES competition started in 1998 and finished in 2001. Salsa was developed in 2005, and Chacha was created in 2008.
      Runner-ups aren't created a decade after the competition. That's not how time works.

    • @fdcrat
      @fdcrat 8 หลายเดือนก่อน +8

      It would be particularly nice to see a similar animation of Serpent. That algorithm was actually considered MORE secure than Rijndael, but it was slower to run.

    • @marc-andreservant201
      @marc-andreservant201 8 หลายเดือนก่อน +3

      ​@@dascandy Also Chacha is a stream cipher, which works in a completely different way. Essentially, it's a cryptographically secure pseudorandom number generator that you seed with the key and a nonce (number used once), and it generates arbitrarily long random bit sequences. The actual encryption is just a XOR of the Chacha output stream and the plaintext. If you reuse the same nonce then you get the same output stream which is really bad (but AES has the same problem, as mentioned at the end of the video you can't just encrypt each block in parallel with the same key, otherwise identical plaintext blocks will result in identical ciphertext blocks which is also bad).

    • @dascandy
      @dascandy 8 หลายเดือนก่อน +4

      @@marc-andreservant201
      > Chacha is a stream cipher, which works in a completely different way
      In its initial design, yes. But practically nobody (

  • @Luk3Pl4ys
    @Luk3Pl4ys ปีที่แล้ว +330

    Finally a simple enough yet comprehensive explanation of AES. I always wondered how this algorithm worked and you layed it out so well!

    • @cameron7374
      @cameron7374 ปีที่แล้ว +6

      @boohba It's 15 minutes of your time.
      I think that's endurable.

    • @minerva474
      @minerva474 ปีที่แล้ว +2

      @boohba most competent loli enjoyer

  • @phunanon
    @phunanon ปีที่แล้ว +42

    The use of the little robots is so engaging! SubBytes is oddly adorable in their mannerisms :D

  • @aprilmintacpineda2713
    @aprilmintacpineda2713 ปีที่แล้ว +59

    The clever use of graphics to illustrate the processes elevates the learning experience to a whole new level! Very well done!

  • @stephenj9470
    @stephenj9470 5 หลายเดือนก่อน +19

    Such a little thing, but the ability to portray so many emotions and reactions on the robots' simple faces is a nice touch. Looking down when we run into a problem, tilting the head when someone new is introduced, etc.

  • @tksnail6837
    @tksnail6837 ปีที่แล้ว +4

    I love how you used 'robots' to describe functions, and the way you arranged them at the end!

  • @MarekKnapek
    @MarekKnapek ปีที่แล้ว +58

    Great! Now continue with why simple AES encryption (ECB) is not enough in case of messages longer than 128bits. That's why cipher mode such as CBC exists.

    • @RemotHuman
      @RemotHuman ปีที่แล้ว +10

      They can also talk about authentication / AES-GCM which is the recommended version to use most of the time or so I've heard

    • @dojelnotmyrealname4018
      @dojelnotmyrealname4018 5 หลายเดือนก่อน +1

      That's technically out of scope of the AES algorithm directly and into Modes of Operation. It is valid though.

  • @erkinalp
    @erkinalp ปีที่แล้ว +24

    The underlying round function of AES also has the nice property of generalisation, namely, it can easily be adapted to a public key one or a hashing function just by modifying how the key modifies the input in AddRoundKey.

  • @slowedreverb6819
    @slowedreverb6819 ปีที่แล้ว +8

    I can't say how grateful I am, cause I was breaking my head to find good videos which I could understand easily, algorithm like MD5 and Sha 256 which teaches me and not just the same old crap. Thank you ❤❤

  • @vani_maki
    @vani_maki ปีที่แล้ว +2

    The best explanation of aes I've ever heard

  • @rileyn2983
    @rileyn2983 ปีที่แล้ว +13

    Great video! Very clear explanation. Would've loved to hear more about how key expansion works

  • @brandonmarks6
    @brandonmarks6 ปีที่แล้ว +9

    Best channel on youtube. Videos are always so clear and great subject matter.

  • @BritishBeachcomber
    @BritishBeachcomber ปีที่แล้ว +29

    Back in '95 I designed a password encryption algorithm based on XOR (exclusive or) logic. The company, AT&T NCR was sutilably impressed.

    • @sharpmouse3013
      @sharpmouse3013 ปีที่แล้ว

      wou

    • @Spirit_69
      @Spirit_69 9 หลายเดือนก่อน

      combined it with aes

    • @cigmorfil4101
      @cigmorfil4101 5 หลายเดือนก่อน

      How reversible were the passwords?

  • @Anythiny
    @Anythiny ปีที่แล้ว +1

    Loved that this guy has not stopped yet!! Thanku so much sir

  • @FerventApathy
    @FerventApathy 5 หลายเดือนก่อน

    You have no clue how helpful this is, and how extremely useful it is for what I work on. Thanks!

  • @isarow
    @isarow ปีที่แล้ว +2

    I haven't posted a single comment for a few years probably, but this video works so well for me that I have to say - very good explanation and thank you for this vid :)

  • @MichaelKubler-kublermdk
    @MichaelKubler-kublermdk 4 หลายเดือนก่อน

    This is the best explanation of AES I've come across.
    Thank you so much for putting this together!

  • @Stvk
    @Stvk ปีที่แล้ว +27

    this is like the only video explaining AES that i totally understand XD
    Also the visualize with box make my brain learn faster
    Good video as always, thanks you and the robots so much

  • @nicolasfuchs2678
    @nicolasfuchs2678 ปีที่แล้ว +1

    Started watching this channel and immediately recognized the voice from CS50 🤣 love your lectures, thank you!

  • @TomLisankie
    @TomLisankie ปีที่แล้ว +2

    Your videos are consistently great. I wish you would do them full time.

  • @gmnahin
    @gmnahin ปีที่แล้ว

    You are one of my favourite teachers on cs50❤❤❤❤❤

  • @conradludgate
    @conradludgate ปีที่แล้ว +28

    Ironically almost all cipher modes still use one-time pads as shown in the beginning, and we use AES or other keyed mixing algorithms to generate a consistent but unique random key stream.
    I guess it was concluded that diffusion of the plaintext isn't a useful property in the end. This only works securely if each message starts with a unique "initialisation vector" aka "nonce" though, to ensure each one-time pad sequence for each key-message pair is unique and can't be statistically analysed

    • @lancemarchetti8673
      @lancemarchetti8673 ปีที่แล้ว +2

      Interesting indeed.
      This also made me start looking into a better method of just one- pass id's for archives like zip, rar, 7z, lzh etc.
      In theory, by randomly changing the byte order in non-destructive areas of the file, the password field will still reject the correct password even it it were uncovered by tools such as Hashcat.
      The user lands up with a garbled extraction without the Byte Order Manipulation Key for that specific archive.
      Let's just call this the BOM-key for sake of explanation.
      I tried this yesterday on a simple lzh archive containg a PNG image.
      Without unlocking the correct byte order sequence, the extracted file was just a black square consisting of 1 color only. Yet the original image consists of 256 colors.
      After applying the byte order key
      (L4C361nf) for this specific file, the original image is extracted to its true representation.
      This is a work in progress but so far looks promising. I'm not aware of any current hack tools that can unpack a random BOM method, seeing that it's not based on any algorithm as such, making it difficult to determine a set obfuscation pattern.
      Your thoughts are welcome... 🙂

    • @conradludgate
      @conradludgate ปีที่แล้ว

      @@lancemarchetti8673 I wouldn't recommend coming up with a fancy non-cryptographic scheme like that. I would generally recommend using a stronger key.
      Designing from modern standards, I would use argon2ID13 to derive a large 256bit key from a password. You can configure the argon2 algorithm to take at least 1 second to derive on modern hardware and use large amounts of memory to make GPU based attacks redundant. I would then use AES-GCM-SIV or XChaCha20Poly1305 stream cipher algorithms to encrypt the files based on that key and a random initialisation vector. This is a fairly trivial construction and almost impossible to screw up assuming you have access to good libraries like NaCl (libsodium)

    • @dascandy
      @dascandy ปีที่แล้ว

      We nowadays look for a good keyed stream of pseudorandom bytes, which is then XORed with the plaintext to create the ciphertext. You can use any good block cipher in a construct like CTR or GCM to get exactly that. New designs will use the benefit of not needing a reversible setup (which Rijndael has, and was created with a Feistel network in the past to make designing it easier) to make them faster and/or better.

    • @dascandy
      @dascandy ปีที่แล้ว

      @@lancemarchetti8673 This approach relies on people not knowing or understanding the thing you're doing. Just changing the order of bytes is typically easily countered by statistics. I recommend cryptopals for its exercises to learn why these things are not a good design.

    • @quinnbattaglia5189
      @quinnbattaglia5189 ปีที่แล้ว +2

      A one-time pad is more than just using XOR, he didn't really explain that well. It's true that the common AES modes do use XOR but because they are not using a true-random key the same length as the plaintext they are not one-time pads.
      A real one-time pad is completely 100% unbreakable, AES is "just" practically unbreakable.

  • @usptact
    @usptact 5 หลายเดือนก่อน

    Thanks for the visual explanation! It was very clear how it works!

  • @kkgt6591
    @kkgt6591 ปีที่แล้ว +2

    Beautiful explanation

  • @prakash_77
    @prakash_77 ปีที่แล้ว +2

    Great explanation with great animation, as always.

  • @SuperLlama88888
    @SuperLlama88888 ปีที่แล้ว +2

    Wow, a very informative and easily understandable explanation! Well done!

  • @HbAli-s7q
    @HbAli-s7q หลายเดือนก่อน

    A well explained AES algo. Thanks a lot...

  • @sycamorerakka2184
    @sycamorerakka2184 8 หลายเดือนก่อน +1

    This is such a concise explanation and the animation is so cute! Thank you so much for your hard work!

  • @donchaput8278
    @donchaput8278 ปีที่แล้ว +3

    Amazing channel. Thank you!

  • @zix2421
    @zix2421 4 หลายเดือนก่อน

    I’ll even rewatch this, really interesting

  • @sunimod1895
    @sunimod1895 ปีที่แล้ว +1

    Excellent explanation and animations!

  • @eric-seastrand
    @eric-seastrand ปีที่แล้ว +1

    Great explanation- Seriously underrated channel. Happy I discovered you today. Subbed 😊

  • @AllamaHonnudike
    @AllamaHonnudike หลายเดือนก่อน

    Great content. Easy to understand

  • @yamanin.ninamay
    @yamanin.ninamay 8 หลายเดือนก่อน +1

    Thank you very much, the explanation was great

  • @VVayVVard
    @VVayVVard 5 หลายเดือนก่อน

    I watched some other videos first but ended up feeling confused since none of them explained the point of the various steps of the algorithm. Now everything makes more sense.

  • @harryrussell154
    @harryrussell154 8 หลายเดือนก่อน

    The Galaxy Cipher Machine: Unbreakable encryption using the Kaliko encryption method.
    Set up:
    A disc cipher machine on a spindle, the discs are like checkers in that they have notches to fit into each other. 1st wheel is the set disc with the numbers 1-80 scrambled, etched around the side, and on the top edge are three alphabets, scrambled the same, with two empty spaces to make 80 digits around the top. Each letter on the top is over a number on the side. There are 26 body discs, each having two rows (top and bottom) of 1-80 on their sides.
    The first message is a four number code: 1234. This is first a security check. The number 23 on the disc, 4 to the right, plus 1, gives you the security response.
    For the set up: The number one represents which set disc is to be used. The 23 is the number on the set disc that is under the letter on the top "E". This letter is the first body disc to be put on the spindle under the set disc. Depending on what the users invented for themselves, an even number goes left, odd/right. So the order of the body discs is the E first, then of right for the rest of the letter order for the discs. The body discs are like checkers in that they have notches for them to fit into each other. There is a dot on the bottom of the set disc somewhere between two numbers, and a dot on each side of each body disc as well. The last number of the 1234, the 4, is how many (left or right) notches to shift the discs as they are being put on using the dots as beginning points. 4 was invented to mean right for the dots so each disc has their dots spaced 4 notches to the right of the one above it. It is also decided/invented which discs go on up-side down. Once all discs are in place a tightening bolt is screwed on the spindle to secure the discs.
    Operation:
    In the coded message sent, the first 30 numbers are still part of the set up. The message follows after them. In these 30 numbers you have invented the pattern that if there are two number 6s in the 5th, 13th, 18th, and 29th numbers, the message is authentic. If there are more or less than two number 6s the message is bogus and is disregarded. In the first 30 numbers, you take the 4th and 9th numbers to know which algorithms to use, in this case both numbers are 12,34. You have invented at least 10 algorithms. The first message letter is O. Find an O on the top of the set disc in one of the alphabets (using another alphabet for the next O), and go down to the number below it on the edge, say 57. Now the first four algorithms are made up by the two users of the machines so they can be anything their imaginations can come up with. Like, from 57, down five discs to the top row of 1-80 where the number is 32, find 32 on the bottom row and go down 7 more discs and do the same, then go straight up to the set disc. 2nd algorithm is a diagonal angling down to the right 8 discs to the lower number on that disc-46, then finding the 46 on the top row, and straight up the to the top set disc. 3rd algorithm is another imaginative pattern ending at the top number 78 on the set disc. 4th algorithm now has a sleeve that fits over the machine with holes randomly drilled into its side lining up with each disc's number lines, 15 holes per line. Now look again to the first 30 numbers and see the 18th and the 62nd numbers are 36, and 84. So now the 78 is lined up with the 3rd disc's top number 6 hole, this shows the number 69 in the bottom number row hole 8. This continues for 4 discs to the last number 51 that is sent in to the other communicating person. (36, 84 is third disc, holes 6 and 8, for 4 discs)They run it all backwards to find the letter O.
    Throughout the sent message there are many OOs. The pattern invented is that you go six numbers beyond the OO to see if there is a number 5 in that number (75). If there is, you know it is a body disc shift. The other number is how many notches to shift each dot.(Odd numbers one way, even the other). Do this at least once every message. If there is a 2 in that number (27) it means to replace the set disc with another one, in this case the number 7 set disc. You replace the old one and just line up the dots of the new set disc directly over the dot beneath it on the first body disc. Do this at least once every message for both set and body discs.
    Another code invented tells you to change the entire order of the set up with a 4 digit set up number following it. Another code tells you to change the number of algorithms to use.
    Golden rules: 1) Never use the same set up code more than once. 2) Always send at least 15 phony messages for every one authentic message. 3) Always shift both the set disc and body discs at least once every message. This cipher machine has ever changing/shifting number patterns, an infinite number of invented algorithms that are used in different orders, a large number of algorithms to constantly change, and every set of machines has a different operation. Each operating set of machines have virgin discs no other machines have.
    This cipher machine cannot be broken, not even by the largest computers in the world if used correctly. The confirmation that a code has been broken is that the message appears. With a 500 letter message, if 500 GCMs are used where each machine only encrypts one letter, there is no confirmation the letter that comes up when trying to break it is the actual letter that is in the message. Every letter has a machine with different discs, different algorithms, and different operators encrypting it. So the most any attempt to break the code can do is acknowledge that each letter position could be any of the letters in the entire alphabet (A-Z). To write out the possibilities on paper would be to have an entire alphabet under letter position #1, then another one under #2, an so on. In the end there would be 500 alphabets in a row as the only clue to what the message says. A wall of alphabets. Its like telling the hackers there are 500 letters in the message and the words are in the dictionary. With this small bit of information it is IMPOSSIBLE to even begin to try to find the message. Not even the biggest computer in the world, working on it for 10,000 years could find the message.
    This encryption form is called KALIkO ENCRYPTION, it is unbreakable, and is perfectly suited for the Galaxy Cipher Machine.

  • @edwardnedharvey8019
    @edwardnedharvey8019 ปีที่แล้ว +1

    Great easy explanation

  • @arielcarloscanete2083
    @arielcarloscanete2083 ปีที่แล้ว +2

    Amazing explanation. Really appreciate the background on confusion and diffusion. Really puts context behind each step!

  • @1ups_15
    @1ups_15 ปีที่แล้ว +5

    I like your explanation of how the XOR gate works, I've never thought of it like that, thank you :D

    • @adissentingopinion848
      @adissentingopinion848 ปีที่แล้ว

      Also good for the various types of "masks" you can apply to a set of bits. (XOR bits) then (add 1) is the fastest way hardware can make a signed (2's complement) negative.

    • @cigmorfil4101
      @cigmorfil4101 5 หลายเดือนก่อน

      It's how the Lorentz cypher masked the bits of the text: it xclusive ored a generated 5-bit stream that was pseudo random with the 5 bits of the teletext code. As long as the decyphering machine was set up the same, a stream of text fed in at one end came out the other with the intervening transmission encrypted.

  • @df-hh7yd
    @df-hh7yd 2 วันที่ผ่านมา

    Really well explained

  • @YKLWEF
    @YKLWEF 11 หลายเดือนก่อน

    Really excellent presentation! Thanks.

  • @gamecom7784
    @gamecom7784 ปีที่แล้ว

    The best way to explaine ever ... thank you

  • @flameofthephoenix8395
    @flameofthephoenix8395 8 หลายเดือนก่อน

    8:45 Any block cipher that is always able to turn the encrypted data back to normal is just a big substitution cipher where for an input of any block combination it will substitute a different block combination.

  • @prabhus7517
    @prabhus7517 11 หลายเดือนก่อน

    Excellent tutorial. Thanks

  • @maph420
    @maph420 ปีที่แล้ว

    such a nice content you don't see everyday on youtube nowadays :)

  • @deanlongmire6166
    @deanlongmire6166 ปีที่แล้ว

    You couldn’t of uploaded this at a better time

  • @rodrigo-tj1gf
    @rodrigo-tj1gf ปีที่แล้ว

    Damn ! That's some good ass content, i can research for days and wouldn't come close to underestand stuff like that

  • @semmu93
    @semmu93 ปีที่แล้ว +1

    very informative video, thanks! do you plan to make a video about the fact that some encryption can be reversed via the same exact key? (i mean the technical requirements for that).

  • @jameshiggins-thomas9617
    @jameshiggins-thomas9617 5 หลายเดือนก่อน +1

    👍. You did, however, skip over another important property -- the ability to recover the plaintext using the key. 😉

  • @earnstein7607
    @earnstein7607 ปีที่แล้ว +4

    Yay!, We got a new video 🎉

  • @winston8589
    @winston8589 ปีที่แล้ว +4

    I love this kind of video please do more...

  • @keyboard_toucher
    @keyboard_toucher ปีที่แล้ว +8

    Another condition you need to add to make the system at 2:41 "perfectly secure" is that the key needs to be strong. In particular, I think it should have high entropy over all suitably short intervals. How short depends on how much the adversary knows about the plaintext. If the attacker knows absolutely nothing about the plaintext (i.e. considers it to be just random bits with no apparent meaning), then this isn't a problem. But that scenario isn't realistic--usually the plaintext has some obvious structure that the attacker is capable of predicting and recognizing (such as being English sentences), so a randomly chosen OTP key that just happens to contain a low-entropy burst can reveal a burst of information about the plaintext. Modern ciphers like AES avoid that issue by mixing up the bits instead of only XORing them with a (pseudo)random sequence.

    • @keyboard_toucher
      @keyboard_toucher ปีที่แล้ว

      @@dsdsspp7130 Ok, I randomly choose the key 0100000000000000000000000000000000000000000001000000000000000000000000000000000000000000000000110000000000000000000000000000000000000000010000 for my OTP. Still perfectly secure?

    • @thewhitefalcon8539
      @thewhitefalcon8539 ปีที่แล้ว +1

      How does the attacker know it's a "low entropy burst"? For that matter what is a low entropy burst? Is it when the key is like 111111? That's fine because the attacker has no idea if it was 111111 or 111112

    • @keyboard_toucher
      @keyboard_toucher ปีที่แล้ว

      @@thewhitefalcon8539 By "low entropy burst", I mean an interval of the key that has much lower entropy than expected. The attacker can know you have a weak key when (a portion of) the ciphertext has something in common with what he knows (or assumes) about the plaintext. For example in the case of OTP, if the ciphertext looks like random garbage except for a patch which looks a lot like plaintext, then you probably have a weak key. In general, a weak key makes a cipher easier to crack (the details of how depend on the cipher).

    • @dsdsspp7130
      @dsdsspp7130 ปีที่แล้ว +4

      @geoffmcqueen9955 when you have something that's truly random it's only natural that there are going to be "low entropy bursts" trying to avoid them would make the key less random and hence less secure.
      as long as the key is random, the cipher is going to be random and even if there is something that matches with what he knows, well that's just pure coincidence and not a leak.
      it's like the library of babel, it's random. does it contain the world's biggest secrets? yeah sure, but is there a way to distinguish between garbage and actual secrets? no, because it's random.

    • @keyboard_toucher
      @keyboard_toucher ปีที่แล้ว

      @@dsdsspp7130 Unfortunately, a key is not automatically strong simply because it was chosen at random. Various algorithms have their own kinds of weak keys, but what they all have in common is that they undermine the security of the cipher. If you XOR an English language novel with a random key and the ciphertext ends up containing a complete English sentence about what Harry Potter did at Hogwarts, we are going to take that as evidence that you somehow fucked up the encryption (e.g. by using a bad key)--the odds that this happened due to pure chance (and that Harry Potter is NOT part of the plaintext [or, accidentally, the key]) are far lower.

  • @esyra
    @esyra ปีที่แล้ว +1

    Thank you!

  • @ThatsWhatTheManWants
    @ThatsWhatTheManWants ปีที่แล้ว +2

    Cool video but i wish it showed the decryption step. As is, AES seems like a fancy hash. I cant fathom how youd do all of that backward again!

  • @dascandy
    @dascandy ปีที่แล้ว

    Nice explanation. Can you add a followup to how many rounds are chosen, with regards to full diffusion in N rounds and bidirectional impossible differential cryptanalysis?

  • @gunar3939
    @gunar3939 ปีที่แล้ว

    Excellent work 👏👏👏

  • @PaigeTArt
    @PaigeTArt ปีที่แล้ว +2

    Thanks for this cute video that lays out the subject so well, which I've found to be interesting but intimidating. The li'l robots are 👌

  • @shreeltrivedi5310
    @shreeltrivedi5310 ปีที่แล้ว

    Great explanation!!

  • @coldwinter1884
    @coldwinter1884 6 หลายเดือนก่อน +1

    Are you planning to do a video like this about TLS? I'd be perfect.

  • @atlasxatlas
    @atlasxatlas 5 หลายเดือนก่อน

    please make a followup showing how to decipher a cipher text with a key in AES

  • @mr_clean575
    @mr_clean575 ปีที่แล้ว

    I'd love to see a video explaining how quantum computers break encryption standards, and how other algorithms can work to protect against quantum computing.

    • @drdca8263
      @drdca8263 ปีที่แล้ว

      AIUI, it is mostly public key cryptography systems (where instead of one key used for both encrypting and decrypting, there is a public-knowledge key used for encrypting, and where there is a separate secret key which is supposed to be needed to decrypt the messages) that quantum algorithms have been found to break.
      I think all of these quantum based attacks (so far) use the quantum Fourier transform? But I’m not sure.

  • @muhammadazeemqureshi
    @muhammadazeemqureshi ปีที่แล้ว +1

    Great Video

  • @CursedOneShot
    @CursedOneShot ปีที่แล้ว +1

    Nice video !😀

  • @hrushik10
    @hrushik10 ปีที่แล้ว +1

    great video

  • @derroz3157
    @derroz3157 หลายเดือนก่อน

    AES is the ultimate formulae ever invented; some might call it a god

  • @dijikstra8
    @dijikstra8 5 วันที่ผ่านมา

    Very interesting! I was surprised that the subBytes step substituted bytes according to a pre-determined table, wouldn't it be better to use values from the round key for the specific step in order to add more confusion? But maybe that just becomes inefficient, you would have to figure out a way to expand the round key to 64k bits if I'm not mistaken in order to have unique substitution for each possible byte?

  • @mohrosyhaqqyaminy2394
    @mohrosyhaqqyaminy2394 ปีที่แล้ว

    Kesini gegara direkom mbak luth

  • @runnow2655
    @runnow2655 8 หลายเดือนก่อน +2

    why can't AES be generalized to higher sizes, like 512 bytes or 1024 etc etc?

  • @kaizorro03
    @kaizorro03 9 หลายเดือนก่อน

    Amazing video !

  • @wutdahack285
    @wutdahack285 5 หลายเดือนก่อน

    Great video

  • @Mucke454
    @Mucke454 ปีที่แล้ว +1

    Thank you goddammit

  • @thedew3083
    @thedew3083 4 วันที่ผ่านมา

    man i love you

  • @VISHWAp.s-w8v
    @VISHWAp.s-w8v 6 หลายเดือนก่อน

    thank you

  • @Rudxain
    @Rudxain ปีที่แล้ว +1

    It's funny that XOR-OTP is 100% guaranteed secure, but AES is only secure in practice, not in theory. Nobody knows if AES has some *hidden vulnerability* that reduces its effective security by orders of magnitude.
    Some small vulnerabilities have been found, but they reduce the effective security by ~5 key bits, not half of all bits

  • @superblaubeere27
    @superblaubeere27 ปีที่แล้ว

    Interesting. Why is the substitution important for confusion? Wouldn't just applying the round keys do a similar job?

  • @Amonimus
    @Amonimus ปีที่แล้ว +1

    How to decrypt all this sounds like a nightmare. Is AES key also an clue for how many rounds it took and what was shifted?

  • @hvnterblack
    @hvnterblack ปีที่แล้ว

    If I am correct, key is weakest point of that security system. It is in need to deliver it somehow to encrypet message reciever.

  • @EMEKC
    @EMEKC 8 หลายเดือนก่อน

    9:25 Knew those values looked familiar :)

  • @vanderkarl3927
    @vanderkarl3927 ปีที่แล้ว +1

    Wait, at about 10:10 it occurred to me that the process sounds a lot like a neural network, with sequences of linear and nonlinear transformations!

  • @magicmulder
    @magicmulder ปีที่แล้ว +2

    Great video.
    One note, it's pronounced RHINE-dahl, not RAIN-dahl.

    • @NootNooter
      @NootNooter ปีที่แล้ว +1

      [ˈrɛindaːl]

  • @tobias131314
    @tobias131314 ปีที่แล้ว +1

    👌

  • @NeinStein
    @NeinStein ปีที่แล้ว +3

    0:35 The phrase "One algorithm - Rijndael - won the competition" does sound like "One algorithm reigned all - won the competition". I cannot imagine this is an accident. Well done!

  • @flameofthephoenix8395
    @flameofthephoenix8395 8 หลายเดือนก่อน

    4:16 One really non-performant way to do it with just the simple XOR algorithm is to make the key an transcendental number that can be computed one digit at a time, then send a second piece of data for what digit you're on and so long as they don't know the transcendental number you can iterate through the digits of your number forever without them being any wiser this will of course be limited by how accurately you're computing and the number of bits used to tell the digit you're on, and you'd have to come up with a new transcendental number each time you want a new key.

  • @sannin9875
    @sannin9875 ปีที่แล้ว +1

    Do for Boyer moore algorithm like
    Fighting

  • @kuldeepaher4937
    @kuldeepaher4937 ปีที่แล้ว

    By hearing his voice was about to comment its brian from CS50 then in description foind out ohh its him 😅

  • @MissLiia07
    @MissLiia07 ปีที่แล้ว +2

    Yeay, a new video to learn from Brian. Thank you!

  • @chase14000
    @chase14000 ปีที่แล้ว

    can you make an animation about JWT authentication tokens? i still cant wrap my head around using it for logging in and logging out!

  • @PabloLewis-ve6ud
    @PabloLewis-ve6ud 6 หลายเดือนก่อน

    I loved thisñ

  • @juliemayhwang4469
    @juliemayhwang4469 6 วันที่ผ่านมา

    That would make sense as to why my thoughts a bit convulyuted

  • @mohammadalamin8910
    @mohammadalamin8910 ปีที่แล้ว +1

    The robots look like they're Wall-E and Eve's kids

  • @youtubeuniversity3638
    @youtubeuniversity3638 ปีที่แล้ว

    The biggest issue with making an AES I would say is the "S" section. Need to stop knowing the AES from working as the sole needed tool to break through it.

  • @microcolonel
    @microcolonel ปีที่แล้ว +5

    ChaCha/Salsa is much less complicated, much less interesting, and probably more secure in its standard configurations.

  • @fintech1378
    @fintech1378 ปีที่แล้ว +2

    is the narrator from CS50?

  • @4thalt
    @4thalt 8 หลายเดือนก่อน

    When it won the NIST contest, Rijndael reigned all.

  • @vishalpatel-uh1mz
    @vishalpatel-uh1mz ปีที่แล้ว

    Please upload java course +dsa

  • @notweewee
    @notweewee หลายเดือนก่อน

    How do you decipher this

  • @philipszeremeta2621
    @philipszeremeta2621 ปีที่แล้ว +1

    How is the key sent to the person you want to be able to “read” the message?

    • @Andrew-jh2bn
      @Andrew-jh2bn ปีที่แล้ว +1

      Currently? Diffie-hellman key exchange. As this method is vulnerable to quantum computers, there are alternatives being worked out. The most likely candidates are known as krystal kyber for key exchange, and Krystal dilithium for signatures.

    • @dascandy
      @dascandy ปีที่แล้ว

      @@Andrew-jh2bn Do you have a reference for DH being susceptible to quantum computers? Is that general DH or DH based on RSA problem?

    • @Andrew-jh2bn
      @Andrew-jh2bn ปีที่แล้ว

      @@dascandy I don't have a specific reference handy, but the method used is called shor's algorithm, I would start there. My understanding is that all diffie hellman key exchanges are vulnerable, not just rsa. Hence, the national institute of standards is in the process of selecting new quantum resistant key exchange methods.

  • @ToyTherapist
    @ToyTherapist 5 หลายเดือนก่อน +1

    Ok but how do you decrypt it?

  • @danysmorell
    @danysmorell ปีที่แล้ว

    Men, youuuu arrrrre awesome ❤

  • @nikilragav
    @nikilragav ปีที่แล้ว

    Seems like mix columns is pretty similar to the key expansion?

    • @dascandy
      @dascandy ปีที่แล้ว

      They're related operations; both use multiplications in GF(2^8) to modify the input values.