Yes, you can follow thru with the normal bernoulli sub, and since Ricatti has the y^2 term, this will always be be z^(1-2), or z^-1, which is 1/z. This is the reason why it is 1/z or z depending on the path you wish to take. When you solve for the linear portion of the bernoulli, you plug back in to find that 1/z = [whatever your result was]. In this case, you have 1/z = -2+ce^-x. So in the end, you are still doing the reciprocal. It’s the same, but I prefer doing the reciprocal at the end with Bernoulli instead of writing the fractions out when plugging in the y1(x) + 1/z into the starting equation. I’m just doing some differential equations for the hell of it, so this may have not reached you in time if you wanted to know this for a course you are taking 😅
@evwerenisaacoghenenyerhovw232 Ive explain how to reduce to Bernoulli in this ricatti video, so that's the introduction. Then you switch to this video th-cam.com/video/dB2S38weIeA/w-d-xo.html On Bernoulli
Please I have an article addressed ( Fast way to solve Ricatti equation) so y'_2y^2+3y=1 or y'=2y^2_3y+1 then A=2 , B=_3 and C=1 dy/dx+(2Ay1+B)y=_A (Alsultani DE 2) dy/dx+[(2*1*1+(_3)]y=_2 dy/dx_y=_2 I.F=e^int (_dx)=e^_x ye^_x=_2int e^_xdx+c=2e^_x+c y=2+ce^x , 1/y=1/(2+ce^x) y2=y1+1/y=1+1/(2 +ce^x) answer Short time and simple way .
Thank you very much I have 4 articles about the first order differential equations: 1- New method to solve the differential equations of the first order which consist of three terms . 2- Fast way to solve Ricatti equation. 3- New methods to solve some types of the first order differential equations. 4- Alsultani rules to find the particular solution of Ricatti's equation. These articles I published theme to help the students , mathematicians and the searchers. Note : I found that Bernoullies equation dy/dx+p(x)y=q(x)y^n is wrong so I put my differential equation dy/dx+P(x)y/n=Q(x)y^k , where k =1_n (Alsultani DE) instead of Bernoullies differential equation.
Thank you very much.
You are most welcome
Thanks a lot, keep it going
Nice and thanks for your words of encouragement
How to know it needs to subs y=y1+1/z?
Thank you
Here I considered that y1 is as a first point on the curve and y2 is the second.
Thanks so much sir
Have you figured it out?
Thank you sir! May I just clarify something, in the particular solution part, can I also use the bernoulli one to solve the problem?
Yes, you can follow thru with the normal bernoulli sub, and since Ricatti has the y^2 term, this will always be be z^(1-2), or z^-1, which is 1/z. This is the reason why it is 1/z or z depending on the path you wish to take.
When you solve for the linear portion of the bernoulli, you plug back in to find that 1/z = [whatever your result was]. In this case, you have 1/z = -2+ce^-x. So in the end, you are still doing the reciprocal.
It’s the same, but I prefer doing the reciprocal at the end with Bernoulli instead of writing the fractions out when plugging in the y1(x) + 1/z into the starting equation.
I’m just doing some differential equations for the hell of it, so this may have not reached you in time if you wanted to know this for a course you are taking 😅
Thank you sir
You are most welcome
Thank you so much sir
Most welcome
Sir thanks for everything but ı couldn't the the clairaut differential equations video. Is it available ?
my scholl was parallel to your videos until the end of bernouilli equations . Then ı couldn't clairaut.
Aww sorry about that....
Will you upload any video About that chapter or it is not possible. I'm Just looking forward to receiving your respond
❤thanks sir.
You are welcome
where did the Z^2 go? how does 3Z^2 on the left cancel out the 2Z^2 + 2Z^2 on the right?
It's actually 3z² cancelling out 2z² + z²
Oooww😅, got it now. Sorry about that
@@your1loner_Keys most welcome, good luck
What if y1 is not given? How can we solve that?
If y1(x) is not given, you need to find that by inspection and that is sometimes difficult to find, but usually it will be given.
Yes you can, but it's easier reducing to linear.
@@SkanCityAcademy_SirJohn Thanks for the clarification. Have a nice day ahead!
@allenycepicar5844 you are most welcome
How to know value of y1
Most of the time, y1 will be given
Sir I need a video on how to reduce from Ricatti to Bernoulli's sir
I think I explained that in the introduction, so after watching that on Bernoulli, you should know how to continue 🙏
@@SkanCityAcademy_SirJohn
I'm lost sir please
@evwerenisaacoghenenyerhovw232
Ive explain how to reduce to Bernoulli in this ricatti video, so that's the introduction.
Then you switch to this video th-cam.com/video/dB2S38weIeA/w-d-xo.html
On Bernoulli
@@SkanCityAcademy_SirJohn
I understood something sir but didn't get it correctly.. sir can I have your number please... I mean your WhatsApp no
Please sir I have a question on riccati I have tried my best but it not go please help me out
Can you tell me your actual problem?
Please I have an article addressed ( Fast way to solve Ricatti equation) so
y'_2y^2+3y=1 or
y'=2y^2_3y+1 then A=2 , B=_3 and C=1
dy/dx+(2Ay1+B)y=_A (Alsultani DE 2)
dy/dx+[(2*1*1+(_3)]y=_2
dy/dx_y=_2
I.F=e^int (_dx)=e^_x
ye^_x=_2int e^_xdx+c=2e^_x+c
y=2+ce^x , 1/y=1/(2+ce^x)
y2=y1+1/y=1+1/(2 +ce^x) answer
Short time and simple way .
Thanks so much for your insightful contribution
Thank you very much
I have 4 articles about the first order differential equations:
1- New method to solve the differential equations of the first order which consist of three terms .
2- Fast way to solve Ricatti equation.
3- New methods to solve some types of the first order differential equations.
4- Alsultani rules to find the particular solution of Ricatti's equation.
These articles I published theme to help the students , mathematicians and the searchers.
Note : I found that Bernoullies equation
dy/dx+p(x)y=q(x)y^n is wrong so I put my differential equation
dy/dx+P(x)y/n=Q(x)y^k , where k =1_n (Alsultani DE) instead of Bernoullies differential equation.