This is the single most helpful video ive watched in my entire life, my text book explains sn1 and sn2 as a bunch of arbitrary rules and this was so much easier to follow and understand
I wish you were my ochem professor! Absolutely fantastic break down of these mechanisms you are so helpful. Thank you for uploading your content and not putting it behind a paywall, you are why I'm not failing ochem.
You are such a nice teacher for uploading all the necessary stuff to learn orgo, I only need to watch your videos and don't need to search around or even pay for the material😭 thank you for saving my finals, I wish I could find your video early
studying for the mcat rn your stuff is amazing and i just found out abt it! love the simple and articulate explanations, is there a playlist on the different lab techniques for orgo to study for the mcat on your yt channel?
15:17 I understand you need to b neutral to consider deprotonation but you said “if possible”, does this mean not all neutral nucleophiles will deprotonate? What does it depend on how will I know if it does or not
Hello! I was wondering if you could substitute bromine in 1-bromopropane with KF for example. Does it depend on the solvent since F- is a stronger nucleophile in aprotic solvent and it's the other way around with protic solvents? Or will it happen regardless because Br- is a more stable anion? Awesome videos. I've watched like 5 in a row today!.
Great vid. Just a quick question about selectivity. Do the inversion of configuration and racemization only happen if the nucleophilic attack takes place at a chiral center, or if a chiral center is present at all? Like if there is a chiral center that isn't being attacked, would it invert configuration if Sn2 or racemize if Sn1? Thanks.
Hey Chad i have a question about the last example ( the one with the P), the reaction is SN2, yet we still have a carbocation but in SN2 reactions we dont have a carbocation . Why is this happening ??
I think it is because the neutral nucleophile could not be deprotonated, since there was'nt any hydrogen to deprotonate... so perhaps we should not confuse it with the carbocation that forms during an SN1 reaction. if you observe examples 2 and 3 , you'll realize that sir got neutral products , due to the fact that the alcohol nucleophiles lost their H atoms "deprotonated" upon attaching to the substrates.
Hey Chad, right around the 19 minute mark when the nucleophile attaches its self to the main compound, what happens to the Hydrogen thats connected to the oxygen. Does the oxygen lose the hydrogen or is the oxygen have a positive charge causing it to be able to have a triple bond?
Is this for the attack by isopropyl alcohol around the 17-18min mark? As I mention in the video, the nucleophile attaches and then is deprotonated right after it has attached. Temporarily you would have O with three single bonds (rather than a triple bond) causing a temporary positive charge on O. There is I- in solution as the leaving group which will assist in deprotonating the H leaving the final product.
![7.4 Introduction to Elimination Reactions [Zaitsev's Rule and the Stability of Alkenes] | OChemistry](http://i.ytimg.com/vi/oQPM9pAo0V8/mqdefault.jpg)
![7.4 Introduction to Elimination Reactions [Zaitsev's Rule and the Stability of Alkenes] | OChemistry](/img/tr.png)
This is the single most helpful video ive watched in my entire life, my text book explains sn1 and sn2 as a bunch of arbitrary rules and this was so much easier to follow and understand
Glad you found us!
I wish you were my ochem professor! Absolutely fantastic break down of these mechanisms you are so helpful. Thank you for uploading your content and not putting it behind a paywall, you are why I'm not failing ochem.
Glad the channel is helping.
Oh my god! it all makes sense now!! Thank you, I NEEDED this for my final tomorrow
Glad it helped, Caroline!
you’re amazing Chad! Thanks for the great and clear explanations. I’ve been studying for the MCAT with your lectures. aiming for a high score!
Glad the channel/video is helping you - Best on your MCAT!
You are such a nice teacher for uploading all the necessary stuff to learn orgo, I only need to watch your videos and don't need to search around or even pay for the material😭 thank you for saving my finals, I wish I could find your video early
Glad the channel is helping you - hope you do well on your finals.
You're the man Chad
Thanks, Younan!
You are really great Chad. Thumbs up
Thank you!
This video was extremely helpful! Thanks so much Chad
Very welcome!
Thank you so much for this amazing, detailed and clear series. Really helps me a lot studying for my first OChem exam
You're very welcome!
I mean you just make everything so easy to understand. THANK YOU!
You're welcome and Thank You!
What an outstanding lesson ,Thanks chad!
You're welcome and Thank You!
studying for the mcat rn your stuff is amazing and i just found out abt it! love the simple and articulate explanations, is there a playlist on the different lab techniques for orgo to study for the mcat on your yt channel?
thanks prof, this is so helpful and easy to understand when attention is paid to it.
You're welcome!
all your videos are so helpful ,thank you 👍
Great to hear it - You're welcome!
Thanks, Chad! This helped me a lot :)
Glad to hear it!
Glad to see u soon I have my exam
Hope you do well on your exam - Happy Studying!
Thank you so much, you guys are seriously the best
You're welcome - Thank you!
15:17 I understand you need to b neutral to consider deprotonation but you said “if possible”, does this mean not all neutral nucleophiles will deprotonate? What does it depend on how will I know if it does or not
this is very helpful.. are you planning on doing elimination also?
Yep! I will be releasing them in the next few days also!
Hello! I was wondering if you could substitute bromine in 1-bromopropane with KF for example. Does it depend on the solvent since F- is a stronger nucleophile in aprotic solvent and it's the other way around with protic solvents? Or will it happen regardless because Br- is a more stable anion?
Awesome videos. I've watched like 5 in a row today!.
Great vid.
Just a quick question about selectivity. Do the inversion of configuration and racemization only happen if the nucleophilic attack takes place at a chiral center, or if a chiral center is present at all?
Like if there is a chiral center that isn't being attacked, would it invert configuration if Sn2 or racemize if Sn1?
Thanks.
The effect is the same due to the back-side attack but there is no configuration to consider if there is no chiral center!
Best professor ever
Thank you
very helpful~ can you explain more about the deprotonation part and the neutral NUC thank you
Hey Chad i have a question about the last example ( the one with the P), the reaction is SN2, yet we still have a carbocation but in SN2 reactions we dont have a carbocation . Why is this happening ??
I think it is because the neutral nucleophile could not be deprotonated, since there was'nt any hydrogen to deprotonate... so perhaps we should not confuse it with the carbocation that forms during an SN1 reaction. if you observe examples 2 and 3 , you'll realize that sir got neutral products , due to the fact that the alcohol nucleophiles lost their H atoms "deprotonated" upon attaching to the substrates.
This is gold.
Glad you think so!
For the last one, could that tri-phenyl phosphorus be considered SN2 because its meso, and thus no racemization?
For example #6 would the major product form from the result of the carbocation shift and be the two racemic molecules?
Hey Chad, right around the 19 minute mark when the nucleophile attaches its self to the main compound, what happens to the Hydrogen thats connected to the oxygen. Does the oxygen lose the hydrogen or is the oxygen have a positive charge causing it to be able to have a triple bond?
Is this for the attack by isopropyl alcohol around the 17-18min mark? As I mention in the video, the nucleophile attaches and then is deprotonated right after it has attached. Temporarily you would have O with three single bonds (rather than a triple bond) causing a temporary positive charge on O. There is I- in solution as the leaving group which will assist in deprotonating the H leaving the final product.
Thank you.
You're welcome
Thank you so much
You're welcome.
Thank you ❤
Most welcome.
amazing presentation 10Q
Thanks!
Very helpful
Excellent!
are u a mesiah ?
legend
Thank you