14:08 made me chuckle, appreciate the help as always Mr. Chad! Got me through Gen Chem, and you are currently getting me through Physics and Orgo. If I ever see you in person, you'll receive the best handshake and hug known to man.
05:33 Since both these two examples are inverses of each other, how do we know which way it would progress? I mean, after the bromine leaves as bromide, leaving behind the carbocation, the most obvious thing it could do now is attack the carbocation and reattach it, being electrically attracted to it. So what makes it leave in the first place, if this creates charges? Shouldn't the opposite be more favorable? (cancellation of charges) And what is stopping it from reattaching back?
how come at 12:28 the second problem is a proton transfer, but the first problem is a nucleophilic attack. Why is it not going to be a proton transfer for both since both take a hydrogen from the other molecule? I am assuming the nucleophilic attack is that one since it breaks a bond and forms another, and the proton transfer is that since it does not break a bond to form another, but that is my guess and not a for sure answer.
At this point I’ve left my professor behind😂 Chad’s prep all the way
Glad you are finding the videos useful, S.P.!
awesome shirt and thanks so much for helping with organic chemistry! your videos have saved countless students :D
Great to hear!
14:08 made me chuckle, appreciate the help as always Mr. Chad! Got me through Gen Chem, and you are currently getting me through Physics and Orgo. If I ever see you in person, you'll receive the best handshake and hug known to man.
Glad to hear you're enjoying the videos :)
Another legendary video. Thank you!
Appreciate your comments, as always!
thanks so much for your help king you made this very understandable :)
You're very welcome, Roxana - thanks for commenting!
i have a final exam in a few days thats heavy in Ochem, just started watching your video and so far its been very clear.
Hope you do well on your final!
At 12:41, the oxygen in the carbonyl loses its lone pairs during the reaction. What happens to those lone pairs?
nothing happend. just not drawn
05:33 Since both these two examples are inverses of each other, how do we know which way it would progress? I mean, after the bromine leaves as bromide, leaving behind the carbocation, the most obvious thing it could do now is attack the carbocation and reattach it, being electrically attracted to it. So what makes it leave in the first place, if this creates charges? Shouldn't the opposite be more favorable? (cancellation of charges) And what is stopping it from reattaching back?
I think it depends on the products
From the products you work backwards and see what could’ve happened
I love the shirt! Great video also.
I agree with you completely Emile; the shirt is more noteworthy than the video!😉 Happy Studying!
@@ChadsPrep Amen to that!
how come at 12:28 the second problem is a proton transfer, but the first problem is a nucleophilic attack. Why is it not going to be a proton transfer for both since both take a hydrogen from the other molecule? I am assuming the nucleophilic attack is that one since it breaks a bond and forms another, and the proton transfer is that since it does not break a bond to form another, but that is my guess and not a for sure answer.
This is the best organic chemistry channel. It really helped me understand organic chemistry, making it enjoyable to learn more
Excellent!
Love you Chad!
Thanks Hu and much appreciated! Glad you're finding these helpful!🙂
Great video! Thank you so much 😊
You're welcome and Thank You.
you are truly the best ever
Thank you!
so helpful!!
Awesome Mia! Glad you found this lesson helpful!
Saw you had a fair amount of subscribers and checked out your channel...can I suggest one more hair style for short hair?!😜
Chad's Prep haha 😁
l love youuuuu
muah
Glad the channel is helping you.
How did you know all that???
Probably the same way for most - with lots of time and study.
رائع 👏
Welcome to the channel.
as long as I watch I get more ashamed of my exam paper...
Sir l don't know you are busy or not but lhave some questions relevant to chemistry can you answer my questions sir g if you become free😊
Sure! You can ask questions under the relevant videos