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Oxford Mathematics Plus
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เข้าร่วมเมื่อ 1 ก.ค. 2020
Oxford Mathematics second channel. Everything you love from the main Oxford Mathematics channel, PLUS livestreams, seminars, and miscellaneous maths videos.
MAT 2021 | All questions | MAT Livestream Bonus
MAT 2021 | All questions | MAT Livestream Bonus
มุมมอง: 11 724
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MAT 2020 | All questions | MAT Livestream Bonus
มุมมอง 14K2 ปีที่แล้ว
MAT 2020 | All questions | MAT Livestream Bonus
Infinity and Infinity Machines | Maths & Philosophy
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Infinity and Infinity Machines | Maths & Philosophy
MAT Livestream 2020 #018 | Maths-only edit | CS with Isaac
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MAT Livestream 2020 #018 | Maths-only edit | CS with Isaac
MAT 2019 | All questions | MAT Livestream Bonus
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MAT 2019 | All questions | MAT Livestream Bonus
MAT Livestream 2020 #017 | Maths-only edit | CS with Maaike
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MAT Livestream 2020 #017 | Maths-only edit | CS with Maaike
MAT 2018 | All questions | MAT Livestream Bonus
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MAT 2018 | All questions | MAT Livestream Bonus
MAT 2017 | All questions | MAT Livestream Bonus
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MAT 2017 | All questions | MAT Livestream Bonus
MAT Livestream 2020 #016 | Maths-only edit | Tricky multiple-choice questions
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MAT Livestream 2020 #016 | Maths-only edit | Tricky multiple-choice questions
MAT Livestream 2020 #015 | Maths-only edit | Curve sketching and graphs
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MAT Livestream 2020 #015 | Maths-only edit | Curve sketching and graphs
MAT 2016 | All questions | MAT Livestream Bonus
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MAT 2016 | All questions | MAT Livestream Bonus
MAT Livestream 2020 #014 | Maths-only edit | Polynomials and Algebra
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MAT Livestream 2020 #014 | Maths-only edit | Polynomials and Algebra
MAT Livestream 2020 #013 | Maths-only edit | Sequences and Series
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MAT Livestream 2020 #013 | Maths-only edit | Sequences and Series
MAT Livestream 2020 #012 | Maths-only edit | Geometry and Trigonometry
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MAT Livestream 2020 #012 | Maths-only edit | Geometry and Trigonometry
MAT Livestream 2020 #011 | Maths-only edit | Differentiation and Integration
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MAT Livestream 2020 #011 | Maths-only edit | Differentiation and Integration
Three problems | Problem Solving Matters
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Three problems | Problem Solving Matters
MAT Livestream 2020 #010 | Maths-only edit | Bonus problems
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MAT Livestream 2020 #010 | Maths-only edit | Bonus problems
Four problems | Problem Solving Matters
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Four problems | Problem Solving Matters
MAT Livestream 2020 #009 | Maths-only edit
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MAT Livestream 2020 #009 | Maths-only edit
MAT Livestream 2020 #008 | Maths-only edit
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MAT Livestream 2020 #008 | Maths-only edit
MAT Livestream 2020 #007 | Maths-only edit
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MAT Livestream 2020 #007 | Maths-only edit
MAT Livestream 2020 #006 | Maths-only edit | Q6 special
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MAT Livestream 2020 #006 | Maths-only edit | Q6 special
MAT Livestream 2020 #005 | Maths-only edit
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MAT Livestream 2020 #005 | Maths-only edit
Reading my personal statement | MAT Livestream Bonus
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Reading my personal statement | MAT Livestream Bonus
Sir I scored about 60% in my 11th class and I'm in 12th currently. i have a really good extracurricular and I've done a lot of researches going to colleges and universities. Am just scared about my 11th grade marks, what should I do about it? Will i be rejected on the basis of 11th grade marks?
We accept Year XII qualifications with CBSE or CISCE boards. Please see www.ox.ac.uk/intquals for standard conditional offers based on international qualifications. ^James
Any idea why Imperial switched to TMUA from MAT?
1:42:56 I like to think of any inverse function like this. e.g. y = sqrt(x), I draw x= y^2 so i rotate my paper pi/2 anti-clock wise and then draw x = y^2 and remember that the negative of y-axis on this horizontal line is actually on the right instead of left and so i flip the graph on the line y = 0 automatically then chose the domain of y that makes it a function. :) Thinking of this and when you said 2 reflection = 1 rotation. I observe 1 rotation and a reflection = 1 reflection? I will go investigate this observation.
Hello, thank you for the lesson. By the way, you look like Tobey Maguire.😁
Can I get into ms computer science in oxford with scholarship by just clearing this exam only? Or should do anything else??
Hi - this is just one part of the application process. Candidates also apply on UCAS, and may be invited to interview. Please see www.ox.ac.uk/apply for details of the application process. ^James
at 41.25, i believe that the answer should be (1+root 5)/2 it cannot be (1- root 5)/2 since root 5 > root 4 (2) and 1- root5 /2 will be a negative no the question is only asking for positive roots
Hi James, Should I apply to oxford if my a levels equivalent did not go well due to health issues and i will be giving improvement exams(an additional exam in my country to increase our score if we are not satisfied with them ) during my gap year
Hi - sorry to hear about the health issues. There's information about international qualifications at www.ox.ac.uk/intquals . I can't advise on the strength of applications before they've been made - tutors look at the information in context. ^James
Q12: is it not just (3/10) * (7/9)? As in 3/10 is probability for 1st contestant to be chosen and 7/9 is probability for 2nd one not to be chosen.
That gives you the right answer, but why have you said 7/9 rather than 7/10? So yes, but I disagree with the word just! 7/9 is the probability of something quite subtle - it's the probability for the 2nd contestant not to be chosen given that the 1st contestant has already been chosen, which is a bit harder to explain. ^James
wIll we know the marks allotted to the MCQ questions
Yes, it's displayed as part of each question. ^James
Will the 2-mark and 3-mark multiple choice questions be designed to be quicker and/or easier than the 4 mark questions? Will the 4-mark questions be a similar difficulty to past multiple choice questions and the 2/3 mark questions easier/quicker? Or is another system being used?
No comment on the difficulty of the questions, sorry! I'll note that we compare candidates' scores to the average score, so that if the average score ends up being a bit higher or lower than the previous year, that doesn't make any difference to the admissions process. ^James
Will the 2-mark and 3-mark multiple choice questions be designed to be quicker and/or easier than the 4 mark questions? Will the 4-mark questions be a similar difficulty to past multiple choice questions and the 2/3 mark questions easier/quicker? Or is another system being used?
No comment on the difficulty of the questions, sorry! I'll note that we compare candidates' scores to the average score, so that if the average score ends up being a bit higher or lower than the previous year, that doesn't make any difference to the admissions process. ^James
How will people from outside of UK give the MAT then
There are Pearson VUE centres in pretty much every country in the world; I believe you can get more info about registering and whatnot on Pearson's website when they upload info about the Oxford Admissions Tests.
Got it thanks a lot I realised later that my city has a few centres too
In light of the MAT changes this year, will a new sample paper/s be released? I understand that many MAT revision resources exist, but it may be helpful to help people get a feel for the new format - e.g what 2 or 3 mark multiple choice questions might look like, as well as timings for the exam.
As per the slides around the 10:00 mark, there will be practice test on the website soon, to give people a feel for the format. This uses past MAT questions. ^James
1:29:46 note that you dont have to take the factor of -6 out of the constant term, it'll work just the same, makes it simpler for me personally
That's a fair point! ^James
You might notice that the audio on the Eurovision clip is weird. That's because it's been flagged for copyright infringement, and one of the options was to remove the song but keep other audio. Because the video I'm playing is the live version, but the copyright claim is for the studio version, you're hearing an AI's impression of one minus the other. I thought this was the funniest option. ^James
Is the dimensions aspect of the frog problem to do with countable infinities?
Is this for ma/ MSc mat paper?
This is for our undergraduate degrees. For information on graduate admissions, please see www.ox.ac.uk/admissions/graduate ^James
thank you for all your help sir!
I haven't looked this up, so this might be very wrong, but I think this amounts to the chopping list (heh) being "more" recursive, i.e it grows really fast, very fast so that it can't be represented in Peano Arithmetic. As you mention, the bad strategy is so bad that it grows insanely quickly, and hence it can't be understood within Peano Arithmetic, you need at least general recursive functions (which are equivalent to anything turing complete, so you basically need to reason about general programs). Fun fact, there's no programming language that can model only all programs that always terminate. You can have programming languages that always terminate, but they'll always miss some terminating programs. Hence, we need the big guns (general recursive functions) to be able to discuss such an algorithm (probably)
i flopped my second mat terribly 4/10 wehn i was doing practise tests with 9/10s and a gold in ukmt
a question about this oomc playlist, are the knowledge assessed in MAT? if I am preparing for mat would it be a goo d idea to go through theses videos first before doing past papers? thanks
Nope - the MAT syllabus is very short, available at www.maths.ox.ac.uk/r/mat , and has absolutely nothing to do with OOMC. This is just for fun and perhaps to help you with a personal statement or EPQ :) ^James
@@OxfordMathematicsPlus Hi James, i love your videos and your attitude towards both mathematics and teaching. I am currently in year 12 can you give me some advice on how to prepare for MAT and how to best study the content on the syllabus? Thank you very much. (I am actually in a sixth form in oxford)
@@anaklusmus Hopefully you're already studying the content in A-level Maths or equivalent! If you want a revision resource, you might like the flashcards and worksheets we made for www.maths.ox.ac.uk/r/matlive ^James
Just got rejected Tuesday😭
😢^James
Who’s excited and also scared for Tuesday when we hear back from
I surely am lol
Hello, Prof. Munro. I'm one of the authors of the mean row paper. I wanted to point out something that I think is very important that you did for the students. Mathematicians typically only present a polished product; we rarely get to see how the sausage is made. In my case I can say that I've built a paper tower monument in my office containing all of my wrong proofs, dead ends, and verifications, but you might not get that impression from reading a paper. From reading the results you would not get a sense of how much time was spent staring at a wall trying to dream up a solution to a roadblock or how many hours were spent at a board with others discussing ideas. I think it was important to show your thought process as you covered a paper and its results. This is something we definitely all do, but maybe it doesn't come across that way. It was a great presentation and an important lesson. Cheers!
Hi, thanks for getting in touch! It's a cool paper. Your comments remind me that back in the day, someone I worked with once got feedback along the lines of "I used to think that all mathematicians were super-smart geniuses until I met you", and I thought that was (1) hilarious (2) worth trying to imitate. ^James
Wow I really like how Jonah explained those concepts. I really think he could do well teaching Maths on TH-cam or as a teacher.
brb sending this to Jonah ^James
woooo looking forward to this
Btw, a fun extension of primes into the complex numbers (of course) is the Gaussian primes, where basically any number with integer coordinates is considered, and any number on the unit circle is excluded. Then, you just do your normal calculations, but importantly factorisation is unique up to a sign (-1, i, -i), which isn't that big of an issue since you can extract it into a separate "thing" and still prove a lot of really cool things.
We did an episode of OOMC on Gaussian primes a couple of seasons ago! Worth it just for the cool diagram you can draw of where they are... th-cam.com/video/P8cRz24Iugo/w-d-xo.html ^James
Happy new year 🎉 Thanks Prof. James for starting another season of this cool maths series. 😊
🎊we're back🎊^James
29:02 rear
24:18 AI is also a word
2:02:08 true...Moral luck and the peculiarity of blame...
How do you get better at identifying the direction they’d like you to go in, starting and progressing through these questions? Is it just through exposure to questions outside the general AL questions? They are very different to any EQ I’ve ever seen.
i put in the worst application probably ever to oxford and got rejected😀
what made it the worst lol
Hi James, I received an interview for Computer Science, but it says my interview is for a Tier 1 subject. I am aware, that the Oxford website does say that you may be given a lower tier than what your subject traditionally is, however, this seems like a significant difference. I'm just wondering if this is correct? Thanks so much for all the live stream help btw!
My advice: Find all x,y intercepts, behaviour as x-> +- infinity , any poles - that's all you need to connect the dots and plot a coherent sketch to a complicated function in less than a minute
missed the stream :( and no stream this week
When will mat b results will come
When are you gonna post additional mat solutions
From what I saw during live chat, James said that he was quite busy but aimed to have the solutions next week.
Oh no I missed the stream
Oh my God the egg problem is giving me Further Maths flashbacks. I think this is the Eularian and Semi-Eularian graphs right? Route inspection or something it's called? Edit: nvm lol seems like I ran into the same misconception as everyone else. It's really funny how common that is.
Всем удачи!!
How much weighting is going to be put on the additional MAT? Would a 9/10 MAT additional get an interview with a poor first MAT
Actually don't answer, I have found answer. Sorry James
@@theosullivan6975 What was the answer?
@@yeet1532 the answer wasn't completely explicit but he says in the livestream just before they start doing questions that any student who did badly first time and well second time they will view as someone who was probably quite disrupted. A kind of 'ideal scenario' for the retest. I think this implies that you are quite likely to get an interview (depending on how well you did in retest) However, Oxford don't know how high of a mark will be good in this test.
@@theosullivan6975ahh that makes sense, thank you
I had to wait up to 2 and a half hours before my test started, almost 6 hours of sitting in a cold test room, I'm 100% retaking
I know this is very late to the party but you tube has just suggested this to me and I wanted to share my thoughts! I'm very surprised that the stream concluded that (1+sqrt(2))^2023 was also close to a whole number. It seems to me that you can't just conclude that it works for one large number then it woks for all. eg if (1+sqrt(2))^2022 was close to a whole number then (1+sqrt(2))^2023 can't be since it is (1+sqrt(2))^2022 multiplied by approximately 2.4. I've not done the maths on paper but I think that if you rigth the small number as (sqrt(2)-1)^2023 and you are adding that to the original then it is more clear that the first term on each side is sqrt(2)^2023 and that they don't cancel and that the second term is going to have sqrt(2)^2022 and will be positive in the first expansion and negative in the second and thus cancel. So in this case all the whole numbers cancel leaving only multiples of sqrt(2). Disclaimer: this maths was done in my head so the later maths might be wrong but the idea that raising to any power can't always be close to a whole number seems like a sound idea!
This comment is a bit late, so you may have resolved your issues by now. The (1+sqrt(2))^n term being close to a whole number made sense to me when looking back at the whole number equation, namely (1+sqrt(2))^n + (1-sqrt(2))^n The first step, of course, is to convince yourself that this will add up to a whole number. If you use the Binomial Theorem, it can be shown that the odd powers of sqrt(2) will cancel each other out from the 2 different expressions, while the even powers will be added to each other. The even powers are simply powers of 2, so the sum is a whole number. From there, note that 1 < sqrt(2) < 2. This means that -1 < 1-sqrt(2) < 0. As n increases, we keep multiplying the second term by a number that's between -1 and 0, so the second term is getting closer and closer to 0. Since we know that the sum of the two terms is equal to a whole number, this means that (1+sqrt(2))^n must be getting closer and closer to a whole number as n increases.
@@enerjae7174 Your problem there is that the "whole number equation" that you have used isn't right. If you want to add (1+sqrt(2))^n on the right hand side then when you multiple top and bottom by (1-sqrt(2))^n then the top comes out to (1-sqrt(2))^n but the bottom comes out to -1^n. So for even n then you are adding (1-sqrt(2))^n but for odd n then you will be subtracting it. So in the even case the whole numbers compund and the squre roots cancel but for odd n its the other way around, the whole numbers cancel and the square roots compound. The confusion really stems I think from the fact that you are adding 1-sqrt(2) which is a negative number. It is a lot more clear if you write it as sqrt(2)-1 (and also sqrt(2)+1 for the main part). Then the bottom is always 1 for n odd and even and it can be much more easily seen which terms cancel and which don't. ie the first term for both will be sqrt(2)^n, then the next terms cancel, then you'll have a sqrt(2)^n-2 term and so on. Then it is much more obvious that if n is even you will have a whole number and if n is odd you will have a multiple of a power of 2. So essentially rather than the first step being to convince yourself that it will add to a whole number your first step should have been to convince yourself that your "whole number equation" was actually correct for all n!
@@ChrisVenus By the Binomial Theorem, (a+b)^n = Σ(n nCr k)a^(n-k)b^k (as k goes from 0 to n, but idk how to format that here) This means that (1+sqrt(2))^n can be plugged in with a=1 and b=sqrt(2), and (1-sqrt(2))^n has b=-sqrt(2). So, summing the two terms is now equivalent to Σ(n nCr k)(sqrt(2))^k + Σ(n nCr k)(-sqrt(2))^k (Here, I chose to not write 1^(n-k) in both sums since it will always be 1) When k is an odd number, the terms will cancel out because of the negative from the second term. When k is even, the second term becomes positive because of the negative, so we get 2Σ(n nCr k)(sqrt(2))^k . Since k is even, sqrt(2)^k will be a power of 2, so the entire sum will be a whole number. Is there a step I can make more clear for you?
@@enerjae7174 I get what you are saying - you are being perfectly clear but your argument is only true for even n. The term on the right hand side that you are adding has (1-sqrt2)^n divided by (-1)^n. In the video (and in your analysis) this factor of -1^n was missed and the bottom of the right hand part was mistakenly said to always be 1. For even n this is true but for odd n that evaluates to -1 so you are subtracting your two binomial expansions from each other. So when they are subtracted the exact opposite happens. When k is even the term on the right is positive so when subtracted from the left it cancels. When k is odd the term on the right is negative so when it is subtracted the two negatives cancel and you add. So you only get the terms when k is odd which is going to be some multiple of sqrt(2) so most definitely not a whole number.
@@ChrisVenus I'm a bit confused where you're getting the (-1)^n. I'm specifically testing if (1+sqrt(2))^n + (1-sqrt(2))^n is a whole number. I've plugged in a=1 for both terms and b=±sqrt(2), so there is no (-1)^n that I'm using anywhere.
I have been following your lectures for my MAT preparation. Will following these lectures and practicing all previous year questions be suffiient
Hi Dr James , like i asked in a previous video , could you tell looking at the level of the paper what the mu-3 score(average of those who were made offers) will be this year, last year it was around 75 , could you perhaps give a rough estimate for this year's mat after analysing the difficulty.
Great stream thank you very much
for the resit of mat, is it a full paper or just multiple choices?
It will be 10 multiple choice questions in the style of a Q1