Common Emitter Amplifier - More-Intuitive Math - Simply Put

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  • เผยแพร่เมื่อ 13 ก.ย. 2024
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ความคิดเห็น • 26

  • @KilobyteCobra
    @KilobyteCobra 3 ปีที่แล้ว +7

    The math for stuff like this has always been presented to me in the past in ways that made me feel like I didn't have the background I needed to make sense of it. This video is a fantastic resource and, in just 25 minutes, makes sense of what, otherwise, seems very complicated.
    "It's just Ohm's law applied a whole bunch of times." - words like that do a fantastic job of taking the fear and mystery out of stuff like this. Keep up the awesome work and I hope to see more!

  • @shrekyboi4776
    @shrekyboi4776 5 หลายเดือนก่อน

    This is an incredible explanation of something I've been having so much trouble understanding in the last few days. Thank you so much for taking the time to give us such great videos on this topic.

  • @shvideo1
    @shvideo1 3 ปีที่แล้ว +3

    I love this practical circuit design. Such a great video because it is tremendously and practically educational. It is great for building things, which many theoretical only videos and books fail to accomplish and quench our enthusiasm at the same time. Thank you for thinking this through and putting it together!

  • @witchdoc94
    @witchdoc94 2 ปีที่แล้ว +1

    This is by far the best explanation of Common Emitter Amplifier component calculation, thx 1000 times. Greetings from France.

  • @donschlonzo7124
    @donschlonzo7124 ปีที่แล้ว

    Finally i got my answer. I testet Vcc/2, (Vcc-VRe)/2 and your method, (Vcc-VRe-VBe)/2 in LTSpice.
    Your method works best, it allows for the maximum "swing".
    Thank you a lot!

  • @beauyoung9241
    @beauyoung9241 3 ปีที่แล้ว +1

    Excellent explanation! As a complete electronics novice trying to make a simple amplifier, this was so useful

  • @adastra123
    @adastra123 2 ปีที่แล้ว

    Brilliant 👏 👏 👏 👏 👏. Not alone do you explain it brilliantly but you also empower people like me to feel more confident in our lives.
    Thank you so much. May you live long and be loved.

  • @keithgreiner2686
    @keithgreiner2686 2 ปีที่แล้ว +2

    Who is this excellent presenter? I would be interested to see a presentation on the calculations for an FET amplifier circuit.

  • @ScienceGuy60223
    @ScienceGuy60223 ปีที่แล้ว +1

    Thanks for this whole video series! Also this is good stuff here, setting the resistance based on the intended power target helped clear up the confusion I was having when other tutorials were selecting random resistor values.

  • @TrebleWing
    @TrebleWing 2 ปีที่แล้ว

    You introduced the key for me that made everything I already knew click..... The power target step and using that to get a current was like magic. Exactly what I was missing

  • @parapos
    @parapos 5 ปีที่แล้ว +1

    another great explanation in detail. thank you. I think this was the most difficult (but understandable) "math video" so far...… sometimes listening to you feels like listening to a professor in a university..... (knowing way much more than it seems at first glance)

  • @fredflickinger643
    @fredflickinger643 ปีที่แล้ว

    Consider the venerable 2N2222A Small−Signal Current Gain
    (IC = 1.0 mAdc, VCE = 10 Vdc, f = 1.0 kHz) (IC = 10 mAdc, VCE = 10 Vdc, f = 1.0 kHz)
    hfe
    50-75 (Min)
    300-375
    (Max)

  • @marc.brunelle
    @marc.brunelle 2 ปีที่แล้ว +1

    Thank you so much for this video! This is a godsend. I’ve been trying to learn more about tube/transistor amplification and all your videos on amplification are perfectly explained. I’ve watched this video here at least 10 times. This needs to get embedded into my brain. I shall watch it even more.
    Also, do you have any plans to make a video on the concept of emitter bias? I’m also interested in tube amplification, and they often use cathode bias resistors which, if I’m understanding this whole thing correctly, should be similar to emitter biasing in a transistor.

  • @simonyoungglostog
    @simonyoungglostog 2 ปีที่แล้ว

    I've just subscribed to your channel. I was wondering why we use a factor of '10', for the current available in the Voltage Divider for the Base?

  • @elijaheisenman6903
    @elijaheisenman6903 ปีที่แล้ว

    That's good that's good that's gooooood

  • @leandroskalogerakos7135
    @leandroskalogerakos7135 10 หลายเดือนก่อน

    Just discovered your videos. Simply amazing explanations. Congratulations!!!
    I have a question: you said that best practice is to make the vamp rail drain at least 10 times more current than what goes through the base of the transistor. So you ended up choosing a 310ohm and 1330ohm resistor for r2 and r1. What i cannot understand is this: The Ibc (current from base to emitter) is what controls the Ice (current from collector to emitter), and not the opposite. Since we chose a 1330ohm for r1 , don't we let 9v/1330=6,77mA pass through the base eventually? Ok, not exactly that much because we have the Re as well in series, but definitely a lot more than 550uA we wanted in the beginning.... And then, since Ibe is going to be about 6ma , then Ice=b*Ibe=100*6=600mA , and not 55mA... An order of magnitude more... How does this not happen eventually?

  • @johnreid2975
    @johnreid2975 5 ปีที่แล้ว +1

    I give it about a year and your channel is going to blow up.

    • @4mb127
      @4mb127 3 ปีที่แล้ว +2

      Sadly, it's taking a lot more than that, but I really like this channel.

  • @silvertongues2
    @silvertongues2 2 ปีที่แล้ว

    hey, this is an amazing explanation and is helping me hugely, seriously I've been trying to get my head around all this and was about to make animal sacrifices in order to help, thats not good, i'm a vegetarian. I do have a question though about Rc calculation, @9:00 you say Rc is calculated by taking 3.65v (Vrc) and dividing it by 55ma resulting in 67ohms. However in the summary @21:30 you write on the board that Rc is equal to Vre (ie 1v) divided by Ic..... did you mean Vrc? Thanks again.

  • @stevegoodjob5902
    @stevegoodjob5902 2 ปีที่แล้ว

    Can I get this amplification with ic amplifier without going through all this?

  • @JDPavon
    @JDPavon 5 ปีที่แล้ว

    Thank you, again for the way you explain, It's realy simple an clear.
    Could you make a practice with real stuff and the oscilloscope, please..
    I need to see the amplification of a wave with an transistor.

    • @simplyput2796
      @simplyput2796  5 ปีที่แล้ว +1

      Yep, I've got that as one of the upcoming videos. I'm working now on videos demonstrating the beta-independence and power-supply-ripple-rejection of the amplifier. I'm sorry I'm so slow at putting out videos; They are coming though!

    • @JDPavon
      @JDPavon 5 ปีที่แล้ว

      @@simplyput2796I'm not trying to rush you, it's just that I've been doing amplification circuits in the Multisim program, in order to better understand what you explain in your videos, and I do not see amplification at all. I really think I'm doing something wrong.
      On the other hand I really appreciate your videos and I thank you very much for the time you take to make them.
      As allways, many thanks.

    • @simplyput2796
      @simplyput2796  5 ปีที่แล้ว

      Here's a simulator set up to show the effect. www.falstad.com/circuit/e-ceamp.html But I will still do videos on it too of course.

    • @JDPavon
      @JDPavon 5 ปีที่แล้ว

      @@simplyput2796 Thank you.

  • @geetikasrivastava2296
    @geetikasrivastava2296 4 ปีที่แล้ว

    thanks