Integral cos^(-1)(x)

[@gracepeyer7253]

thank you i was about to put a fist-sized hole into my laptop

[@zanecantuba9338]

i feel that

[@luigianchondo7241]

🤣🤣🤣 at least I’m not the only one that think like you.

[@SilverLady52]

Same! lol Glad I'm not alone.

[@D_N_H_bilkul]

Why??m

[@arrowfence4]

thank you my good sir you are amazing

[@TheMathSorcerer]

Happy to help:)

[@isabellamontoyaserna9158]

señor lo quiero mucho, gracias

[@phillipeffertz6346]

Thank you! Calc 2 is giving me a headache.

[@royalewithcheese9257]

Straight to the point as always. Thank you!

[@SilverLady52]

Very helpful! Thank you for posting this.

[@TheMathSorcerer]

You're very welcome!

[@a.ricole4081]

This helped me a lot. Thank you very much!

[@rafaelpolo6023]

Excellent explanation

[@-jakenandez9380]

Thanks man, good explanation

[@niceguy909]

thank you king

[@husnaa7483]

But the answer is x.arccosx-sin(arccosx)+c in our book. Which is true this or that ??

[@lakavathsurya4907]

Both are same but arc cosx in the sense cos inverse x arc means inverse

[@tantelou2996]

Um... Why did you use integration by parts? Don't you need two functions to be multiplied for that? I don't think dx is a function or maybe I'm dumb.

[@scottwillard7998]

You have to see an invisible one represented in front of the dx so we can get x by integrating. This also goes for integrating lnxdx where u = lnx and dv = 1dx

[@vijayyadav8865]

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[@certifiedsmartass4122]

@@vijayyadav8865 😬😬😬

[@KausPaus]

multiplied by 1

[@husendrakunal5427]

@@vijayyadav8865 im from also....

[@sanko.a2756]

How will we know which one to put as U and what as dv??

[@MarwaAhmed-bs8ic]

شكرااا جدا لحضرتك

[@a.s.6495]

Thank you so much!

[@christianmoray1842]

Thank you

[@BhuvaneswariDannina]

Thank you sir

[@devilkazuya2001]

Im confused. I thought cos^-1(x) is the same as sec(x). Cant you just use the derivative sec(x) how did you get 1/(1-x^2)^1/2??

[@nicolasfierro2143]

that’s the confusing part cos^-1 is not the same as sec. cos^-1 undoes cos the ^-1 doesn’t actually take it to the -1 power it’s very bad notation

[@RufusFinnick]

el coseno a la menos uno cos^-1(x) no es igual a 1/cos(x) = sec(x), la INVERSA DEL VALOR de coseno es sec(x), mientras que su FUNCION INVERSA es cos^-1(x) o arccos(x), la función inversa te sirve para sacar el valor de angulo si sabes cuando vale cos(x) = z entonces cos^-1(z) = x.

[@nicolasgoossens832]

this made me not squeeze my dog

[@ryanchurchman9017]

I love you

[@TheMathSorcerer]

😀

[@xuexiang7456]

Wow

[@itz_Sachin_Gola]

🤔🤔🤔🤔

[@pratikjethwa8701]

Cos^-1 (cosx) dx ?
What's d solution?

[@rudyoactiv]

1

[@pratikkumbhar1608]

x(dx)

[@husendrakunal5427]

X^2/2

[@Souvikviveds]

🌝🌝🌝

[@toastygetthatbred5839]

thank you so much!