Work as area under curve | Work and energy | Physics | Khan Academy

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  • เผยแพร่เมื่อ 12 พ.ย. 2024

ความคิดเห็น • 21

  • @MintTree1
    @MintTree1 3 ปีที่แล้ว +5

    This video is gold. I wonder why it doesn't have more views.

  • @weenewman8123
    @weenewman8123 6 ปีที่แล้ว +6

    i love this guys so much.He thinking like he is student.
    .

  • @ffhashimi
    @ffhashimi 7 ปีที่แล้ว +3

    Excellent explanation!

  • @sricharanabd1787
    @sricharanabd1787 7 ปีที่แล้ว +1

    Very nice to think differently

  • @BlackMambaKO
    @BlackMambaKO 7 ปีที่แล้ว +3

    How do you calculate time needed to perform work from the graph given?

  • @physicstyco8631
    @physicstyco8631 4 ปีที่แล้ว +1

    Really it's good

  • @jdsaaa66767
    @jdsaaa66767 8 หลายเดือนก่อน +1

    beautiful

  • @gandra2091
    @gandra2091 3 ปีที่แล้ว +1

    dobar dan profesorka

  • @isabela6967
    @isabela6967 6 ปีที่แล้ว +1

    thank you !!!

  • @mahreenkashif2137
    @mahreenkashif2137 4 ปีที่แล้ว +1

    Well done ..😊😊

  • @sayantannaskar1916
    @sayantannaskar1916 6 ปีที่แล้ว +1

    Good explanation

  • @jessicaaurellialorenz5165
    @jessicaaurellialorenz5165 2 ปีที่แล้ว

    Isn't work a scalar quantity? Which mean that the direction doesn't matter and thus the work done for the last problems is 5J?

  • @meseretasfaye6844
    @meseretasfaye6844 3 ปีที่แล้ว

    Nice

  • @swathynatarajan5560
    @swathynatarajan5560 7 ปีที่แล้ว +3

    Isn't the entire infinitely small rectangle thing just using calculus, as in taking a Riemann integral?

    • @Dreamsai_
      @Dreamsai_ 7 ปีที่แล้ว +1

      Swathy Natarajan Well some Physics does require Calc.

    • @ruskodudesko9679
      @ruskodudesko9679 7 ปีที่แล้ว +2

      yeah pretty much. In physics you use calculus and the work done by a varying force is the integral of Fxdx from x1 to x2.

  • @vijaysinghchauhan7079
    @vijaysinghchauhan7079 6 ปีที่แล้ว +1

    Wait a min. At 11:26 you can't have -1J of workdone. Coz if your hamburger moves to the right(+) that meant you are applying a force in the rightward direction (+) or if your hamburger moves left(-) that meant you must be applying leftward (-) force. Hence, the work done is positive.😎😎

    • @karenlewis6750
      @karenlewis6750 6 ปีที่แล้ว +2

      There's an error in the explanation. You would get this plot if the hamburger were already in motion (moving to the right) and you were applying a negative force (to left) to slow it down a bit then eventually pushing it to the right. The graph is correct and the result is correct, but the explanation is not correct.

    • @iconic410
      @iconic410 4 ปีที่แล้ว +2

      You have negative work done when it is in the negative direction(in this case left). He states at 9:59 that the hamburger was initially pushed to the left at a negative velocity(negative because left). Then it starts getting pushed to the right. The overall energy ended up being positive because there was more work done over more displacement in the positive (right) direction.

    • @mr.noname6109
      @mr.noname6109 4 ปีที่แล้ว +1

      @@karenlewis6750 that's right.

  • @meseretasfaye6844
    @meseretasfaye6844 3 ปีที่แล้ว

    Nice