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Awesome!
The answer is in my head...😂😂😂. Anyway, thanks for the video.
4ˣ+25ˣ=10ˣ.10 -> (4/10)ˣ + (25/10)ˣ = 10 -> (2/5)ˣ + (5/2)ˣ = 10 with (2/5)ˣ = z -> z + 1/z = 10 -> z² + 1 - 10z = 0 -> z= [10±√(100-4)]/2 (with 96=16.6) -> z=5±2√6 -> (2/5)ˣ = 5±2√6 -> x = [log(5±2√6)/log(2/5)]
Голова МЕШАЕТ!
> (2/5)^x+(5/2 )^x=10;Take (5/2)^x=m; thensolve=>for (5/2)^x; >>x= {log(5±2√6)}/(log5-log2)
log (5)=log (10/2)=log(10)-log(2)=.... ? log5-log2=...?
@marcobsomer5574 log5-log2 ≈.69897- .30103= .39794
МОЖНО НЕ ВЕРТЕТЬСЯ ПЕРЕД ДОСКОЙ И ВЗЯТЬ УКАЗКУ В РУКИ!
shuruaat Se Hilog Le Lena chahie thaItna Lamba khinchne kijarurat Nahin thi
Awesome!
The answer is in my head...😂😂😂. Anyway, thanks for the video.
4ˣ+25ˣ=10ˣ.10 -> (4/10)ˣ + (25/10)ˣ = 10 -> (2/5)ˣ + (5/2)ˣ = 10 with (2/5)ˣ = z -> z + 1/z = 10 -> z² + 1 - 10z = 0 -> z= [10±√(100-4)]/2 (with 96=16.6) -> z=5±2√6 -> (2/5)ˣ = 5±2√6 -> x = [log(5±2√6)/log(2/5)]
Голова МЕШАЕТ!
> (2/5)^x+(5/2 )^x=10;
Take (5/2)^x=m; then
solve=>for (5/2)^x; >>x= {log(5±2√6)}/(log5-log2)
log (5)=log (10/2)=log(10)-log(2)=.... ? log5-log2=...?
@marcobsomer5574 log5-log2 ≈
.69897- .30103= .39794
МОЖНО НЕ ВЕРТЕТЬСЯ ПЕРЕД ДОСКОЙ И ВЗЯТЬ УКАЗКУ В РУКИ!
shuruaat Se Hilog Le Lena chahie thaItna Lamba khinchne kijarurat Nahin thi