I personally really appreciate these videos. All of them are well thought out and easily understood. You are an excellent teacher and a clear speaker. I know these kinds of videos take up your time and I really appreciate you sacrificing time from your life to upload stuff like this. In my opinion it's no small thing to do the videos you do. It's really helping me and I'm sure many others. Keep doing what you're doing. You definitely deserve more subs than you have. Subbed.
An aircraft flying straight and level has a load factor of 1. Load factor of 1 means lift force is counteracting the weight with the same amount of force (2000lbs of lift, 2000lbs of weight) 0 would be weightless just like astronauts that can fly without any lift force since there's no weight in the first place. Load factor is lift/weight, therefore in a turn of an aircraft the lift force is going to be divided into two forces: the vertical lift (holding the aircraft aloft) and the horizontal lift (making it turn). Since vertical lift is decreased in a turn as it's shared with the horizontal lift to make it turn, weight force (that always points towards the center of the earth, even in a turn) is going to be greater than vertical lift and the aircraft descends. In order to maintain altitude we need to increase the Angle of Attack to compensate for the decrease in vertical lift. Doing so will increase the total lift (both vertical and horizontal lift) and this is where the load factor of 1 increases since the total lift is greater than the weight force (Load factor = Lift/weight). Since the load factor increased, means we're maintaining altitude at a higher angle of attack than normal to compensate for the decreased vertical lift in a turn, doing so will increase the stall speed because we are closer to reach the critical angle of attack at a higher airspeed than at straight and level (1G). This is called accelerated stall, the more load factor you have the higher airspeed you will stall. To find the % of increase of airspeed in a specific load factor just add a square root to the load factor number: Load factor of 2: √2 = 1.41 You will have an increase in 41% of stall speed. Using the chart example at 1G stall speed is 64 airspeed. 64 x 1.41= 90 airspeed. At 2 load factor you will stall at 90 airspeed Just found this video randomly, not really sure why drone pilots need to understand this, sure you do if applying for airplane license
Great video, thanks! Easiest way for me to remember this is to replace the fuzzy term “load factor” with the word “weight”. So, looking at the graph it is immediately obvious that if your aircraft gets heavier, you gotta go faster, else you will fall out of the sky. It’s a gravity thing. That’s why earth-orbiting satellites need to go really fast to keep from falling to the earth. Just my .02, I may be wrong, but that’s the mental model I use to keep this lesson in my brain.
Wow, Mr. Mig! Thank you for your help. Who knew that finding out the weight of an aircraft on a bank turn could be as simple as multiplying the weight of the aircraft by the load factor. Mind blown. I'll be tuning in for more videos. I'm gonna ace (hopefully) this exam! Thanks!
The fundamental concept to note is cross multiplication. Easy and straightforward if you use that term when looking for more information. At least that’s how I do it. Normal weight over 1 (x/1) cross multiplied with (to find) your unknown load factored weight (y -what we are finding) over specified load factor(x - from the question) (y/x)
![ประสบการณ์ จ้าง Developer ที่ผมจะไม่มีวันลืม [ภาค1]](http://i.ytimg.com/vi/bzivN4KDg-k/mqdefault.jpg)
I personally really appreciate these videos. All of them are well thought out and easily understood. You are an excellent teacher and a clear speaker. I know these kinds of videos take up your time and I really appreciate you sacrificing time from your life to upload stuff like this. In my opinion it's no small thing to do the videos you do. It's really helping me and I'm sure many others. Keep doing what you're doing. You definitely deserve more subs than you have. Subbed.
Thanks Hunty! That means a lot!
An aircraft flying straight and level has a load factor of 1. Load factor of 1 means lift force is counteracting the weight with the same amount of force (2000lbs of lift, 2000lbs of weight) 0 would be weightless just like astronauts that can fly without any lift force since there's no weight in the first place. Load factor is lift/weight, therefore in a turn of an aircraft the lift force is going to be divided into two forces: the vertical lift (holding the aircraft aloft) and the horizontal lift (making it turn). Since vertical lift is decreased in a turn as it's shared with the horizontal lift to make it turn, weight force (that always points towards the center of the earth, even in a turn) is going to be greater than vertical lift and the aircraft descends. In order to maintain altitude we need to increase the Angle of Attack to compensate for the decrease in vertical lift. Doing so will increase the total lift (both vertical and horizontal lift) and this is where the load factor of 1 increases since the total lift is greater than the weight force (Load factor = Lift/weight). Since the load factor increased, means we're maintaining altitude at a higher angle of attack than normal to compensate for the decreased vertical lift in a turn, doing so will increase the stall speed because we are closer to reach the critical angle of attack at a higher airspeed than at straight and level (1G). This is called accelerated stall, the more load factor you have the higher airspeed you will stall.
To find the % of increase of airspeed in a specific load factor just add a square root to the load factor number:
Load factor of 2: √2 = 1.41
You will have an increase in 41% of stall speed. Using the chart example at 1G stall speed is 64 airspeed. 64 x 1.41= 90 airspeed. At 2 load factor you will stall at 90 airspeed
Just found this video randomly, not really sure why drone pilots need to understand this, sure you do if applying for airplane license
Great video, thanks! Easiest way for me to remember this is to replace the fuzzy term “load factor” with the word “weight”. So, looking at the graph it is immediately obvious that if your aircraft gets heavier, you gotta go faster, else you will fall out of the sky. It’s a gravity thing. That’s why earth-orbiting satellites need to go really fast to keep from falling to the earth.
Just my .02, I may be wrong, but that’s the mental model I use to keep this lesson in my brain.
Wow, Mr. Mig! Thank you for your help. Who knew that finding out the weight of an aircraft on a bank turn could be as simple as multiplying the weight of the aircraft by the load factor. Mind blown. I'll be tuning in for more videos. I'm gonna ace (hopefully) this exam! Thanks!
i really appreciate them as well. they are really beneficial from my point of view. they help break things down in a better way for me.
Good video; Thanks.
All of that went over my head.
Hi sir,
I have really important question what would a helicopter V-n diagram looks like?
Thank you
Does this calculation work with any number. For example, what if the number was 41 or 42 or even 39, which load factor number would I multiply by.
The fundamental concept to note is cross multiplication. Easy and straightforward if you use that term when looking for more information. At least that’s how I do it. Normal weight over 1 (x/1) cross multiplied with (to find) your unknown load factored weight (y -what we are finding) over specified load factor(x - from the question) (y/x)