Understanding Common Mode Rejection Ratio

[@Kenobiii]

I'm getting into RF engineering and your videos help me soooooo much to understand many of the concepts a lot better!!!! It's all explained so well and clear, thank you so much!

[@pauldenisowski]

Thank you! I sometimes tell people that I'm making the videos I wish that I had when I started in engineering :)

[@Floyd..B]

​@@pauldenisowski And you are doing a perfect job at that.

[@waferlayout]

真強你

[@sharifmostaqhye7753]

Thanks very much for sharing this very helpful presentation.

[@MarioVladutTino]

What I don't understand, is that if noise is present in both inputs of the OA, when you subtract them, you should see 0V. So i do not understand why it's amplified.

[@AdrianBoyko]

Same here

[@KingdomAddict]

Thank you for the lectures; they are very helpful, thank you. Question: Should Vout be Adm(V2-V1) instead of Adm(V1-V2) shown in the video?

[@pauldenisowski]

Yes - thank you for catching that. Vout is Adm * (Vplus - Vminus). In retrospect, I should have used Vplus an Vminus instead of V1 and V2. Thanks again for the correction!

[@stud_mechatronic_polito_22]

thank you, now it's clearer; I was getting crazy with that indian accent -_- but apart the indian accent "all about electonics" is a great yt channel.

[@nareshkumar4207]

Thanks for this good lecture

[@pauldenisowski]

Thanks for the feedback!