I used T network in a BMS for an UPS Pb battery pack. T network allowed to prevent the battery from discharge through the measurement front end input resistance. Thanks for the video!
Hi sir, In 1:51 min, you are using the ratio needed for the differential amplifier to work as we need, it seems that the ratio should be R2/R1=R4/R3, please correct me if i'm wrong. Thank you for a great lecture again !
Very nice presentation! The advantages and disadvantages of the first two methods were explained in some detail, while the third method was given, but with less information on performance relative to the first two methods. This is left as an exercise for the (lazy) viewer, which is fine.
@@sambenyaakov Thank you in turn for your precious work here on TH-cam. It helps a lot of engineers in getting better. People like you make the world a better place.
Sam... another nice lecture, expanding on the old, dusty textbook. 😋😋 Now, if you could circle back to the elaplace based ferrite model? I'm not lazy; I just don't have it in LTSpice.... Or, is it possible by using laplace in the LTSpice B model?
I actually came across several papers where they float the opamp to the higher voltage and use a zener to create a voltage difference at the high voltage which is used to power the opamp. The output is connected to fet which supposedly produces the currwnt on a sense resistor. I think i will try that too😄
Sir, why not use an instrumentation amplifier which has inherently good common mode rejection capabilities and is less susceptible to component (resistor) deviations
Hi Srinath, Instrumentation amps are basically a differential amp with buffers. They do not have, inherently, high common mode volt capability. The common mode is generally restricted to the power supply range. CMRR does not imply high Vcm withstanding.
I had never looked at this topology before. Thank you for the excellent presentation.
Thanks for comment
I used T network in a BMS for an UPS Pb battery pack. T network allowed to prevent the battery from discharge through the measurement front end input resistance. Thanks for the video!
Thanks for sharing.
Hi sir,
In 1:51 min, you are using the ratio needed for the differential amplifier to work as we need, it seems that the ratio should be R2/R1=R4/R3, please correct me if i'm wrong.
Thank you for a great lecture again !
Indeed, this slide has a typo. Thanks for bringing this up.
Very nice presentation! The advantages and disadvantages of the first two methods were explained in some detail, while the third method was given, but with less information on performance relative to the first two methods. This is left as an exercise for the (lazy) viewer, which is fine.
You got it. Home work!
Hi Prof. Ben-Yaakov. I think that in minute 2:31 in equetion bellow should be (R3+R4) / R3. The missing is "4". If I am wrong please correct me.
You are correct. Thanks for spotting the error and commenting.
If you take the method #3 and turn the star circuit r2, r5, r6 into a triangle circuit, you get the method #2.
HI, Frunse Thank you for the enlightenment. Never thought about that.
@@sambenyaakov Thank you in turn for your precious work here on TH-cam. It helps a lot of engineers in getting better. People like you make the world a better place.
Great!!...Thank you for sharing
👍😊
Sam... another nice lecture, expanding on the old, dusty textbook. 😋😋
Now, if you could circle back to the elaplace based ferrite model? I'm not lazy; I just don't have it in LTSpice.... Or, is it possible by using laplace in the LTSpice B model?
Yes, you can use Laplace in LTspice B models.
Excellent video!
Thanks
For the battery monitor, wouldn't a microcontroller per cell be cheaper and also handle switching in the balancing circuit?
Not really. You need precision voltage measurement and isolated communication between units.
Great video!
Thanks!
Second to none!!
Thanks
Thanks a lot!
👍🙏
@@sambenyaakov can u recommend me a topology I can build on my own which does not require tight resistors?
@@bsuryasaradhi6816 Just build the basic topology. The accuracy of the resistors will determine the common mode error.
I actually came across several papers where they float the opamp to the higher voltage and use a zener to create a voltage difference at the high voltage which is used to power the opamp. The output is connected to fet which supposedly produces the currwnt on a sense resistor. I think i will try that too😄
@@bsuryasaradhi6816 as in our patent 😊www.freepatentsonline.com/20230125811.pdf
Hello, Professor. I am currently designing an inverter application. Is it possible that I could discuss some doubts I have with you?
You can write to sby@bgu.ac.il
Sir, why not use an instrumentation amplifier which has inherently good common mode rejection capabilities and is less susceptible to component (resistor) deviations
Hi Srinath, Instrumentation amps are basically a differential amp with buffers. They do not have, inherently, high common mode volt capability. The common mode is generally restricted to the power supply range. CMRR does not imply high Vcm withstanding.
ערוץ מעולה יש לך ידע נרחב
👍