Power calculation for inclined belt conveyor

Belt Pull and Power for Inclined Conveyors

[@thapliyalsk]

Very genuine way of designing conveyor for a specific purpose, people never come to know what is the actual power required to convey a specific material up a required height. You have given a situation. Thanks. I also design conveyors

[@ashutoshsuthar3753]

Best explaination ever.

[@Ryohgantz]

Thank you for sharing the tutorial.
I wanna ask a question, how to determine the power of the conveyor if our conveyor has a horizontal and inclined also ?
Is it possible to combine their two calculation or there is another kind of calculation ?

[@thapliyalsk]

Very simple add Power for the inclined portion

[@mohanbabu2609]

Sir if Conveyor length 50 mtrs means total length of belt approx 100 mtrs we have to take full length of belt for weight calculation or half length

[@thapliyalsk]

Only the carrying side you have to consider

[@vijeshm6462]

HP to kW convertion as shown divided but i it is multification

[@rulmecacorporation4596]

Weight is measured in Newtons not kg. 1 N = 1 kg x 9.81 m/sec/sec

[@hr5094]

Yes weight is measured in Kg
means travelling/Linear speed and respective weight = Kg/sec

[@usmanahmad7922]

too loud background music

[@veereshs.konanakeri542]

I didn't understand that 7.9/0.7457= 5.9kw