A tricky Stanford Exam Question | Nice Algebra Math Simplification

[@RealQinnMalloryu4]

60/30=1 (x ➖ 1x+1).

[@veijolalli326]

(10^x+10^x+10^x)/(5^x+5^x+5^x)=100
3*10^x/3/5^x=100
10^x/5^x=100
(10/5)^x=100
2^x=100
ln(2^x)=ln(100)
x*ln(2)=ln(100)
x=ln(100)/ln(2)

[@serjonunes181]

(10^x + 10^x + 10^x)/(5^x + 5^x + 5^x) = 100
10^x/5^x=100
(10/5)^x=100
x log2 =2
x= 2/log2