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Great work ! Thanks so much !
x = 5 & - 1 are satisfying the identity.
Nice, you found six roots of the equation, which four is complex! ;)
Thank you this is very helpful!
x_j=2+3[cos(jπ/3)+i*sin(jπ/3)], j=0,1,...,.5
Х- 2=3 х=5, т.к 3 в 6 = 729
1.case. (x--2)^6= 3^6 =729. /6Г2.case( x--2)^6=(--3)^6=729. / 6Г1.case. x,--2 =3 ------->x,=52. case. x,,--2= --3------>x,,=--1🙋♂️
(X - 2)⁶ = 3⁶. ; X - 2 = 3X = 5
3^6=729, hence x-2=3, x=5. Or x-2=-3, x=-1. Other roots ... thats what the video is for.
x - 2 = ±3, x = 2 ± 3 = {-1, 5}.
Why isn't x=5? (5-2) to the sixth is 729, simples.Unless the answer you've come up with is another way of saying '5'.
5
X=5Ans
X=-1,5
Great work ! Thanks so much !
x = 5 & - 1 are satisfying the identity.
Nice, you found six roots of the equation, which four is complex! ;)
Thank you this is very helpful!
x_j=2+3[cos(jπ/3)+i*sin(jπ/3)], j=0,1,...,.5
Х- 2=3 х=5, т.к 3 в 6 = 729
1.case. (x--2)^6= 3^6 =729. /6Г
2.case( x--2)^6=(--3)^6=729. / 6Г
1.case. x,--2 =3 ------->x,=5
2. case. x,,--2= --3------>x,,=--1🙋♂️
(X - 2)⁶ = 3⁶. ;
X - 2 = 3
X = 5
3^6=729, hence x-2=3, x=5. Or x-2=-3, x=-1. Other roots ... thats what the video is for.
x - 2 = ±3, x = 2 ± 3 = {-1, 5}.
Why isn't x=5? (5-2) to the sixth is 729, simples.
Unless the answer you've come up with is another way of saying '5'.
5
X=5Ans
X=-1,5