Can you prove it? The Intermediate Value Theorem

แชร์
ฝัง
  • เผยแพร่เมื่อ 31 ม.ค. 2025

ความคิดเห็น • 56

  • @MrAllenmath
    @MrAllenmath 3 ปีที่แล้ว +6

    I've been wanting a solid proof of IVT and here it is. Thank you!

  • @omjoglekar3677
    @omjoglekar3677 3 ปีที่แล้ว +19

    Wait . . .till now I thought that the IVT was intuitive. I mean it is. But there exists a proof ? And that too formal ? Whoa ! COOL !

    • @damyankorena
      @damyankorena ปีที่แล้ว +2

      oh my god we have the same profile picture

    • @omjoglekar3677
      @omjoglekar3677 ปีที่แล้ว

      yay !@@damyankorena

  • @dylank6191
    @dylank6191 3 ปีที่แล้ว +11

    Exactly the way I proved it as well. I just said that, without loss of generality, we can assume c = 0 (we can consider g(z) := f(z) - c which is continuous, so if we show that g(z) = 0 for a z in (a,b), we know that f(z) = c for this exact z) which makes everything a bit easier to write down and visualize.

  • @ninafiliakelly3086
    @ninafiliakelly3086 3 ปีที่แล้ว

    Thank you so much for making these videos. They have really helped my university maths as everything you explain makes so much sense!

  • @alieser7770
    @alieser7770 3 ปีที่แล้ว +1

    sir i love you so much, you're one of the few TH-camrs that I think are wonderful people in real life too

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว

      Thank you!!

    • @Khadim-hk4gr
      @Khadim-hk4gr 7 หลายเดือนก่อน

      Sir, very informative

  • @raminrasouli191
    @raminrasouli191 3 ปีที่แล้ว +1

    I haven't seen the proof in a long time. Thanks 🍉❤❤🌷

  • @ghstmn7320
    @ghstmn7320 10 หลายเดือนก่อน +2

    Hello there! My school textbook has a proof of IVT by using Bolzano Theorem which states if a function is continuous at [a, b] and f(a)*f(b)

    • @drpeyam
      @drpeyam  10 หลายเดือนก่อน +1

      Same thing!

  • @luisrosano3510
    @luisrosano3510 3 ปีที่แล้ว

    Thank you Dr Peyam. Always is a pleasure watch you channel.

  • @broccoloodle
    @broccoloodle 3 ปีที่แล้ว

    Your analysis proofs are always beautiful

  • @justincallan2549
    @justincallan2549 4 ปีที่แล้ว

    How come at 10:20 the limit is

    • @justincallan2549
      @justincallan2549 4 ปีที่แล้ว +1

      Wait no never mind, disregard that ^^ i convinced myself haha say: (-1/n) < 0 but lim (-1/n) = 0

    • @drpeyam
      @drpeyam  4 ปีที่แล้ว +1

      Yep :)

    • @irinaignatova1799
      @irinaignatova1799 3 ปีที่แล้ว

      The set I= ]-inf;a[ is not closed in R, which means, there exist sequence of element of I, which converges, but the limit is no longer in I
      The sequence s_n is exactly this kind of sequence
      The same goes for your (1/n) sequence
      Each element of your sequence is inside ]0;+inf[ but your limit is not in ]0;+inf[

  • @rodrigocalixto470
    @rodrigocalixto470 ปีที่แล้ว +4

    12:15 Did you mean for N "very big" instead of "very small"?

  • @jimmykitty
    @jimmykitty 3 ปีที่แล้ว

    Wow!! Elegantly explained Boss 🤩
    Thanks for posting the video ❤🌿

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว +1

      You’re welcome!!!

    • @jimmykitty
      @jimmykitty 3 ปีที่แล้ว

      @@drpeyam ❤❤🌿🌿

  • @rahulseetharaman261
    @rahulseetharaman261 2 ปีที่แล้ว

    Hello Sir, could you please elaborate a bit more on how you used

    • @drpeyam
      @drpeyam  2 ปีที่แล้ว +1

      1-1/n < 1 for all n but the limit is 1

    • @rahulseetharaman261
      @rahulseetharaman261 2 ปีที่แล้ว

      @@drpeyam Thank you Sir.

  • @noahtaul
    @noahtaul 3 ปีที่แล้ว +1

    Did you ever give a topological version of this proof, not using metric spaces but proving that continuous image of connected is connected? There's all these topological properties that continuous functions preserve, and you have to remember whether it's f or f^-1, like open, closed, compact, connected, etc. And each of them is a new theorem/definition when interpreted in the metric space context.

  • @mrdavetrouble
    @mrdavetrouble 2 ปีที่แล้ว

    yes, this proof is beautiful. But would you agree "beauty is in the eye of the beholder" so we can not all be viewed beautiful even though we are. How do you feel about route to the summit using the nested interval theorem.

  • @anshumanagrawal346
    @anshumanagrawal346 3 ปีที่แล้ว +1

    The proof is absolutely 😘 indeed

  • @guill3978
    @guill3978 3 ปีที่แล้ว +1

    Can you prove in a video that the area of an squircle x^n+y^n=1 es equal to 4*(gamma(1+1/n))^2/gamma(1+2/n)?

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว

      That’s a nice idea

  • @mattetor6726
    @mattetor6726 ปีที่แล้ว

    Thank you! I c what you did there!

  • @szewing9038
    @szewing9038 4 ปีที่แล้ว

    Hi Dr Peyam at 14:18 why f of TN is greater than or equal c ?I think it's just greater than c only no equal sign.
    Thanks.

    • @drpeyam
      @drpeyam  4 ปีที่แล้ว +2

      Yes but if it’s > c then it’s >= c

  • @dgrandlapinblanc
    @dgrandlapinblanc 2 ปีที่แล้ว

    Thank you very much.

  • @mrdavetrouble
    @mrdavetrouble 2 ปีที่แล้ว

    well done my friend

  • @martinepstein9826
    @martinepstein9826 3 ปีที่แล้ว +1

    Great vid. We can also use open balls instead of sequences. Suppose f(x0) < c. Then by continuity of f there is an open ball about x0 whose image is < c. This ball contains points in S greater than x0 which contradicts the fact that x0 is an upper bound of S. On the other hand, suppose f(x0) > c. Then by continuity of f there is an open ball about x0 whose image is > c. This ball contains upper bounds of S less than x0 which contradicts the fact the x0 is the _least_ upper bound of S. Hence f(x0) = c.

    • @martinepstein9826
      @martinepstein9826 3 ปีที่แล้ว

      Speaking of real analysis, I looked at Folland's 'Real Analysis' the other day. I found two of his definitions extremely interesting: the limit supremum and limit infimum of a sequence of _sets_ E1, E2, E3, ...
      One is defined as the intersection from k=1 to oo of the union from i=k to oo of Ei. The other is the same but with "union" and "intersection" swapped. To make sure I understood, I intentionally forgot which was which and tasked myself with figuring it out based on what makes conceptual sense. These definitions suggest that an arbitrary sequence of sets "converges" if its limit supremum equals its limit infimum. I wonder how this relates to traditional limits in calculus and topology.

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว +1

      There are videos precisely on that, check out my sequences playlist

    • @martinepstein9826
      @martinepstein9826 3 ปีที่แล้ว

      @@drpeyam Hi Dr. Peyam, I checked out the playlist but I only found content for sequences of real numbers, not sequences of arbitrary sets. Maybe I just missed it. I can see if you take real numbers to be Dedekind cuts then the notions are actually equivalent.

  • @nicholascousar4306
    @nicholascousar4306 11 หลายเดือนก่อน

    Can the IVT be restated as the following? If f is continuous on the interval [a,b], then for every c between f(a) and f(b), c belongs to the image set of f([a,b]).

    • @drpeyam
      @drpeyam  11 หลายเดือนก่อน +1

      Yes, by definition of image set

  • @yoav613
    @yoav613 3 ปีที่แล้ว

    Nice prrof. What about cool integral are you planning one?

  • @adityaekbote8498
    @adityaekbote8498 3 ปีที่แล้ว

    Can you do a video on line integrals which are very generalized I get it for like R¹ or R² but it's hard to visualize for R^n/ n-integrals like there are double and triple integrals I want to know (and think something interesting will happen in the infinite case but I maybe wrong)

  • @isaacstamper7798
    @isaacstamper7798 4 ปีที่แล้ว +2

    Are you using Pugh's Real Mathematical Analysis book for this course? I'm using it for a course right now and a lot of the examples you give are the same.

    • @drpeyam
      @drpeyam  4 ปีที่แล้ว

      I love that book!!! Lucky you, it was the same I used when I took analysis. But no, the videos are based on the book by Ross

  • @whatitmeans
    @whatitmeans 3 ปีที่แล้ว

    Here is a somehow related questions, about upper bounds for maximum slew rate of functions.. I hope you could talk about it on your videos: on math stack exchange, question 4269062

  • @SimsHacks
    @SimsHacks ปีที่แล้ว

    Baby analysis : Proof of IVT
    Adult analysis: Proof of IFT 😂

  • @nnnn0596
    @nnnn0596 3 ปีที่แล้ว

    Always radioactive💫🤍

  • @117hippo3
    @117hippo3 3 ปีที่แล้ว

    중간값의 정리인가요?

    • @reeeeeplease1178
      @reeeeeplease1178 3 ปีที่แล้ว

      In english it's called
      Intermediate Value Theorem
      Hope this helps :D

  • @lancege8596
    @lancege8596 3 ปีที่แล้ว

    中值定理

  • @chessematics
    @chessematics 3 ปีที่แล้ว

    Back to classroom????

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว

      No that video was from May 2020

    • @chessematics
      @chessematics 3 ปีที่แล้ว

      @@drpeyam oh

    • @reeeeeplease1178
      @reeeeeplease1178 3 ปีที่แล้ว

      @@chessematics xD