Because we are looking for when sin (2 theta - 1.107) is equal to zero. For the 7/2 pi that you’re suggesting, this would make it equal to -1. I explain it in that section in the video. In order to make N(theta) as big as possible, we need to make the denominator as small as possible. If we use 7/2 pi to make the sin (2 theta - 1.107) equal to -1, we then square the trig value so it will become +1. Therefore, we want to make the sin (2 theta - 1.107) equal to zero, to make the denominator as small as possible. Sorry for taking a couple days to respond! The notification for your comment didn’t come up on my phone!
this was very helpful, thanks!
Good to hear, thanks so much for watching!
on exam questionn 2, why is 7/2pi not used as that is less than 11.459 and it would give the largest value? please respond
Because we are looking for when sin (2 theta - 1.107) is equal to zero. For the 7/2 pi that you’re suggesting, this would make it equal to -1.
I explain it in that section in the video. In order to make N(theta) as big as possible, we need to make the denominator as small as possible. If we use 7/2 pi to make the sin (2 theta - 1.107) equal to -1, we then square the trig value so it will become +1. Therefore, we want to make the sin (2 theta - 1.107) equal to zero, to make the denominator as small as possible.
Sorry for taking a couple days to respond! The notification for your comment didn’t come up on my phone!