lets say the angle (b+2,a) made with x-axis is theta . so Tan(theta)=a/(b+2) now , adding pi/4 in theta as rotation in anticlokwise will increase the angle with x-axis by pi/4. we know the new coordinates are (-1/√2 , 7/√2) . Tan(theta+pi/4)=(7/√2)/(-1/√2)=-7 => Tan(theta) + 1/1-Tan(theta)= -7 by solving we get ,Tan(theta)=4/3 a=4 , b=1. so 2a-b=7
We can assume x= rcos theta and y=r sin theta Then tan theta= y/x Again tan (π/4+ theta) can be found And distances can be compared It shud be (a+b+2)/√2, (a-b-2)/√2
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I think this ques is present in cengage coordinate geometry
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But if you remember that rotation matrix this becomes more easy nd fast!!
lets say the angle (b+2,a) made with x-axis is theta . so Tan(theta)=a/(b+2)
now , adding pi/4 in theta as rotation in anticlokwise will increase the angle with x-axis by pi/4.
we know the new coordinates are (-1/√2 , 7/√2) .
Tan(theta+pi/4)=(7/√2)/(-1/√2)=-7
=> Tan(theta) + 1/1-Tan(theta)= -7
by solving we get ,Tan(theta)=4/3
a=4 , b=1. so 2a-b=7
Rotation sunte hi physics walo ko rolling without slipping dimag mein aata hai, hamein complex numbers :)
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We can assume x= rcos theta and y=r sin theta
Then tan theta= y/x
Again tan (π/4+ theta) can be found
And distances can be compared
It shud be (a+b+2)/√2, (a-b-2)/√2
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Rotn matrix watching from hell🤔....
Solution?
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Same approach is used in vector too
my head rotated 360 when i heard your voice only on the left side of my ear in headphones
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Yes lmao very easy i dont think anybody does the whole long method
i did in same way
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me who did it in less than 10 secs
Are Einstein baba ap?😮
@@TobiZet_9 bhai idk why but when i saw the question the first thing that came in my mind is parametric forms of transformed points 🤣🤣🤣
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