You could have done it very simply. For Logarithms, you can raise the base of any logarithm to any power you like, as long as you raise its argument to the same power as well. So, you could have squared log2^x, to get log4^x^2, then you combine the logs to get log4^x^3, then put it in exponential form, so you have 4^6 = x^3, then of course take the cubic root, so 4096 cube rooted, to find that x = 16.
If you simplify the power of 2,the answer is 4. log base 2 of 4 is 2 then 2x6=12 divided by 1+ log base 2 of 4=1+2=3. Making the power equal to 12÷3=4!
Yeah, I agree with most if the comments. Could have simplified the logs earlier to make the equation easier to work with. But well done. I won't fight your approach since you maintained the accuracy of your soln
Very impressive but log x base 4=½log x base 2 Log x ¹`². x base 2=6 By exponentiating we have x³'²=2^6 By inverting the exponent 3/2 and multiply both exponents by 2/3,we have X=2⁴=16
I'm new to logs and I've solved this equation 3 different ways that were much simpler and easier. You might want to simplify your methods for your students as to not over complicate their lives unnecessarily
Thank you for good work, but the final stage to the answer is easy to simplify and get the answer, so I advise not to use a calculator for solving without using the calculator is most preferable.
You made the problem too messy to do because you failed to realize that log2(4) = log2(2²) = 2 . This means at 02:45, you could write: log2(x)/2 + log2(x) = 6 log2(x)*(1/2 + 1) = 6 log2(x)*3/2 = 6 log2(x) = 4 x = 2⁴ = 16 Why use a calculator?
Yes, but that's just another method...nothing messy about it. Maths is a mental subject that trains the mind to solve problems and believe you me, a single problem can be solved using several different methods!
The base of the first term is 4 which is 2^2. Just bring this exponent 2 as 1/2 infront of the first term and then the base is the same of both the term. Then the solution is readily there which is 16.
Much appreciated sir surely goodness and mercy shall follow you all the days of your life
Your channel is really helpful , keep up the good work, Mr sichamba
Wonderful teacher let's get this man to 2.2m subscribers, all the best sir.
You're good teacher
Keep going Jacob
Big up sir Jacob you have it in you I wish you all the best the world needs your light ❤
It is really helpful sir.
Thanks sir for your help , I appreciate the Lord for your knowledge you're sharing with us 🎉
Thank you sir for the lessons they really help ❤❤
Very helpful Mr Sichamba J❤
excellent work sir
It's very awesome
This vedio is really helpful thanks
You could have done it very simply. For Logarithms, you can raise the base of any logarithm to any power you like, as long as you raise its argument to the same power as well. So, you could have squared log2^x, to get log4^x^2, then you combine the logs to get log4^x^3, then put it in exponential form, so you have 4^6 = x^3, then of course take the cubic root, so 4096 cube rooted, to find that x = 16.
You're right boss
From 6:15 onwards, he changed from logarithmic form to index form.
Log2^x=b(logarithmic form) == x=2^b(index from)
Thanks you sir I hav (learned) a lot from your lesson
Perfect, way to go. Thanks Mr. Jacob.
,thank you very much ,continue helping us
If you simplify the power of 2,the answer is 4.
log base 2 of 4 is 2 then 2x6=12 divided by 1+ log base 2 of 4=1+2=3.
Making the power equal to 12÷3=4!
Yeah, I agree with most if the comments. Could have simplified the logs earlier to make the equation easier to work with.
But well done.
I won't fight your approach since you maintained the accuracy of your soln
Thank you so much, Teacher ❤😊
Fantastic
Good job thanks
Good stuff
Good teacher
Very impressive but log x base 4=½log x base 2
Log x ¹`². x base 2=6
By exponentiating we have x³'²=2^6
By inverting the exponent 3/2 and multiply both exponents by 2/3,we have
X=2⁴=16
At the last step it can be solved without even the calculator, Mr tutor
I really do understand much appreciated
Thank you sir
Thanks sir its best
You don't have to punch a calculator to determine the final value of "x". It can still be simplified further to give same answer. Thanks
Evaluate this for me please l log x + log x cubed minus log x squared is equals to log 100
Bros been waiiugtin@@damarismutiso-dx2xo
I'm new to logs and I've solved this equation 3 different ways that were much simpler and easier. You might want to simplify your methods for your students as to not over complicate their lives unnecessarily
Thank for the help Sir
this was so helpful to me
I'm really getting the knowledge
It's woow
More sir❤
More sir
Thank you
Thanks sir
Thanks Sir
Answer as x-16 can be brought out. Answer is correct.
This video is really helpful God bless you sir
Thank you for good work, but the final stage to the answer is easy to simplify and get the answer, so I advise not to use a calculator for solving without using the calculator is most preferable.
I'm still confused about the factorization part 🤔
❤❤❤
DAYUMN DIS IS G LIKE TEACH
This method is not meant for beginners. There so many ways of solving in little steps.
Thank you very many sir
Thank u sir 🎉
You are doing well but you go fast
How do we press on calculator
Is the factorization correct??
I didn't get how u multiplied to remove the denominator
Mr next week we r doing final exams buh man am scared
Are you sure the factorization is correctly applied there
Very correctly applied Sir/madam whatever the case may be.
You made the problem too messy to do because you failed to realize that log2(4) = log2(2²) = 2 .
This means at 02:45, you could write:
log2(x)/2 + log2(x) = 6
log2(x)*(1/2 + 1) = 6
log2(x)*3/2 = 6
log2(x) = 4
x = 2⁴ = 16
Why use a calculator?
Yes, but that's just another method...nothing messy about it.
Maths is a mental subject that trains the mind to solve problems and believe you me, a single problem can be solved using several different methods!
Pls sir solve loga 27+ logb 4 = 5
Hello. ..a little bit confused... because of two unknowns
Sir please the solution is not clear
How is paper two am really scared
The base of the first term is 4 which is 2^2. Just bring this exponent 2 as 1/2 infront of the first term and then the base is the same of both the term. Then the solution is readily there which is 16.
Correct. Short and precise. Following from Nairobi.
do you teach science?
This is long method for students understanding , so you have to solve it shortest way , my answer also 16 but 3 line solving tricks
Kindly share pls
Thanks
How?
Duh thanks so much Mr
We are just fellow your platform , therefore we short format otherwise am lose
Sir so sorry to say but i thank you feel like writing , there is too much of mess sir pleas kindly review your work
❤
You don't have to use a calculator here sir.
WAS NICE FIRST BUT THEN U SHOULD FINISH IT USING
PROPERTIES AND LAWS NOT CALCULATOR
log x base2=6×2/3=4=>x=2^4=16 ans
Can't we solve it without saying that x=2^others
=>1/2log 2 basex +logxbase2=6=>3/2(logx base2)=6=>logxbase2=4=>x=16 ans
Wow
....😵💫😵💫🤯
Am not understanding on changing the Base
Log x base 4=(log x)/(log 4. Log 4=log 2^2=2log 2
(Log x)/(2log 2) +(Log x)/(Log 2) = 6
Multiply by 2log 2
Log x + 2log x =6 ×2log 2
÷2
Log x + log x = 6 log 2
2log x = 6 log 2
÷2
Log x = 3log 2 =log 8
x = 8
@harrymatabal8448: line 2 is correct, but line 3 is wrong. Fix it with:
log2(x) + 2*log2(x) =6*2*log2(2)
3*log2(x) = 12*1
log2(x) = 4
x = 2⁴ = 16
Just explain how you got 16 with better clarity
I have apricoated
Thank u so much 🙏🙏🙏🥹
3/2 log xbase2=6=>logxbase2=4=>x=16ans
You have made a mistake on the second step
What is the mistake he made
Please Mr.explain in short form
This method is unnecessarily too long. You can solve this problem in an easier and shorter way
logxbase2=6×2/3=4=>x=2^4=16ans
Somehow confusing Sir.
U shud b able to simplify further to get 16 without using calculator
I'm getting 12 as the answer
uh oh
x=e^(6*ln4*ln2/(ln4+ln2)) , x=16 , test , log₄16=2 , log₂16=4 , 2+4=6 , OK ,
Please I don't understand
No need to remind us about the rules. We are not stupid.
Why are you so rude bathwetu 😢??
thank you so much sir
DO NOT MAKE A COMPLEX EXPLANATION
Which grade is this topic coming from sir
It's general
Okay
In additional mathematics grade 12
In additional mathematics grade 12
Long
th-cam.com/video/Y1X21qtC19w/w-d-xo.htmlsi=yY5OekcndgcPIQxh
I don't understand
right ,but bad solution
log4(x) + log2(x) = 6
log(x)/log(4) + log(x)/log(2) = 6
log(x)/(2*log(2)) + log(x)/log(2) = 6
log(x) + 2*log(x) = 12*log(2)
log(x) = log(16)
x = 16
So long
Not clear