I want to use this opportunity and thank the management of Manocha Academy because of them I did exceptional 🎉in my physics WASCCE paper words can’t explain how grateful I am ❤️🙏🏾 once again mammoth thanks to you Sir 🙏🏾
Let's dive deeper into the concept of "systems" and their role in the context of de Broglie wavelengths and quantum mechanics. What is a system in physics? In physics, a system is simply a collection of objects or entities that we choose to focus our attention on. It's a way of mentally separating a part of the universe from the rest, so we can analyze its behavior and interactions more easily. Types of Systems * Isolated System: No exchange of matter or energy with its surroundings. A perfectly isolated system is an idealization, but some systems come close (e.g., a well-insulated thermos). * Closed System: Can exchange energy but not matter with its surroundings (e.g., a sealed container with a hot liquid). * Open System: Can exchange both matter and energy with its surroundings (e.g., a living organism). Why Systems Matter in Quantum Mechanics When we talk about a particle's de Broglie wavelength interacting with a system, we're essentially talking about how the particle's wave function interacts with the potential energy landscape or boundaries defined by that system. * Confinement: Systems can confine particles to specific regions of space, altering their wave functions and energy levels. This leads to phenomena like quantum confinement in nanostructures, where the particle's behavior is strongly influenced by the system's boundaries. * Scattering and Diffraction: When a particle interacts with a system, its wave function can be scattered or diffracted, revealing information about the system's structure. This is the basis for techniques like electron microscopy and neutron scattering. * Tunneling: In quantum mechanics, particles can "tunnel" through potential energy barriers, even if they don't have enough classical energy to do so. The probability of tunneling depends on the particle's de Broglie wavelength and the shape of the barrier, which is often determined by the system's properties. Choosing the Right System The choice of system depends on the specific problem or phenomenon we're interested in. * Single Particle in a Potential: We might consider a single particle (e.g., an electron) interacting with a potential well or barrier created by some external field or structure. This allows us to focus on the particle's wave function and energy levels within that specific environment. * Many-Particle Systems: In more complex systems, we need to consider the interactions between multiple particles, which can lead to collective phenomena like Bose-Einstein condensation or superconductivity. * Open Systems: In some cases, we need to account for the exchange of matter and energy with the surroundings, which can lead to decoherence and other effects that influence the quantum behavior of the system. Key Takeaway The concept of a "system" provides a framework for analyzing the behavior of particles in quantum mechanics. By defining the system and its boundaries, we can understand how a particle's de Broglie wavelength interacts with its environment, leading to a wide range of quantum phenomena. Let me know if you'd like to explore any specific examples or aspects of systems in more detail. I'm here to help!
Sir ....i watched your video when I was in 9th standard That was so clear After 5 years.... I got your video from suggestions ❤ So I'm an old student of your TH-cam class😂❤
Change in wavelength is (9x10-¹¹) that's exactly 27.3% decrease. This when you truncate the numbers while solving. But, when you decide not to truncate, estimate or approximate. The percentage change is 28.57142857143% exactly.
The wavelength originally is 3.3×10-¹⁰m but as K.E(2.202x10-¹⁸) increased by 96% it changed the wavelength down to 2.4×10-¹⁰m that's a difference of 0.9×10-¹⁰ in correct standard form 9.0x10-¹¹. 23.7%. K.E is 1/2mv² where m(mass) is 9.1x10-³¹kg and v(velocity)=2.2x10⁶m/s.
Good 👍 Next video on What is matter What is Physics definition area dimensions scope philosophy Physical world and it's measurements Physics day Physics history Physics Father
λ = h / p where h is Planck's constant. Since kinetic energy (KE) is related to momentum by: KE = p^2 / (2m) where m is the mass of the electron, we can express the change in kinetic energy as: ΔKE = (p2^2 - p1^2) / (2m) Given that the kinetic energy increases by 96%, we can write: ΔKE = 0.96KE1 where KE1 is the initial kinetic energy. Substituting the expression for KE in terms of momentum, we get: (p2^2 - p1^2) / (2m) = 0.96(p1^2 / (2m)) Simplifying, we get: p2^2 = 1.96p1^2 Taking the square root of both sides: p2 = √1.96p1 ≈ 1.4p1 Now, using the de Broglie equation, we can find the change in wavelength: λ2 = h / p2 = h / (1.4p1) ≈ 0.71λ1 So, the wavelength decreases by about 29% (1 - 0.71 ≈ 0.29).
If we let the first kenetic energy is KE1 and The second kenetic energy is KE2 then the answer will be -0.2hKE1m h =Planck's constant m=the mass of an electron KE1=the first kenetic energy I hope you will give me a correction if I'm wrong 🙏 Thanks for the video I swear this video is so amazing
The fact that the energy levels are quantized doesn’t mean that there are particles. Rather, it is all waves but “quantized waves” as I call them. They give the false impression of particles but do account for the so called “dual nature of particles”.
I want to use this opportunity and thank the management of Manocha Academy because of them I did exceptional 🎉in my physics WASCCE paper words can’t explain how grateful I am ❤️🙏🏾 once again mammoth thanks to you Sir 🙏🏾
Congratulations!! Great to hear that you did in your Physics paper! Do share our channel with your friends!
@@ManochaAcademy Yes Sir and they also did well
Woooow
For LIVE Classes, Concept Videos, Quizzes, Mock Tests & Revision Notes please see our Website/App
👉Our Website: bit.ly/2KBC0l1
👉Android App: bit.ly/3k48zdK
Pls add more videos in math..it is very helpful to my son..you have taught in depth which the school fails to
I admire the way you are teaching
OMG guys my 10 years in STEM in one video omg this person deserves so much more recognition!!! lots of love and gratefulness
God will continue to bless you as long as you exist both you and your family and generations.
The answer for change in wave length is 40%
Wavelength=h/(2mKE)1~²
By using this we can calculate
How bro
Brilliant lecture I will understand 😅
Thanks so much now I can go on and do my assignment.
I wanna become quantum scientist thanks sir for this video
Awesome to hear that ☺️
Can u tell me the roadmap to become along with marine biologist?
Niga it ain't that much easy as said
I guess you don't know the dot of quantum. Sir ki video toh khud sur confuse lag raha hae. Theory is not physics it's understanding.
😂@@amreedit
It's energy that was thought to be continuous, not matter.
The quality of these videos! My god! Fantastic! 11th videos are very intresting even to the 10th graders!
Sir, you have helped me so much through all you videos. Thank you so much!🎉🎉
Sir from 11 lakh to 12 lakh congratulations
Let's dive deeper into the concept of "systems" and their role in the context of de Broglie wavelengths and quantum mechanics.
What is a system in physics?
In physics, a system is simply a collection of objects or entities that we choose to focus our attention on. It's a way of mentally separating a part of the universe from the rest, so we can analyze its behavior and interactions more easily.
Types of Systems
* Isolated System: No exchange of matter or energy with its surroundings. A perfectly isolated system is an idealization, but some systems come close (e.g., a well-insulated thermos).
* Closed System: Can exchange energy but not matter with its surroundings (e.g., a sealed container with a hot liquid).
* Open System: Can exchange both matter and energy with its surroundings (e.g., a living organism).
Why Systems Matter in Quantum Mechanics
When we talk about a particle's de Broglie wavelength interacting with a system, we're essentially talking about how the particle's wave function interacts with the potential energy landscape or boundaries defined by that system.
* Confinement: Systems can confine particles to specific regions of space, altering their wave functions and energy levels. This leads to phenomena like quantum confinement in nanostructures, where the particle's behavior is strongly influenced by the system's boundaries.
* Scattering and Diffraction: When a particle interacts with a system, its wave function can be scattered or diffracted, revealing information about the system's structure. This is the basis for techniques like electron microscopy and neutron scattering.
* Tunneling: In quantum mechanics, particles can "tunnel" through potential energy barriers, even if they don't have enough classical energy to do so. The probability of tunneling depends on the particle's de Broglie wavelength and the shape of the barrier, which is often determined by the system's properties.
Choosing the Right System
The choice of system depends on the specific problem or phenomenon we're interested in.
* Single Particle in a Potential: We might consider a single particle (e.g., an electron) interacting with a potential well or barrier created by some external field or structure. This allows us to focus on the particle's wave function and energy levels within that specific environment.
* Many-Particle Systems: In more complex systems, we need to consider the interactions between multiple particles, which can lead to collective phenomena like Bose-Einstein condensation or superconductivity.
* Open Systems: In some cases, we need to account for the exchange of matter and energy with the surroundings, which can lead to decoherence and other effects that influence the quantum behavior of the system.
Key Takeaway
The concept of a "system" provides a framework for analyzing the behavior of particles in quantum mechanics. By defining the system and its boundaries, we can understand how a particle's de Broglie wavelength interacts with its environment, leading to a wide range of quantum phenomena.
Let me know if you'd like to explore any specific examples or aspects of systems in more detail. I'm here to help!
@anthonymckinnev8173 Amazing comment, I really appreciate it! This sheds light on a very important and usually overlooked concept.
Thanks you sir for your kindly information to students ❤❤❤🎉🎉🎉😅😅😊😊😊
Thanks 🙏 from Bangladesh 🇧🇩. Does that means that all object r high Frequency least wavelength? 2. All objects r frozen light?
the lecture i wanted thank you
Glad to hear that
It was a very helpful video. Love from Bangladesh. ❤
God bless you sir ❤
Great class about quantum mechanics ❤
Sir ....i watched your video when I was in 9th standard
That was so clear
After 5 years....
I got your video from suggestions ❤
So I'm an old student of your TH-cam class😂❤
Great explanation❤ liked this video
Change in wavelength is (9x10-¹¹) that's exactly 27.3% decrease. This when you truncate the numbers while solving.
But, when you decide not to truncate, estimate or approximate. The percentage change is 28.57142857143% exactly.
The wavelength originally is 3.3×10-¹⁰m but as K.E(2.202x10-¹⁸) increased by 96% it changed the wavelength down to 2.4×10-¹⁰m that's a difference of 0.9×10-¹⁰ in correct standard form 9.0x10-¹¹. 23.7%. K.E is 1/2mv² where m(mass) is 9.1x10-³¹kg and v(velocity)=2.2x10⁶m/s.
Good 👍
Next video on
What is matter
What is Physics definition area dimensions scope philosophy Physical world and it's measurements Physics day Physics history
Physics Father
You are a star sir
Sir one video on weightless
Will try to make that one soon!
5.0127×10^-19
Thank you very much sir
λ = h / p
where h is Planck's constant.
Since kinetic energy (KE) is related to momentum by:
KE = p^2 / (2m)
where m is the mass of the electron, we can express the change in kinetic energy as:
ΔKE = (p2^2 - p1^2) / (2m)
Given that the kinetic energy increases by 96%, we can write:
ΔKE = 0.96KE1
where KE1 is the initial kinetic energy.
Substituting the expression for KE in terms of momentum, we get:
(p2^2 - p1^2) / (2m) = 0.96(p1^2 / (2m))
Simplifying, we get:
p2^2 = 1.96p1^2
Taking the square root of both sides:
p2 = √1.96p1 ≈ 1.4p1
Now, using the de Broglie equation, we can find the change in wavelength:
λ2 = h / p2
= h / (1.4p1)
≈ 0.71λ1
So, the wavelength decreases by about 29% (1 - 0.71 ≈ 0.29).
If we let the first kenetic energy is KE1 and The second kenetic energy is KE2 then the answer will be -0.2hKE1m
h =Planck's constant
m=the mass of an electron
KE1=the first kenetic energy
I hope you will give me a correction if I'm wrong 🙏
Thanks for the video I swear this video is so amazing
bro answer is -.03 aa raha h mera to
kya tum bataoge kaise kiya tumne
What is Quantum sir ?
Is it something like quantified or will it can be other way said as made into mathematically expressible once Sir ?
Sir Please do a video on electromagnetic induction
the wavelength decreases by about 29% (1 - 0.71 ≈ 0.29).
Nice one!
Can you do relationship between schrodinger wave equation and de broglie equation?
Sir the answer would be 5.01×10^-19 .
Amazing🎉
Are number of electrons reduced when metal was exposed to light ?
Sir I want you to teach the topic "state of matter". Thank you.
Sir from which website you use simulations like you use photoelectric effect in this video ??
Please can help me on how to identify colour in chemistry 9:55
Thank you sir
Sir question ki answer kuda cheppandi
Wavelength will decrease by 28.5 %
Sir please pin if ans is correct ❤
what is the answer for the question? please help ?
7/5
1.58×10^-15
Clear explanation sir :) Sir can i please know the answer for the homework question? Thanks in advance sir.
the percentage change in wavelength is 2.14%.
Sir very nice video..heart please ❤
Most welcome!
Change in wavelength=2/5 and %change in wavelength= 40%
The fact that the energy levels are quantized doesn’t mean that there are particles. Rather, it is all waves but “quantized waves” as I call them. They give the false impression of particles but do account for the so called “dual nature of particles”.
Thank you.... your explanation is crystal clear
❤❤❤❤❤
Thank you!
we want the bloopers 😛
Please i can't get it explain for me
0.13383×10-34
Could you explain structure of atom lesson sir😅😅😅
Exams aa gaye h aur tujhe Lecture chahiye 🤣🤣🤣🤣😂😑
Sir is the change in wavelength 92.8%
27%
Sir please Give tha answer of last Question
Is this KEf=kei+96%(ke) i
kral bir türk olarak alt yazıya cevirip kesintisiz izledim :)
0.287 decrease
I got 51%....i.e the wavelength decreases by 51%
Whose student present in watching this lecture 2025😅
-28.6%
98% decrease
The answer is:
1.4 times the initial wavelength.
i.e.,
Final wavelength=1.4 initial wavelength
or,
λ'=1.4λ.
Hope it's true.
Please let me know.
28.57% dicreases
how to find
First
Thanks for watching so fast :)
This is awesome. How can I have to these topics in physics that difficult to explain theoretically
kk
There are so many students who are not able to understand english so please make your lectures in hindi❤❤❤❤❤
u are number one stupid
71.428% increase in wave length.
Aby jaldi bol kal subah palvey nikalna ha
কী গাবাই।
Decrease 28.571428571 %