Yeah I am wondering why does that happen myself. Your teacher with a PHD has been drilling some knowledge into you but you discover you are learning better from a youtuber.
Thanks for the detailed tutorial. For the people who find it hard to calculate break away point, just calculate characteristic equation 1+G(s)H(s) = 0, then find the equation in terms of s and with k on RHS. Now differentiate with respect to s or dK/dS and equate it to zero. From this you can find the solutions for s, which are break away and break in points.
@10:52 woah I'm mind blown by that equation for solving the break-in/break-away points. The method taught to us in class is differentiating the equation K = -1/GH and setting it to zero. It's naturally a bit tedious because the quotient rule for differentiation would have to be applied, but it yields the polynomial that's solvable through a hand calculator. I tried solving the equation here using shift-solve in the calculator and it's not able to get -3.0864. That being said, still a very helpful thing to know! I'm curious now how that is derived for solving the points :)
Your voice made me concentrate the whole 16 min video which my professor tried explaining throughout 3 sessions of 2 hour lectures each. Thank you so much!
Thank you so much ma'am You literally solved this problem and made it really easy to understand Other TH-camrs just wasted my time Thank you again ❤️❤️
Thanks for clearing that up, great video. Although I think at 0:48 is wrong to assume that the open loop T.F is done by only taking the top line, as this is only valid in unity feedback systems where H(s) = 1, when H(s) is not equal to 1, Open loop T.F is equal to G(s) * H(s)
about the angles its a stated thing - if Fp-Fz = 2 its gonna be 90, -90 if it's three then 60,-60, and 180 and if it's 4 then 45, -45 something I didn't remember the point is that - in RL you need an identical asymptote that will to in the other direction in the same angle from the same point on the Real axis (hope it helped) oh and thank you really helped me to understand how to draw the RL graph
oh and one more tip - instead of taking random K's you could just do the: (2*h+1)*180\Fp-Fz when h = Fp-Fw-1 the way you do it is you start from zero and work your way up to the value of -> Fp-Fw-1 ich time you put the results in the equation
Thanks for the video! But there is another easy way to find break away break in points, just take the derivative of G_open without K and equate it to zero.
What to do if i have imaginary poles and try to find the breakaway points? I mean, i will get double real parts. So, do i have to sum just once, or sum by each for the pole side?
Break away points only need to be calculated where the root locus is "joined" on the real axis. If you have imaginary poles then they won't be on the real axis (other than if they are at the origin - in which can you just apply the process shown the video).
I would have gotten an A in my ECE 460 class (Control Systems) if this lady was my professor. The one I had was a complete JOKE as are most university professors.
K (the gain) depends on where you select to put your closed loop poles. What you plot on the diagram is the potential locations. You typically have some sort of criteria that determines what your K should be. I recommend watching some of the other (later) videos in the control playlist that cover this part (look for ones about designing controllers).
16min video summed up what my professor was trying to explain in a 2hr lecture... Thank you so much
Literally the same man. I have a 72 page document on this from my prof and I understand in 16 minutes
love this
Yeah I am wondering why does that happen myself. Your teacher with a PHD has been drilling some knowledge into you but you discover you are learning better from a youtuber.
I thought it was a third world issue, but turns out it's global.
فضحتنا يا هشام
Why can't everybody on youtube make clear, concise, straight to the point videos like this one. 5 star rating, you are the bomb!!! lol
you are right!
i'm literally going to cry, this was so helpful. my professor's 70 slides cannot compare to this 15 min vid.
This is, by far, the best video I've seen on root locus. The explanation was short, concise, the formulas and steps easy to follow.
This is exactly what I expect from a teacher, being direct and unbelievably precise! Thank you very much, teacher!
Thanks for the detailed tutorial.
For the people who find it hard to calculate break away point, just calculate characteristic equation 1+G(s)H(s) = 0, then find the equation in terms of s and with k on RHS. Now differentiate with respect to s or dK/dS and equate it to zero. From this you can find the solutions for s, which are break away and break in points.
@10:52 woah I'm mind blown by that equation for solving the break-in/break-away points. The method taught to us in class is differentiating the equation K = -1/GH and setting it to zero. It's naturally a bit tedious because the quotient rule for differentiation would have to be applied, but it yields the polynomial that's solvable through a hand calculator. I tried solving the equation here using shift-solve in the calculator and it's not able to get -3.0864.
That being said, still a very helpful thing to know! I'm curious now how that is derived for solving the points :)
Im no stranger to TH-cam math videos and this by far is one of the best I've seen. Thank you!
You saved my life! I've never watched a control systems lecture so objective, thank you!
Bless You
Thank you from Canada. Amazing work! Super clear, concise, and logical. You’re the best!
The best Root Locus video. The 2 hours as discussed with my professor was to difficult to understand while with this clip, it is clear and concise.
Absolutley amazing video! Can't get over how clear it is
Love your hand writing, looks really cool! xD
Your voice just literally made me understand this topic
I've nothing to say other than this is one of the most helpful videos I've ever come across
Thank you! Straight and direct to the point with a nice simple example to actually help understand what's happening👌😁
I can't believe my eyes. How come a human can make such a great video. I am literally shocked. Thanks a lot Mam.
You are simply amazing !
This was so clear and easy to understand!! Thank you so much!
Fantastic video, really clear and concise. Thank you so much!
Super helpful! Thanks, girl!
Too much helpful about understanding root locus , thanks a lot !!
first time a video deserves 0 dislike. great video thank you so much
Your voice made me concentrate the whole 16 min video which my professor tried explaining throughout 3 sessions of 2 hour lectures each. Thank you so much!
you're a life saver, thank you for explaining this >.
Woow.you made it too easy😊
thank you so much . this is quite simplified, keep up the good work
Thank you for sharing. Greetings from Panama 🇵🇦
you are the best teacher,you deserve a bell
Why didnt i found this video before my final exam. Thank you so much
Mine is next week. Glad I found it before 😇
@@Baraka_SYP good for you i still passed it but with a C.
Thanks a lot great sense of humor mam !!
Really too helpful for me
Really solved all my doubts I was having earlier
Thank you for making this video
you just 2 weeks into a nice 16 minute session. Thank you
Awesome tutorial, thanks!
These are great, thank you very much!
Thank you so much, you gave me confidence in solving these problems now :)
Nice video on root locus
Thank you so much..Amazing video, simple yet easy to understand and to the point.
i love your voice the way you speak is fabulous.And you are so intelligent lol
Thank you so much ma'am
You literally solved this problem and made it really easy to understand
Other TH-camrs just wasted my time
Thank you again ❤️❤️
Thanks for clearing that up, great video.
Although I think at 0:48 is wrong to assume that the open loop T.F is done by only taking the top line, as this is only valid in unity feedback systems where H(s) = 1, when H(s) is not equal to 1, Open loop T.F is equal to G(s) * H(s)
thinking the same thing
You are great 👍 thanks for this
Thank you very much. the Best video about the Root Locus. ❤🔥
Thank you so much :) Saved my life !!!
Thank you so much! This was very helpful as I prepare for my exam!
about the angles its a stated thing - if Fp-Fz = 2 its gonna be 90, -90 if it's three then 60,-60, and 180 and if it's 4 then 45, -45 something I didn't remember the point is that - in RL you need an identical asymptote that will to in the other direction in the same angle from the same point on the Real axis (hope it helped)
oh and thank you really helped me to understand how to draw the RL graph
oh and one more tip - instead of taking random K's you could just do the:
(2*h+1)*180\Fp-Fz when h = Fp-Fw-1 the way you do it is you start from zero and work your way up to the value of -> Fp-Fw-1 ich time you put the results in the equation
How do you do your video like that? Like what do you use to write on the background, and how do you record?
Thanks thanks a lot. This was amazing 👏
Great work, i was confused with asymptotes
Merci à toi ! très bonne explication
Super explanation
Excellent !
This is really good explanation.thank you very much
Thank you! Very Clear.
Thanku for very nice explain 👌
Thanks that was so easy
This is the best!!
omg she is adorable. thanks a lot
Great video.
thank you so much this video its perfect for me
Thanks so much.
Explanation was perfect
Thank you very much 💖, this video really helped.
Lovely
Thank u so much ma'am it helped me alot u have explained everything so crystal clearly thanks alot
this saved my damn life
good job ryder
Thank you so much. your worth much more then 1000 views.
Thanks for the video! But there is another easy way to find break away break in points, just take the derivative of G_open without K and equate it to zero.
This is the shit, you did a great job on this. Teachers cant teach nearly as well as you did
❤️❤️ Paoools
Hi I was wondering, when u found the asymptotes angles 90, 270 deg, can you instead can you write +_90 degrees? Cause the formula has +- Infront of it
Is there any video on Bode plot?
Hi! Nice video! are you a student? what's your major?
Actually my prof took a week , but I didn't understand what he wanted to teach..... Love you from BIHAR
What to do if i have imaginary poles and try to find the breakaway points? I mean, i will get double real parts. So, do i have to sum just once, or sum by each for the pole side?
Break away points only need to be calculated where the root locus is "joined" on the real axis. If you have imaginary poles then they won't be on the real axis (other than if they are at the origin - in which can you just apply the process shown the video).
you're the best
Tyvm,even I’m not an English native speaker,I still understand 90%what ur saying ,ty
I have a better understanding just after watching this video, please explain how the break away/break in is done in MATLAB .
Thank you prof !!!
thanks... From Iraq 🌹🌺
I would have gotten an A in my ECE 460 class (Control Systems) if this lady was my professor. The one I had was a complete JOKE as are most university professors.
ありがとうございます！！
the way you explain is good but, im always distacted by your sound lmao
One question: What if we had (s+6) / ((s+6)(s+1)(s+2)), then we have zero=-6 and pole=-6 ? What in that case?
noice
thank you!!!
thanks you perfect 10/10
5:38 niceeeee :)
Really helped a lot 🙏🙏... Thank you so much. My college teachers are so 💀💀☠️☠️
how do you know that the asymptote in your example is a straight line asymptote parallel to Im-Axis?
It's from theta_a calculated about 7.23 in the video
you the best
💓
Love
thanks mam love from INDIA
thank youuu
Thanks for your clear explanation. I just have a question please. How to find 'K' coefficient in this exercise ? thanks :)
K (the gain) depends on where you select to put your closed loop poles. What you plot on the diagram is the potential locations. You typically have some sort of criteria that determines what your K should be. I recommend watching some of the other (later) videos in the control playlist that cover this part (look for ones about designing controllers).
what if a pole repeats? do you add it twice?
Yes
Thank you from Thailand.
LOL i owe my degree to youtube ... finally something that helps !! i was about to go crazyyyy