Yeah I am wondering why does that happen myself. Your teacher with a PHD has been drilling some knowledge into you but you discover you are learning better from a youtuber.
Thanks for the detailed tutorial. For the people who find it hard to calculate break away point, just calculate characteristic equation 1+G(s)H(s) = 0, then find the equation in terms of s and with k on RHS. Now differentiate with respect to s or dK/dS and equate it to zero. From this you can find the solutions for s, which are break away and break in points.
@10:52 woah I'm mind blown by that equation for solving the break-in/break-away points. The method taught to us in class is differentiating the equation K = -1/GH and setting it to zero. It's naturally a bit tedious because the quotient rule for differentiation would have to be applied, but it yields the polynomial that's solvable through a hand calculator. I tried solving the equation here using shift-solve in the calculator and it's not able to get -3.0864. That being said, still a very helpful thing to know! I'm curious now how that is derived for solving the points :)
Your voice made me concentrate the whole 16 min video which my professor tried explaining throughout 3 sessions of 2 hour lectures each. Thank you so much!
about the angles its a stated thing - if Fp-Fz = 2 its gonna be 90, -90 if it's three then 60,-60, and 180 and if it's 4 then 45, -45 something I didn't remember the point is that - in RL you need an identical asymptote that will to in the other direction in the same angle from the same point on the Real axis (hope it helped) oh and thank you really helped me to understand how to draw the RL graph
oh and one more tip - instead of taking random K's you could just do the: (2*h+1)*180\Fp-Fz when h = Fp-Fw-1 the way you do it is you start from zero and work your way up to the value of -> Fp-Fw-1 ich time you put the results in the equation
Thanks for clearing that up, great video. Although I think at 0:48 is wrong to assume that the open loop T.F is done by only taking the top line, as this is only valid in unity feedback systems where H(s) = 1, when H(s) is not equal to 1, Open loop T.F is equal to G(s) * H(s)
Thank you so much ma'am You literally solved this problem and made it really easy to understand Other TH-camrs just wasted my time Thank you again ❤️❤️
I would have gotten an A in my ECE 460 class (Control Systems) if this lady was my professor. The one I had was a complete JOKE as are most university professors.
16min video summed up what my professor was trying to explain in a 2hr lecture... Thank you so much
Literally the same man. I have a 72 page document on this from my prof and I understand in 16 minutes
love this
Yeah I am wondering why does that happen myself. Your teacher with a PHD has been drilling some knowledge into you but you discover you are learning better from a youtuber.
I thought it was a third world issue, but turns out it's global.
فضحتنا يا هشام
Why can't everybody on youtube make clear, concise, straight to the point videos like this one. 5 star rating, you are the bomb!!! lol
you are right!
This is, by far, the best video I've seen on root locus. The explanation was short, concise, the formulas and steps easy to follow.
This is exactly what I expect from a teacher, being direct and unbelievably precise! Thank you very much, teacher!
Thanks for the detailed tutorial.
For the people who find it hard to calculate break away point, just calculate characteristic equation 1+G(s)H(s) = 0, then find the equation in terms of s and with k on RHS. Now differentiate with respect to s or dK/dS and equate it to zero. From this you can find the solutions for s, which are break away and break in points.
i'm literally going to cry, this was so helpful. my professor's 70 slides cannot compare to this 15 min vid.
lol my professor's slides are triple that
@10:52 woah I'm mind blown by that equation for solving the break-in/break-away points. The method taught to us in class is differentiating the equation K = -1/GH and setting it to zero. It's naturally a bit tedious because the quotient rule for differentiation would have to be applied, but it yields the polynomial that's solvable through a hand calculator. I tried solving the equation here using shift-solve in the calculator and it's not able to get -3.0864.
That being said, still a very helpful thing to know! I'm curious now how that is derived for solving the points :)
Im no stranger to TH-cam math videos and this by far is one of the best I've seen. Thank you!
I can't believe my eyes. How come a human can make such a great video. I am literally shocked. Thanks a lot Mam.
The best Root Locus video. The 2 hours as discussed with my professor was to difficult to understand while with this clip, it is clear and concise.
Why didnt i found this video before my final exam. Thank you so much
Mine is next week. Glad I found it before 😇
@@ReussirSonProjetEtudesAuCanada good for you i still passed it but with a C.
your videos are genuinely so good
The steps are so clear and helpful! Very efficient. Thank you!
Your voice made me concentrate the whole 16 min video which my professor tried explaining throughout 3 sessions of 2 hour lectures each. Thank you so much!
Your voice just literally made me understand this topic
about the angles its a stated thing - if Fp-Fz = 2 its gonna be 90, -90 if it's three then 60,-60, and 180 and if it's 4 then 45, -45 something I didn't remember the point is that - in RL you need an identical asymptote that will to in the other direction in the same angle from the same point on the Real axis (hope it helped)
oh and thank you really helped me to understand how to draw the RL graph
oh and one more tip - instead of taking random K's you could just do the:
(2*h+1)*180\Fp-Fz when h = Fp-Fw-1 the way you do it is you start from zero and work your way up to the value of -> Fp-Fw-1 ich time you put the results in the equation
Thank you from Canada. Amazing work! Super clear, concise, and logical. You’re the best!
Thanks for clearing that up, great video.
Although I think at 0:48 is wrong to assume that the open loop T.F is done by only taking the top line, as this is only valid in unity feedback systems where H(s) = 1, when H(s) is not equal to 1, Open loop T.F is equal to G(s) * H(s)
thinking the same thing
This is the cutest voice I have ever heard !!
Super helpful! Thanks, girl!
Bless You
I've nothing to say other than this is one of the most helpful videos I've ever come across
You saved my life! I've never watched a control systems lecture so objective, thank you!
This was so clear and easy to understand!! Thank you so much!
Too much helpful about understanding root locus , thanks a lot !!
Absolutley amazing video! Can't get over how clear it is
Really too helpful for me
Really solved all my doubts I was having earlier
Thank you for making this video
You are simply amazing !
Love your hand writing, looks really cool! xD
first time a video deserves 0 dislike. great video thank you so much
Nice video on root locus
Thank you for sharing. Greetings from Panama 🇵🇦
Thank you very much. the Best video about the Root Locus. ❤🔥
Thank you so much ma'am
You literally solved this problem and made it really easy to understand
Other TH-camrs just wasted my time
Thank you again ❤️❤️
you are the best teacher,you deserve a bell
Ledgends open this video 10 min before end sem ☠️☠️
Fantastic video, really clear and concise. Thank you so much!
you just 2 weeks into a nice 16 minute session. Thank you
Thank you! Straight and direct to the point with a nice simple example to actually help understand what's happening👌😁
Thank you so much, you gave me confidence in solving these problems now :)
Wow what a precise and clear lecture ❤
Thanks a lot great sense of humor mam !!
Woow.you made it too easy😊
I can't believe a girl is teaching me
you're a life saver, thank you for explaining this >.
Super explanation
thank you so much . this is quite simplified, keep up the good work
Awesome tutorial, thanks!
best shit ive seen in a while. Great job! :D
can you tell me how to draw root locus when the zeros or poles are in the img axis?
These are great, thank you very much!
Thank you so much..Amazing video, simple yet easy to understand and to the point.
i love your voice the way you speak is fabulous.And you are so intelligent lol
Lovely
Thank you so much. your worth much more then 1000 views.
How do you do your video like that? Like what do you use to write on the background, and how do you record?
Thank you so much! This was very helpful as I prepare for my exam!
Thanku for very nice explain 👌
how to find " the range of gain for which the system is stable"?
Great video thank you
Great work, i was confused with asymptotes
I have a better understanding just after watching this video, please explain how the break away/break in is done in MATLAB .
omg she is adorable. thanks a lot
Is there any video on Bode plot?
Actually my prof took a week , but I didn't understand what he wanted to teach..... Love you from BIHAR
You just saved my career
You are great 👍 thanks for this
This is the shit, you did a great job on this. Teachers cant teach nearly as well as you did
Tyvm,even I’m not an English native speaker,I still understand 90%what ur saying ,ty
Thank u so much ma'am it helped me alot u have explained everything so crystal clearly thanks alot
❤️❤️ Paoools
thanks... From Iraq 🌹🌺
good job ryder
Thanks thanks a lot. This was amazing 👏
Merci à toi ! très bonne explication
this saved my damn life
This is really good explanation.thank you very much
thank you so much this video its perfect for me
I would have gotten an A in my ECE 460 class (Control Systems) if this lady was my professor. The one I had was a complete JOKE as are most university professors.
Thank you so much :) Saved my life !!!
hi, at 8:15 i do not understand what you mean by repeating angles. could you explain?
Excellent !
One question: What if we had (s+6) / ((s+6)(s+1)(s+2)), then we have zero=-6 and pole=-6 ? What in that case?
LOL i owe my degree to youtube ... finally something that helps !! i was about to go crazyyyy
ありがとうございます！！
thank youuu
Thanks a lot! You are helping now a student in 2024😂
thank you!!!
Break away points are easier to find by taking the derivative of G.
Wouldnt you only join them starting at ODD poles/zeros
Thanks that was so easy
Great video.
Can you please ... explain how find break away point for another appropriate example
I think there are other examples in the playlist.
@@theryderproject5053 tq for respond
Love
Thank you very much 💖, this video really helped.
This is the best!!
Thanks so much.
Explanation was perfect
thanks mam love from INDIA
why my teacher draws from negative axis to the first pole at right? and how do you draw the line between -2 to -4, why not -4 to -6
Really helped a lot 🙏🙏... Thank you so much. My college teachers are so 💀💀☠️☠️