I did the same thing. The expression you mentioned equals e ^ (ln(2)*(4/3)), which equals (e^ln(2)) ^ (4/3). Then we use e^ln(x) = x with x = 2 to get the answer from the video 2^(4/3).
Greetings. Yes we can. The value for X that satisfies the expression is 2(2)^1/3. The given expression can be written as X^3/4=2 by dividing the entire expression by 3 and transposing the known quantity to the right hand side. Now, moving on, we will raise each side of the expression to the 4th power to get (X^3/4)^4=2^4, and X^3=16, from which it is determined that X =2(2)^1/3. Lovely.
Instead of using the letters "m" and "n" for the numerator and denominator, why not use the letters "d" for denominator and "n" for numerator? Makes sense?
Not a math gal, but ended up tutoring beginning algebra at one point. My best advice: 1. BREATHE! (Not this 😳. This 🌬️.) 2. Use examples from the text lesson. (The book is trying to guide your learning.) 3. Note every step. (If it goes away one can retrace steps.)
Why do you unnecessarily make stuff hard to follow? All you need to do is x^(3/4) = 2 (x^3)^1/4 = (2^4)^(1/4) Using the power rule x^3 = 2^4 x = 2^(4/3)
Unless x is supposed to be real, there are two other complex number solutions and this video doesn't cover that at all while going unnecessarily long to get the obvious / trivial real value solution.
I can raise 2 to the 4th power then take the cube root. Or I can take the cube root, then raise it to the 4th power. And get the same answer! I didn't know that.
I kept getting 2 (1/4) - 6 = 0 which doesn't add up, so I'm still unsure how to correctly get it to = 0 😅 I was taught to make whole numbers fractions to handle fractions, ie 3 becomes 3/1, so the result is 9/4. Then again, I barely passed math haha
Good lesson, but is evident that all that manipulation is not necessary. Maths is about making difficult things understandable in an easy way, not the other way around. It seems a show up of manipulation, thing is it's not necessary here. A pupil should be shown immediately to see that x is 2, then briefly explain why, not the other way round. Although I compliment you for your manipulation skills I cannot do for the way you put it unnecessarily.
@@maxhenderson1890 With this part I agree: "Firstly, you could notice that ³√16 = 16⅓ = (2⁴)⅓ = 2^(4/3). But I don't see how "2^(4/3) = 2 * 2⅓", neither how ³√(2*2) * ³√(2*2) = ³√2 * ³√2 * ³√2 * ³√2 = 2 * ³√2. Perhaps my lack of understanding.
2nd grade students are barely learning the concept of multiplication. They have no idea what exponents are -- much less, how to deal with fractional exponents (all caps notwithstanding).
@Astrobrant2 Apologize for the caps. I hadn't noticed my keyboard was set on capitals when I posted. My bad. And you're right. A Second grade student would NOT be expected to know this level of math. Don't know what I was thinking. (Caps intentional this time ).
![[(3 - 11) + 2(5 - 6)] divided by (8 - 10) = ? Can You Do BASIC MATH?](http://i.ytimg.com/vi/4-U2GvfJB8s/mqdefault.jpg)
![[(3 – 11) + 2(5 – 6)] divided by (8 – 10) = ? Can You Do BASIC MATH?](/img/tr.png)
"Many will get wrong", "Many don't know where to start". Nice encouragement you provided there John!
If you did in fact get it wrong, then you won't feel so alone. And if you got it right, you can feel a little bit special.
Love all these people saying the did it in 30s…It’s not FOR YOU. It’s for people learning it for the first time and it is remarkably well explained.🎉
I think the point is, a lot of this stuff isn't being taught anymore. As is the case for a lot of other things not being taught anymire...
I got e^(4*ln(2)/3). What do I do from here and what log properties allow me to make those maneuvers?
I did the same thing. The expression you mentioned equals e ^ (ln(2)*(4/3)), which equals (e^ln(2)) ^ (4/3). Then we use e^ln(x) = x with x = 2 to get the answer from the video 2^(4/3).
Greetings. Yes we can. The value for X that satisfies the expression is
2(2)^1/3. The given expression can be written as X^3/4=2 by dividing the entire expression by 3 and transposing the known quantity to the right hand side. Now, moving on, we will raise each side of the expression to the 4th power to get
(X^3/4)^4=2^4, and X^3=16, from which it is determined that X =2(2)^1/3. Lovely.
hi can you say that in English please?
This might be completely wrong but ..
3X^3/4 - 6 = 0 means that
3X^3/4 = 6 and X^3/4 = 2 and X = 2^4/3
Hi. What software are you using, please??
Cube root 2^4 = cube root of 16.
No bone today. Excellent lesson. Thanks Boss.
Instead of using the letters "m" and "n" for the numerator and denominator, why not use the letters "d" for denominator and "n" for numerator? Makes sense?
Another fun one in my head, mostly thanks to your refresher in a previous video. Keep up the good work!
I'm glad I'm not at school anymore
Took a different approach via log: logx= 4/3log2, hence x= 2,52...
Not a math gal, but ended up tutoring beginning algebra at one point. My best advice:
1. BREATHE! (Not this 😳. This 🌬️.)
2. Use examples from the text lesson. (The book is trying to guide your learning.)
3. Note every step. (If it goes away one can retrace steps.)
Why do you unnecessarily make stuff hard to follow?
All you need to do is
x^(3/4) = 2
(x^3)^1/4 = (2^4)^(1/4)
Using the power rule
x^3 = 2^4
x = 2^(4/3)
Never mind I get it. Thanks.
Why not show that 2^4/3 equals 2 times sqrt 2?
2(2)^1/3
fun. thanks for the lesson. i knew the exp was inversed, just couldn't remember the whole procedure.
Cube root 16?
3(x^3/4)=6
x^3/4=2
(x^3)^4=2^4
x^3=16
x=16^1/3
x=8^1/3 X 2^1/3
x=2X2^1/3 and/or 2^4/3
Thank you
Take both sides to log base 2 and it’s a no brainer.
3/4log3x = log 6 => log3x = log 6 ^ (4/3) => x = (log6^(4/3))/3
Lot easier just to see that if 3x^3/4 =6 then.... x^3/4 must = 2 then 4th power of both side equation to see the final answer..:)
Solved in my head. It's been a while but I remembered exponent rules.
2>4/3 but i dont know how to solve it from there without a calculator
He’s not talking too much!!! I stand corrected!!
to be picky: as an example, you said "x^3=8, x=2", but that has an additional two complex roots.
Unless x is supposed to be real, there are two other complex number solutions and this video doesn't cover that at all while going unnecessarily long to get the obvious / trivial real value solution.
x^3/4=2
x=2^4/3
Thanks Mr. TH-cam Math man!
I can raise 2 to the 4th power then take the cube root.
Or I can take the cube root, then raise it to the 4th power.
And get the same answer!
I didn't know that.
3x^(3/4) - 6 = 0
3x^(3/4) = 6
x^(3/4) = 2
x^(3/4)^(4/3) = 2^(4/3)
3 __ 3 ____
x = 2^(4/3) = ✔️16 =✔️8•2
3 _
x = 2✔️2 ≈ 2.51984
I kept getting 2 (1/4) - 6 = 0 which doesn't add up, so I'm still unsure how to correctly get it to = 0 😅
I was taught to make whole numbers fractions to handle fractions, ie 3 becomes 3/1, so the result is 9/4.
Then again, I barely passed math haha
Cube root of 16
Good lesson, but is evident that all that manipulation is not necessary. Maths is about making difficult things understandable in an easy way, not the other way around. It seems a show up of manipulation, thing is it's not necessary here. A pupil should be shown immediately to see that x is 2, then briefly explain why, not the other way round. Although I compliment you for your manipulation skills I cannot do for the way you put it unnecessarily.
Wut? x does not equal 2. x = cube root of 16 = 2^(4/3). If you think x = 2, your reasoning is way off.
Wasnt it friday the movie when craig whistled
Dude, if it takes longer than 8 minutes to explain, you can safely assume I aint ever going to get it.
How you know that. Maybe you were their maths teacher
2.6 comes very close
seems like the cube root of 16 is a better answer
2^(4÷3)
I got 2*cubert(2). 😅
I assume you mean 2 * ³√2. This is also correct. If x = 2^(4/3), then we can evaluate (2^4)^(1/3) = 16^(1/3) = 2 * ³√2
@@maxhenderson1890 I know it is, which is why I added the laughing smiley. 😃
@@maxhenderson1890 How can 2 times the cube root of 2 be the same as the cube root of 16? I don't see it.
@@Kleermaker1000Firstly, you could notice that ³√16 = 16⅓ = (2⁴)⅓ = 2^(4/3) = 2 * 2⅓ = 2 * ³√2
Similarly you can solve by doing ³√16 = ³√(4*4) = ³√4 * ³√4 = ³√(2*2) * ³√(2*2) = ³√2 * ³√2 * ³√2 * ³√2 = 2 * ³√2
@@maxhenderson1890 With this part I agree: "Firstly, you could notice that ³√16 = 16⅓ = (2⁴)⅓ = 2^(4/3). But I don't see how "2^(4/3) = 2 * 2⅓", neither how ³√(2*2) * ³√(2*2) = ³√2 * ³√2 * ³√2 * ³√2 = 2 * ³√2. Perhaps my lack of understanding.
There we go again with the idea that Mahan will get this wrong. It is such a tiring opening.
Yet true! Everyone named Mahan will get this wrong!
I think I did that? Still got 2 cube root 2. So I think good
X=2^(4/3)… so what?
John suffers from verbal diarrhea VERBAL DIARRHEA, VERBAL DIARRHEA, VERBAL DIARRHEA 😢😢😢😢😢😢😢😢😢😢THE
x³/⁴ = 2
x = 2⁴/³
Solved this in 10 seconds in my head. Really doesn't need a 20 minute video.
Dont invade peoples integers
A small percentage of youse will get this right.
Qitth westt chemrew yantex we need more and more anmore x yanten righthn allah bmayshr beshta ylkefat aza
Huh?
SORRY, BUT A GRADE 2 STUDENT COULD DO THIS IN UNDER 20 SECONDS.
2nd grade students are barely learning the concept of multiplication. They have no idea what exponents are -- much less, how to deal with fractional exponents (all caps notwithstanding).
@Astrobrant2 Apologize for the caps. I hadn't noticed my keyboard was set on capitals when I posted. My bad.
And you're right. A Second grade student would NOT be expected to know this level of math. Don't know what I was thinking. (Caps intentional this time ).
X^(3/4)=2
X=4
Not even close. How do you get from line 1 (right) to line 2 (false)?!?
Of course we have to raise both sides to ^(4/3) to get the left side exponent to 1, so 2^(4/3)
I'm getting 2*³√2 ≈ 2.5198421