Whatever power that we are getting in CCR is motor power it means motor output is equal to fan shaft power as per fan efficiency -Fan Mechanical power/Motor(kW)*motor efficiency Fan shaft power -motor efficiency * motor power In ideal conditions fanshaft power is equals to mechanical power in which fan efficiency equals to 100 percentage. In Fan law it is the same power..
@@er.prabinakumarpatanayak9814 first you have to percentage of false air on the basis of it you convert into Nm3/hr. 4,00,000 Nm3/hr then 10 percent false air-40,000 Nm3/hr.
बहुत बढ़िया 👏👏
Very very informative.
Keep it
Thanks sir
Kindly make video on pyro optimisation
Presently I am busy once I get the time then I will upload 3-4 new videos...
Sir tromp curve explain kar dejiye
Ok will try to take on the next classes..
Sir shaft power is different from that power which is mentioned in fan law?
Whatever power that we are getting in CCR is motor power it means motor output is equal to fan shaft power as per fan efficiency -Fan Mechanical power/Motor(kW)*motor efficiency
Fan shaft power -motor efficiency * motor power
In ideal conditions fanshaft power is equals to mechanical power in which fan efficiency equals to 100 percentage.
In Fan law it is the same power..
@@Asnaniclasses_Cement thank you sir
Kindly explain how M1 & M2 are calculated by doing mass balance n energy balance. As we have two variables M1 & M2 in equation
Sir, Can we calculate the False air in NM3/Hr
@@er.prabinakumarpatanayak9814 first you have to percentage of false air on the basis of it you convert into Nm3/hr.
4,00,000 Nm3/hr then 10 percent false air-40,000 Nm3/hr.